标签: simplehttpserver

我总是用$ python -m SimpleHTTPServer快速的本地静态网页测试,它的伟大工程,index.htm或index.html为索引文件.

但是我需要使用default.htm或default.html正在进行我正在进行的项目.有人可以帮忙写一个简单的脚本吗？

我在网上找到了以下示例,我希望它可以帮助我们开始一点点.

import sys, SimpleHTTPServer, BaseHTTPServer
from SimpleHTTPServer import SimpleHTTPRequestHandler

SimpleHTTPRequestHandler.protocol_version = "HTTP/1.0"

httpd = BaseHTTPServer.HTTPServer(('127.0.0.1', 8000), SimpleHTTPRequestHandler)

sa = httpd.socket.getsockname()

print "Serving HTTP on", sa[0], sa[1], "..."

httpd.serve_forever()

我有以下代码:

import os
from ghost import Ghost
import urlparse, urllib

import SimpleHTTPServer
import SocketServer

import sys, traceback

from threading import Thread, Event
from time import sleep

please_die = Event() # this is my enemy

httpd = None
PORT = 8001
address = 'http://localhost:'+str(PORT)+'/'
search_dir = './category'

def main():
    """
      basic run script routine, 
      FIXME: is supossed to exits gracefully
    """
    thread = Thread(target = simpleServe)
    try:
      thread.start()
      run()
    except KeyboardInterrupt:
      print "Shutdown requested"
    except Exception:
      traceback.print_exc(file=sys.stdout)

    shutdown()
    sys.exit(0)

def shutdown(): …

我正在python -m SimpleHTTPServer 8888从目录运行my_server,我想访问index.html包含读取的javascript命令my_file.csv的文件,但该文件不在my_server其子文件夹或其中一个子文件夹中.

path/to/my_server $ ln -s /some_path/to/my_file.csv symbolic_link_to_my_file.csv
path/to/my_server $ python -m SimpleHTTPServer 8888

如果我创建符号链接里面my_server指向my_file.csv,然后访问它像这样:

http://localhost:8888/my_server/index.html?file=symbolic_link_to_my_file.csv

有什么办法我可以用javascript里面的这个符号链接index.html来阅读my_file.csv？

<script>
    //read URL params
    ...
    d3.csv(file, ...)
</script>

所以我通过这样做在端口 8000 上的 Ubuntu 机器上创建了一个简单的服务器：

python -m SimpleHTTPServer

10.127.11.18 - - [14/Aug/2014 15:11:55] "GET / HTTP/1.1" 200 -
10.127.11.18 - - [14/Aug/2014 15:11:55] code 404, message File not found
10.127.11.18 - - [14/Aug/2014 15:11:55] "GET /favicon.ico HTTP/1.1" 404 -
10.127.11.18 - - [14/Aug/2014 15:12:02] "GET /crazysean/ HTTP/1.1" 200 -
10.127.11.18 - - [14/Aug/2014 15:12:37] "GET /crazysean/ HTTP/1.1" 200 -
10.127.11.18 - - [14/Aug/2014 15:12:52] "GET /crazysean/?url=www.google.com&x=200&y=400 HTTP/1.1" 301 -
10.127.11.18 - - [14/Aug/2014 15:12:52] "GET /crazysean/?url=www.google.com&x=200&y=400/ HTTP/1.1" 200 -
10.127.11.18 …

我想用我的Java HttpServer进行一些SQL查询,但似乎HttpServer无法识别我提交到浏览器的链接中的特殊字符:

[1]: http://localhost:8001/test?query=SELECT * WHERE{ ?s rdf:type ?o. }

我总是收到这样的回复:

400 Bad Request
URISyntaxException thrown

这是我的服务器的代码:

public class SimpleHttpServer 
{

public static void main(String[] args) throws Exception 
{

        dir = args[0];
        HttpServer server = HttpServer.create(new InetSocketAddress(8001), 0);
        server.createContext("/test", new MyHandler());
        server.setExecutor(null);
        server.start();
    }

    static class MyHandler implements HttpHandler {
        public void handle(HttpExchange t) throws IOException {
            String response ;
            System.out.println(t.getRequestURI().getQuery().toString().replaceAll("query=",   ""));
            response =   ExecuteHttpQuery.getInstance().httpQuery(t.getRequestURI().getQuery().toString().replaceAll("query=", "").toString(), dir) + "\n";
            t.sendResponseHeaders(200, response.length());
            OutputStream os = t.getResponseBody();
            os.write(response.getBytes());
            os.close();
        }
    }
} …