标签: shapedrawable

我需要通过扩展ShapeDrawable以编程方式创建带圆角的边框.我需要一个带圆角的黑色边框,外面的像素是白色,内部像素是透明的.我目前的代码存在多个问题,其中的问题是它不会创建一个与边框厚度相同的平滑角,并且边框的外部像素是透明的而不是白色.

这是我目前得到的角落的图片

这是我在构造函数中为'fill'传递Color.TRANSPARENT的代码:

public class CustomShape extends ShapeDrawable {
 private final Paint fillpaint, strokepaint;
public CustomShape(int fill, int strokeWidth,int radius) {

    super(new RoundRectShape(new float[] { radius, radius, radius, radius, radius, radius, radius, radius }, null, null));
    fillpaint = new Paint(this.getPaint());
    fillpaint.setColor(fill);
    strokepaint = new Paint(fillpaint);
    strokepaint.setStyle(Paint.Style.STROKE);
    strokepaint.setStrokeWidth(strokeWidth);
    strokepaint.setColor(Color.BLACK);
}



@Override
protected void onDraw(Shape shape, Canvas canvas, Paint paint) {
    shape.draw(canvas, fillpaint);
    shape.draw(canvas, strokepaint);
}

}

我想为我的Android按钮制作一个drawable,定义为drawable.我发现我可以通过使用一个矩形来设置所有边框,但是当我想要三面时,我有点卡住了.我希望例如打开顶部或底部.

谁能告诉我怎么做？

我定义了以下drawable my_background_drawable.xml:

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
    <item>
        <shape android:gravity="center"
            android:shape="rectangle">
            <solid android:color="@color/color_stateful" />
        </shape>
    </item>

    <item android:drawable="@drawable/selector_png_drawable" />
</layer-list>

我还定义了以下颜色状态列表资源color_stateful.xml:

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android" >
    <item android:state_pressed="true" android:color="#FF00ff00"/>
    <item android:color="#FFff0000"/>
</selector>

当我将my_background_drawable某个视图设置为某个视图的背景时,我无法观察到color_stateful.xml为我的形状定义的颜色的任何变化,而视图状态实际上已更改(selector_png_drawable.xml是指示符).

但是,当我通过my_background_drawable.xml以下方式修改我时,一切都很好:

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<!-- This doesn't work
    <item>
        <shape android:gravity="center"
            android:shape="rectangle">
            <solid android:color="@color/color_stateful" />
        </shape>
    </item>
-->
    <item>
        <selector xmlns:android="http://schemas.android.com/apk/res/android">
            <item android:state_pressed="true">
                <shape android:gravity="center"
                    android:shape="rectangle">
                    <solid android:color="#FF00ff00" />
                </shape>
            </item> …

我正在尝试为我的按钮创建一个具有不同状态的可绘制形状.所以我写了这个:

<selector xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:state_pressed="true" android:color="@android:color/black" >
    <shape android:shape="rectangle" >
        <solid android:color="@color/NEGATIVE_pressed" />
        <stroke
            android:width="1dp"
            android:color="@color/ORANGE" />
        <corners android:radius="4dp" />
    </shape>
</item>
<item android:state_focused="true" android:color="@android:color/black" >
    <shape android:shape="rectangle" >
        <solid android:color="@color/NEGATIVE_focused" />
        <stroke
            android:width="1dp"
            android:color="@color/ORANGE" />
        <corners android:radius="4dp" />
    </shape>
</item>
<item android:color="@android:color/black" >
    <shape android:shape="rectangle" >
        <solid android:color="@color/NEGATIVE" />
        <stroke
            android:width="1dp"
            android:color="@color/NEGATIVE" />
        <corners android:radius="4dp" />
    </shape>
</item>
</selector>

然后在我的按钮中我用它作为 android:background="@drawable/btn_negative_selector"

但是,我想绘制一个底部边框到那个形状,就像3 dp和不同颜色,但我无法弄清楚如何做到这一点.我试过搜索,但找不到适合选择器的东西.有什么建议吗？

我正在尝试为我的textview制作平行四边形背景,但它没有正确显示...它显示以下输出

<layer-list  >
    <item>
        <rotate
            android:fromDegrees="10"
            android:toDegrees="10"
            android:pivotX="-40%"
            android:pivotY="87%" >
            <shape
                android:shape="rectangle" >
                <stroke android:color="#000000" android:width="10dp"/>

            </shape>

        </rotate>

    </item>
</layer-list>

我需要像这样的输出........

尝试为Android Ring Shape设置动画,以产生与所示图像序列类似的效果.

我找到了Shape Drawable类型的戒指.

<shape
xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="ring"
android:innerRadius="75dp"
android:thickness="25dp"
android:useLevel="false">

随着ArcShape(startAngle,sweepAngle)方法.

ShapeDrawable shape = new ShapeDrawable(new ArcShape(0, 360));     
shape.setIntrinsicHeight(100);
shape.setIntrinsicWidth(100);
shape.getPaint().setColor(Color.BLACK);

然而,问题在于无法找到可绘制形状的扫掠角度属性或为ArcShape创建内半径的能力.

我试图制作一个流畅的动画.

我正在使用Action Bar Compat,因此带导航抽屉的操作栏向下兼容到API级别9,我想更改操作栏的背景.

我复制了Android开发者的代码:

<?xml version="1.0" encoding="utf-8"?>
<resources>
<!-- the theme applied to the application or activity -->
<style name="CustomActionBarTheme"
       parent="@style/Theme.AppCompat.Light.DarkActionBar">
    <item name="android:actionBarStyle">@style/MyActionBar</item>

    <!-- Support library compatibility -->
    <item name="actionBarStyle">@style/MyActionBar</item>
</style>

<!-- ActionBar styles -->
<style name="MyActionBar"
       parent="@style/Widget.AppCompat.Light.ActionBar.Solid.Inverse">
    <item name="android:background">@drawable/actionbar_background</item>

    <!-- Support library compatibility -->
    <item name="background">@drawable/actionbar_background</item>
</style>
</resources>

这就是问题所在.

当我将图像绘制或颜色作为背景时,它工作正常.但是我想将背景定义为渐变形状,所以我actionbar_background看起来像:

<?xml version="1.0" encoding="utf-8"?>
<shape
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="line">
<gradient
        android:startColor="@color/ac_bg_start"
        android:endColor="@color/ac_bg_end"
        android:type="linear"/>
<size
        android:width="1dp"
        android:height="48dp"/>
</shape>

我希望它以水平方式重复,但即使这样也会导致错误,实际上是非常有趣的错误.当我尝试运行应用程序时,测试设备甚至模拟器都会重新启动.DeadObjectException在重新启动之前我能够捕获.

背景画如何看起来像？

我的项目要求在运行时动态绘制一个圆.所以为了这个目的,我使用ShapeDrawable以编程方式创建圆,但不幸的是我在CircleShape的ShapeDrawable中找不到任何类或方法,而只是我找到了OvalShape().亲切地请帮我通过ShapeDrawable绘制一个圆圈,只需通过圆的直径或半径即可.提前致谢.任何类型的自定义对我来说都很有用,可以修复我的解决方案.

我用于ShapeDrawable的代码是

public static ShapeDrawable drawCircle (Context context, int width, int height, int color) {

        //////Drawing oval & Circle programmatically /////////////

        ShapeDrawable oval = new ShapeDrawable (new OvalShape ());
        oval.setIntrinsicHeight (height);
        oval.setIntrinsicWidth (width);
        oval.getPaint ().setColor (color);
        return oval;
    }

使用的代码 MainActivity.java

if(Build.VERSION.SDK_INT >= 16) {
            txtCount.setBackground (Util.drawCircle (MainActivity.this, 50, 50, getResources ().getColor (R.color.yellow)));
            txtHotelCount.setText ("20");
        }else{
            txtCount.setBackgroundDrawable (Util.drawCircle (MainActivity.this, 50, 50, getResources ().getColor (R.color.yellow)));
            txtHotelCount.setText ("20");

        }

在我的项目中用于TextView的 xml txtCount是

<LinearLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:padding="10dp"
        android:background="@color/white">

        <TextView …

我怎么能放弃fromFegrees,toDegrees和android:color="#000000"编程？

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
    <item >


        <rotate 
            android:fromDegrees="45"
            android:toDegrees="45"
            android:pivotX="-40%"
            android:pivotY="87%" >

            <shape 
            android:shape="rectangle"  >
            <stroke android:color="@android:color/transparent" android:width="10dp"/>
            <solid  
                android:color="#000000"  />
        </shape>

        </rotate>
    </item>
</layer-list>

我在视图的背景中使用此xml.

我必须以编程方式创建三角形.所以需要以编程方式创建RotationDrawable.

我在LinearLayouts背景中使用ShapeDrawable.形状由cod制作,因为我需要动态地为它们分配颜色,具体取决于条件.这是我的自定义形状

public class CustomShapeDrawable extends ShapeDrawable {
    private final Paint fillpaint, strokepaint, linePaint = new Paint();
    private int strokeWidth = 3;
    private final boolean disableBottomBorder;

    public CustomShapeDrawable(Shape s, int fill, int stroke, int strokewidth, boolean disablebottomborder) {
        super(s);
        fillpaint = new Paint(this.getPaint());
        fillpaint.setColor(fill);
        strokepaint = new Paint(fillpaint);
        strokepaint.setStyle(Paint.Style.STROKE);
        strokepaint.setStrokeWidth(strokewidth);
        strokepaint.setColor(stroke);
        linePaint.setStyle(Paint.Style.STROKE);
        linePaint.setStrokeWidth(strokewidth + 1);
        linePaint.setColor(fill);
        strokeWidth = strokewidth;
        disableBottomBorder = disablebottomborder;

    }

    public CustomShapeDrawable(Shape s, int fill, int stroke, boolean disablebottomborder) {
        super(s);
        fillpaint = new Paint(this.getPaint());
        fillpaint.setColor(fill);
        strokepaint = …