标签: serializable

我有两个maven项目,项目A内容一些可序列化的模型对象,项目B是GWT项目.现在我想使用项目A中的一些对象来进行项目B中客户端和服务器之间的RPC调用.

所以这就是我所做的:

GWT项目B xml:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE module PUBLIC "-//Google Inc.//DTD Google Web Toolkit 2.4.0//EN" "http://google-web-toolkit.googlecode.com/svn/tags/2.4.0/distro-source/core/src/gwt-module.dtd">
<module rename-to='Index'>
<inherits name='com.google.gwt.user.User' />
<inherits name='com.projectA.Models' />

<inherits name='com.google.gwt.user.theme.standard.Standard' />
<entry-point class='com.projectB.client.Index' />

<source path='client' />
<source path='shared' />

</module>

Java对象项目A xml:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE module PUBLIC "-//Google Inc.//DTD Google Web Toolkit 2.4.0//EN" "http://google-web-toolkit.googlecode.com/svn/tags/2.4.0/distro-source/core/src/gwt-module.dtd">
<module>
<inherits name="com.google.gwt.user.User"/>
<source path="./" />
</module>

我仍然得到"没有源代码可用于类型com.projectA.Object;你忘了继承一个必需的模块吗？" 消息=(

(POM依赖设置!)

您好我试图将图像位置保存到sreen到内部存储但是我得到一个NotSerializableException.我去搜索并发现问题是Bitmap不是为了在这个链接上 序列化问题序列化Drawable我从来没有真正理解他如何修复问题抛出这个例子.如果有人可以解释他如何修复他的NotSerializableException并帮助我与我的相处,我将不胜感激

这是我的Elememt课程

public class Element extends main implements Serializable{
private int mX;
private int mY;
int location2 ;
Matrix elementlocation;
private Bitmap mBitmap;
Canvas canvas2;

public Element(Resources res, int x, int y) {
  location2 =item3;
    mBitmap = BitmapFactory.decodeResource(res, location2);
    mX = x - mBitmap.getWidth() / 2;
    mY = y - mBitmap.getHeight() / 2;
  }

public Element(){

}
public void doDraw2(Canvas canvas) {
    elementlocation=new Matrix();
    elementlocation.postTranslate(mX,mY);
    canvas2=canvas;
    canvas2.drawBitmap(mBitmap, elementlocation,null);
    }
public void setelementlocation(float num1,float num2){
   elementlocation=new Matrix();
   elementlocation.postTranslate(num1,num2);
 } …

我正在写一个班级来跟踪锦标赛的比赛数据.我想将这个类存储到一个文件中,所以我正在使用ObjectInputStream.我写的类实现了Serializable.我得到了一个EOFException,而且我在SO和其他地方找到的解决方案都没有解决这个问题.

我的文件编写者是:

public void writeToFile(String path) {
    File f = new File(path);
    if(f.exists()) f.delete();

    try {
        OutputStream fileOut = new FileOutputStream(path);
        OutputStream bufferOut = new BufferedOutputStream(fileOut);
        ObjectOutput output = new ObjectOutputStream(bufferOut);

        output.writeObject(this);
    } catch(IOException e) {}
}

我的文件阅读器是:

public static DivisionDataFTC readFromFile(String path) {
    try {
        InputStream fileIn = new FileInputStream(path);
        InputStream bufferIn = new BufferedInputStream(fileIn);
        ObjectInput input = new ObjectInputStream(bufferIn);

        System.out.println(input.read());
    } catch(Exception e) {
        System.out.println(path);
        e.printStackTrace();
    }

    if(1==1) throw new Error("Could not read DivisionDataFTC …

我收到此错误:

                FATAL EXCEPTION: main
        java.lang.RuntimeException: Parcelable encountered IOException writing serializable object (name = game.Level)
        at android.os.Parcel.writeSerializable(Parcel.java)
        at android.os.Parcel.writeValue(Parcel.java)
        at android.os.Parcel.writeMapInternal(Parcel.java)
        at android.os.Bundle.writeToParcel(Bundle.java)
        at android.os.Parcel.writeBundle(Parcel.java)
        at android.content.Intent.writeToParcel(Intent.java)
        at android.app.ActivityManagerProxy.startActivity(ActivityManagerNative.java)
        at android.app.Instrumentation.execStartActivity(Instrumentation.java)
        at android.app.Activity.startActivityForResult(Activity.java)
        at android.app.Activity.startActivityForResult(Activity.java)
        at android.app.Activity.startActivity(Activity.java)
        at android.app.Activity.startActivity(Activity.java)
        at menu.AreaAdapter$1.onClick(AreaAdapter.java:93)
        at android.view.View.performClick(View.java)
        at android.view.View$PerformClick.run(View.java)
        at android.os.Handler.handleCallback(Handler.java)
        at android.os.Handler.dispatchMessage(Handler.java)
        at android.os.Looper.loop(Looper.java)
        at android.app.ActivityThread.main(ActivityThread.java)
        at java.lang.reflect.Method.invokeNative(Native Method)
        at java.lang.reflect.Method.invoke(Method.java:511)
        at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java)
        at com.android.internal.os.ZygoteInit.main(ZygoteInit.java)
        at dalvik.system.NativeStart.main(Native Method)
        Caused by: java.io.NotSerializableException: menu.AreaActivity
        at java.io.ObjectOutputStream.writeNewObject(ObjectOutputStream.java:1364)
        at java.io.ObjectOutputStream.writeObjectInternal(ObjectOutputStream.java:1671)
        at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1517)
        at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1481)
        at java.io.ObjectOutputStream.writeFieldValues(ObjectOutputStream.java:979)
        at java.io.ObjectOutputStream.defaultWriteObject(ObjectOutputStream.java:368) …

我试图用JAXB序列化ArrayList并失败.这是因为elementData被标记为瞬态？

为什么ArrayList实现Serializable Inferface并且它的数据是瞬态的？

我尝试序列化Serializables的ArrayList:

JAXBElement<ArrayList> jaxbElement = new JAXBElement<ArrayList>(new QName(ArrayList.class.getSimpleName()), ArrayList.class, allEntities);
        Marshaller marshaller = jaxbContext.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(jaxbElement, System.out);

如何通过JAXB执行此操作？

我有一个用户定义的类Message,我想在客户端和服务器之间传递它的对象.

Message类如下:

import java.io.Serializable;

public class Message implements Serializable
{
    String CorS;
    int data_id;
    int status_id;
    Integer value;
    boolean withdraw;

    public Message()
    {
        CorS = null;
        data_id = 0;
        status_id = 0;
        value = 0;
        withdraw = false;
    }

    public Message(String CorS, int data_id, int status_id, Integer value)
    {
        this.CorS = CorS;
        this.data_id = data_id;
        this.status_id = status_id;
        this.value = value;
    }

    public Message(boolean withdraw)
    {
        this.withdraw = withdraw;
    }
}

将对象发送到服务器的客户端代码如下:

Socket s = null;
    ObjectInputStream in = null; …

我这次使用的是Serializable Interface.我想将ArrayList从一个活动传递到另一个活动,但它给了我这个错误"无法编组值",代码是,

//发送活动:

    public class LogIn extends Activity implements OnClickListener
    {
    ProgressDialog pd;
    ImageButton logIn,registr;
    EditText userName,Password;
     public static String usrName,passwrd;
     String TAG=LogIn.class.getName();
    @Override
    protected void onCreate(Bundle savedInstanceState)
    {

        super.onCreate(savedInstanceState);
        setContentView(R.layout.login);
        userName=(EditText)findViewById(R.id.logIn_etuserName);
        Password=(EditText)findViewById(R.id.logIn_etpaswrd);
        logIn=(ImageButton)findViewById(R.id.logIn_B_logIn);
        registr=(ImageButton)findViewById(R.id.logIn_B_registration);       
        logIn.setOnClickListener(this);
        registr.setOnClickListener(this);

    }
    @Override
    public void onClick(View v)
    {

        String respns="";
        switch (v.getId())
        {
        case R.id.logIn_B_logIn:

            try 
            {
                usrName=userName.getText().toString();
                passwrd=Password.getText().toString();
                        if(usrName.contentEquals("") && passwrd.contentEquals(""))
                {
                    Toast.makeText(getApplicationContext(), "Enter       userName",Toast.LENGTH_LONG).show();
                }
      //                        else if(passwrd.contentEquals(""))
    //              {
    //                  Toast.makeText(getApplicationContext(), "Enter      password",Toast.LENGTH_LONG).show();
    //              }
                else
                {
                    pd=ProgressDialog.show(LogIn.this, "LogIn", "Logging");
                    new …

我正在使用ObjectOutputStream将我的对象保存到.dat文件.我的问题是,如果我改变我的对象的源代码(例如我添加一个方法(getter))输入流无法加载数据并告诉我一个错误Serializable:有可能解决这个问题吗？.dat如果我更改源代码,我必须每次都生成新文件.

使用此方法:( 不要看对象类型 - 返回值)保存

public void saveToFile(HeaderOfMapTeachStructure hm, String nameOfFile) {
    try (ObjectOutputStream os = new ObjectOutputStream(
            new FileOutputStream(nameOfFile + "." + this.TYPE_OF_FILE))) {
        os.writeObject(hm);
    } catch (IOException e) {
        System.out.println("Error: " + e);
    }
}

加载

public MapStandard loadFromFileMS(String nameOfFile) {
    MapStandard hm = null;
    InputStream inputStreaminputStream
            = getClass().getClassLoader().
            getResourceAsStream("data/" + nameOfFile + ".data");
    try {
        try (ObjectInputStream is = new ObjectInputStream(inputStreaminputStream)) {
            hm = (MapStandard) is.readObject();
        }
    } …

我已经尝试了所有在StackOverflow上发现的该问题的解决方案，但是尽管如此，我还是无法解决。我有一个“ MainObj”对象，该对象实例化了“ Recommendation”对象。当我调用“ recommendationProducts”方法时，总是出现错误。这是该方法的代码：

def recommendationProducts(item: Int): Unit = {

val aMatrix = new DoubleMatrix(Array(1.0, 2.0, 3.0))

def cosineSimilarity(vec1: DoubleMatrix, vec2: DoubleMatrix): Double = {
  vec1.dot(vec2) / (vec1.norm2() * vec2.norm2())
}

val itemFactor = model.productFeatures.lookup(item).head
val itemVector = new DoubleMatrix(itemFactor)

//Here is where I get the error:
val sims = model.productFeatures.map { case (id, factor) =>
  val factorVector = new DoubleMatrix(factor)
  val sim = cosineSimilarity(factorVector, itemVector)
  (id, sim)
}

val sortedSims = sims.top(10)(Ordering.by[(Int, Double), Double] {
  case (id, similarity) => …

我正在使用.NET Framework 4.7开发C＃库。

我想将类ProductionOrderXmlFile转换为XML文件：

[Serializable]
public class Level
{
    [XmlElement("Id")]
    public byte Id { get; set; }
    [XmlElement("Name")]
    public string Name { get; set; }
    [XmlElement("CodeType")]
    public byte CodeType { get; set; }
    [XmlElement("CodeSourceType")]
    public byte CodeSourceType { get; set; }
    [XmlElement("HelperCodeType")]
    public byte HelperCodeType { get; set; }
    [XmlElement("HelperCodeSourceType")]
    public byte HelperCodeSourceType { get; set; }
    [XmlElement("PkgRatio")]
    public int PkgRatio { get; set; }
}

[Serializable]
public class VarData
{
    [XmlElement("VariableDataId")]
    public string VariableDataId { get; set; …