RFC的测试值指定:
Appendix D - HOTP Algorithm: Test Values
The following test data uses the ASCII string
"12345678901234567890" for the secret:
Secret = 0x3132333435363738393031323334353637383930
Table 1 details for each count, the intermediate HMAC value.
Count Hexadecimal HMAC-SHA-1(secret, count)
0 cc93cf18508d94934c64b65d8ba7667fb7cde4b0
1 75a48a19d4cbe100644e8ac1397eea747a2d33ab
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因此,如果我尝试在红宝石中获得0的HMAC,我会得到:
[20] pry(AuthyOTP)> secret_key = "12345678901234567890"
=> "12345678901234567890"
[22] pry(AuthyOTP)> OpenSSL::HMAC.hexdigest(digest, secret_key, "0")
=> "32a67f374525d32d0ce13e3db42b5b4a3f370cce"
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我原本应该得到 cc93cf18508d94934c64b65d8ba7667fb7cde4b0
所以我在java中编写了一个实现,我得到了同样的结果:
Calculation OTP for movingFactor = 0
2. Calculate Hash =
32a67f374525d32d0ce13e3db42b5b4a3f370cce
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那么当秘密是"12345678901234567890"时,什么是"0"的十六进制SHA1-HMAC?