标签: phpquery

使用PHPQuery的问题

我试图使用PHPquery来抓取网页(free-lance.ru)

Simple HTML Dom中的Equiv代码正在工作:

include('simple_html_dom.php');

$shd = str_get_html($html);

$projects = array();
$i = 0;
foreach ($shd->find('.project-preview') as $work){
    $projects[$i]['name'] = $work->find('h3', 0)->children(1)->plaintext;
    $i++;
}
Run Code Online (Sandbox Code Playgroud)

但我需要它在PHPQuery中.

我尝试使用类似的东西:

include('phpQuery.php');

$pq = phpQuery::newDocument($html);

foreach ($pq->find('.project-preview') as $work){
        echo 'wow';
}
Run Code Online (Sandbox Code Playgroud)

但它不起作用... sizeof($ pq-> find('.project-preview'))为0

我将非常感谢任何帮助.

php parsing simple-html-dom phpquery

2
推荐指数
1
解决办法
6305
查看次数

从html页面使用phpquery获取图像src

如何从HTML页面使用phpQuery获取img src?补充:我需要获取此“ src”以在解析器模块中用于drupal

phpquery

1
推荐指数
1
解决办法
1615
查看次数

带逗号的小数位数或第一个数字后的点数

编辑2

感谢大家的帮助!通过融合答案和其他一些论坛帖子我设法通过以下方式解决:

$string = strip_tags($oNode['div.item-prijs']);
$array = str_split($string,1); 
$arraytotal = ( $array[0] . ',' . $array[1] . $array[2] );
echo $arraytotal;
Run Code Online (Sandbox Code Playgroud)

现在显示正确的价格."7,49"我自动转换为的PHP脚本.

对不起,我不能给更多的问题回答标记.案件结案.

拜托了伙计们

$price = strip_tags($oNode['div.item-prijs']);
$new_price = substr(chunk_split($price, 1, ','), 0, -1); 
echo $new_price;
Run Code Online (Sandbox Code Playgroud)

这将回应7,4,9而不是7,49.但是这段代码是目前为止最好的代码.有人知道如何解决这个问题吗?

好吧,我现在已经坚持了一段时间..

我正在从网站解析数据,我想得到价格,但在网站上没有逗号或价格之间的点.所以它显示像499,4大于99.

当我做:

$price = $oNode['div.item-prijs'];
echo $price;
Run Code Online (Sandbox Code Playgroud)

它将回显499.我希望它添加逗号或4到99之间的点.

我试过了:

$price = $oNode['div.item-prijs'];
$new_price = substr(chunk_split($price, 1, ','), 0, -1); 
echo $new_string;
Run Code Online (Sandbox Code Playgroud)

这将回应:

<,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,7,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,4,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,0,<,s,u,p,>,6,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,6,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,1,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,8,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,2,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,0,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, …
Run Code Online (Sandbox Code Playgroud)

php string parsing phpquery

0
推荐指数
1
解决办法
432
查看次数

PHPQuery ...试图从页面获取所有图像的所有链接

我试图使用PHPQuery获取给定页面上所有图像的所有链接.我正在使用PHPQuery的PHP支持语法.

这是我到目前为止的代码:

include('phpQuery-onefile.php');

$all = phpQuery::newDocumentFileHTML("http://www.mysite.com", $charset = 'utf-8');

// in theory this gives me all image sources
$images = $all->find('img')->attr('src'); 

// but if I do `echo $images;` what I get is the src to the first image
Run Code Online (Sandbox Code Playgroud)

出于好奇,我尝试过

$images = $all->find('img:first')->attr('src'); 
Run Code Online (Sandbox Code Playgroud)

$images = $all->find('img:last')->attr('src'); 
Run Code Online (Sandbox Code Playgroud)

并且它分别正确地打印了第一个和最后一个图像的地址,但是我怎么能得到所有链接的数组呢?

php jquery parsing phpquery

0
推荐指数
1
解决办法
1679
查看次数

标签 统计

phpquery ×4

parsing ×3

php ×3

jquery ×1

simple-html-dom ×1

string ×1