我需要允许类型实现两个接口(Foo和Bar),而不是其中之一.
interface Foo {};
interface Bar {};
class Foz implements Foo {};
class Baz implements Bar {};
class Foobar implements Foo, Bar {};
$resolver = new OptionsResolver();
$resolver->setRequired('data');
$resolver->setAllowedTypes('data', ['Foo', 'Bar']);
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错误!允许Foz和Baz实例.
我需要允许类型的子类Bar,而不是Bar实例.
class Bar {};
class Foobar extends Bar {};
class FoobarBaz extends Foobar {};
$resolver = new OptionsResolver();
$resolver->setRequired('data');
$resolver->setAllowedTypes('data', ['Bar']);
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错误!也允许Bar实例.
我可以重新设计我的类/接口,但这不是设计问题.那么,用这个组件可以实现吗?