我用Google搜索了一下,但在这个问题上找不到很多东西.我有一个RSS提要的URL,我想知道如何以NSDictionary的形式将该内容放入我的应用程序.我可以使用NSData的initWithContentsOfURL吗？
我有这个方法.
[self postRequestWithURL: (NSString *) postArgs:(NSDictionary *) headerArgs: (NSDictionary *) ];
我怎样才能正确调用此方法？
网址是: http://www.google.com/reader/api/0/edit-tag?
帖子args是: "a=user/-/state/com.google/read&ac=edit-tags&s=feed/%@&i=%@&T=%@", entry.link, entry.identifier, tokenString
和标题是:
NSString *authHeader = [NSString stringWithFormat:@"GoogleLogin %@", authString];
[thttpReq addValue:authHeader forHTTPHeaderField:@"Authorization"];
[thttpReq addValue:@"Content-Type" forHTTPHeaderField:@"application/x-www-form-urlencoded"];
sompne可以帮我插入postArgs和HeaderArgs NSDictionary吗？谢谢保罗
编辑:
代码:
//存储问题字典
- (void)requestFinished:(ASIHTTPRequest *)request
{
NSData *responseData = [request responseData];
NSString *json = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
NSDictionary *qs = [json objectFromJSONString];
self.questions = qs;
NSLog(@"%@", questions);
[json release];
[self setQuestions];
[load fadeOut:load.view withDuration:0.7 andWait:0];
UIBarButtonItem *anotherButton = [[UIBarButtonItem alloc] initWithTitle:@"Start" style:UIBarButtonItemStylePlain target:self action:@selector(start:)];
self.navigationItem.rightBarButtonItem = anotherButton;
}
我在NSDictionary中有以下项目:
(
{
max = 120;
min = 30;
question = "Morning Bodyweight (Kg)";
questionId = 1;
questionNumber = 1;
sectionId = 1;
type = TextInput;
},
{
question = …运行我的代码时出错.罪魁祸首是我从下面的plist访问一个字符串:
NSString *sImageFile = [dictionary objectForKey:@"answerCorrect"];
NSLog(@"%@",sImageFile);
我在这里显示的cocos2d Init中有这个:
-(id) init
{
// always call "super" init
// Apple recommends to re-assign "self" with the "super" return value
if( (self=[super init])) {
NSUserDefaults *sud = [NSUserDefaults standardUserDefaults];
NSString *ctlLang = [sud valueForKey:@"ctlLang"];
NSNumber *questionState = [sud valueForKey:@"questionState"];
NSNumber *scoreState = [sud valueForKey:@"scoreState"];
gameArray = (NSMutableArray *)[sud valueForKey:@"gameArray"];
for (NSString *element in gameArray) {
NSLog(@"\nQL gameArray value=%d\n", [element intValue]);
}
NSString *path = [[NSBundle mainBundle] bundlePath];
NSString *finalPath = [path stringByAppendingPathComponent:ctlLang]; …我有一个NSDictionary,我试图从中拉出一个字符串.出于某种原因,最后一个字符串似乎无法恢复(!？!).在下面的代码中,我检索labelString的NSString对象,完全没有问题.但是当我尝试为foo检索NSString时,我总是没有.但我没有看到差异 - 你能看出我做错了吗？
NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:
[NSNumber numberWithInt:CellStyleLabelledStringCell], @"cellStyle",
@"name", @"fieldName",
@"Name", @"labelString",
foodItem.name, @"contentString",
@"foo", @"fookey",
nil];
NSString *string1 = (NSString *)[dict objectForKey:@"fookey"];
NSString *string2 = (NSString *)[dict objectForKey:@"labelString"];
NSLog(@"[%@][%@]", string1, string2);
日志消息看起来像这样,并备份我在调试器中看到的内容(即string1为null):
2012-03-17 21:35:03.302 QuickList7 [8244:fb03] [(null)] [名称]
真的很困惑.提前致谢.
我正在尝试使用我从服务器获得的JSON响应字典.当我打印字典的描述时,一切都井然有序
Printing description of dict:
{
category = 1;
code = 1;
name = "xxxx";
pictureUrl = "xxxx";
sessionId = xxx;
status = 0;
}
我需要"代码"值,当我使用objectForKey:@"code"来获取它时,我得到一个错误的值:
int code = [NSDictionary objectForKey:@"code"];
在此之后我打印出代码的值和它的东西,如3483765348,这是非常非常错误的.
为什么会这样？
我要做的是检查我的词典有多深.我的JSON有两种可能性:
stop-schedule:
0:
route:
1:
route:
要么
stop-schedule:
route:
所以我正在检查是否需要更深入或更深入.
通常我会做一些类似的事情
[dict objectForKey:@"0"]
检查密钥是否存在(如果没有则返回nill)但是由于某种原因我在iOS上测试时遇到错误.
[__NSCFArray objectForKey:]: unrecognized selector sent to instance
我试图创建一个字典(不确定它是否应该NSDictionary或NSMutableDictionary)从NSString一个数组(不确定它是否应该NSArray或NSMutableArray).
属性:
@property(nonatomic, readonly) NSMutableDictionary * categories;
执行:
@synthesize categories = _categories;
- (NSMutableDictionary *)categories{
if(! _categories) {
for(PFObject * each in self.products) {
NSString * currentcategory = [each valueForKey:@"subtitle"];
NSArray * currentlist = [_categories objectForKey:currentcategory];
if(! currentlist) {
currentlist = [[NSArray alloc] init];
}
NSMutableArray * newArray = [currentlist mutableCopy];
[newArray addObject:each];
NSArray * newlist = [NSArray arrayWithArray:newArray];
[_categories setObject:newlist forKey:currentcategory];
}
}
NSLog(@"After constructor the value of the …我有NSDictionary值,我想将其转换为Json字符串,如:
{
body = "10-feb";
comments = (
);
complete = 1;
"created_at" = "2014-02-09T15:56:01Z";
"due_at" = "2014-01-10 20:00:00 +0000";
"due_on" = "2014-10-02";
id = 439824;
"notification_sent" = 0;
"notify_user" = 0;
"organization_id" = 972;
participants = (
);
reminders = (
);
starred = 0;
"updated_at" = "2014-02-09T15:56:01Z";
"user_id" = 11129;
}
我将它转换为json的方式是:
- (NSString*) jsonStringWithPrettyPrint:(BOOL) prettyPrint str:(NSDictionary *)str {
NSError *error = nil;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:str
options:(NSJSONWritingOptions) (prettyPrint ? NSJSONWritingPrettyPrinted : 0)
error:&error];
if (! jsonData) …Swift中的列表字典键行为与Objective-C不同.
Objective-C的:
NSDictionary *myDict = @{@"key1": @"One",@"key2": @"Two",@"key3": @"Three"};
for (NSString *myKey in myDict) {
NSLog(@"key: %@",myKey);
}
Objective-C调试输出:
key: key1
key: key3
key: key2
但Swift表现不同:
let stringOfStrings = ["key1":"value1", "key2":"value2"]
for key in stringOfStrings {
println(key)
}
斯威夫特的输出:
(key2, value2)
(key1, value1)
如何使Swift像Objective-C一样执行; 即,仅列出键？