我有每组约有30,000行的8组数据,数据是针对不同语言的相同结构.
该站点的前端将获得相对较高的流量.
所以我的问题是关于MySQL性能,如果我应该有一个表有一列来区分数据所属的集合(即coloumn"language")或为每种语言集创建单独的表?
(解释为什么如果可能会真的有用)
在此先感谢Shadi
我面临以下错误:
com.google.gwt.user.server.rpc.UnexpectedException: Service method 'public abstract void com.xxx.Service.save(com.xxx.Bean)' threw an unexpected exception: org.hibernate.AssertionFailure: null id in com.xxx.Bean entry (don't flush the Session after an exception occurs)
at com.google.gwt.user.server.rpc.RPC.encodeResponseForFailure(RPC.java:385)
at com.google.gwt.user.server.rpc.RPC.invokeAndEncodeResponse(RPC.java:588)
at com.google.gwt.user.server.rpc.RemoteServiceServlet.processCall(RemoteServiceServlet.java:208)
at com.google.gwt.user.server.rpc.RemoteServiceServlet.processPost(RemoteServiceServlet.java:248)
at com.google.gwt.user.server.rpc.AbstractRemoteServiceServlet.doPost(AbstractRemoteServiceServlet.java:62)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:641)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:306)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:240)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:161)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:496)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:164)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:541)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:383)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:243)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:188)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:166)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:288)
at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908)
at java.lang.Thread.run(Thread.java:680)
Caused by: org.hibernate.AssertionFailure: null id in …Run Code Online (Sandbox Code Playgroud) 所以我正在尝试使用文档中的语法创建联合表.在此之后,我创建了一个这样的表:
CREATE TABLE `federated_table` (
`table_uid` int(10) unsigned not null auto_increment,
...,
PRIMARY KEY (`table_uid`)
) ENGINE=FEDERATED DEFAULT CHARSET=latin1 CONNECTION='mysql://user:password@host.name:3306/';
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每次我这样做,我都会收到错误:
ERROR 1432 (HY000): Can't create federated table. The data source connection string 'mysql://user:password@host.name:3306/' is not in the correct format
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我查看了文档,我相信我正在关注这些文档.此连接字符串的正确语法是什么?
我有一个旧的应用程序,从MySQL 5.0升级到5.1后开始失败.
一些研究表明这是由于"严格模式"导致阻止插入某些类型的"无效"值,这些值之前只是自动转换为合理的值.
我试过SET @@SESSION.sql_mode = ''和SET @@GLOBAL.sql_mode = '',但我仍然得到错误.
也尝试在评论sql_mode中my.ini.
有没有更强大的"核"选择来解决这个问题?
我试图强制用户的地址信息中的州/省和国家名称来自我列出国家和州/省的一组表格.为了做到这一点,我尝试运行这样的alter table命令......
ALTER TABLE User
ADD FOREIGN KEY (stateProvince,country)
REFERENCES `StateProvince`(`name`,`countryName`);
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然后我收到这条消息......
使用外键约束创建表'realtorprint_dev/#sql-d5c_3d'失败.引用的表中没有索引,其中引用的列显示为第一列.
有没有人知道如何处理此错误消息?
这是州和国家表的创建......
CREATE TABLE Country (
name varchar(40) NOT NULL,
abbreviation varchar(4) NOT NULL,
PRIMARY KEY (name)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE StateProvince (
countryName varchar(40) NOT NULL,
name varchar(100) NOT NULL,
abbreviation varchar(3) NOT NULL,
PRIMARY KEY (countryName,name)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
alter table StateProvince
add constraint FK_StateProvince_Country
foreign key (countryName)
references Country (name);
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现在对于用户表...
create table realtorprint_dev.user (
id bigint not null,
created datetime, …Run Code Online (Sandbox Code Playgroud) 此查询运行,但它会生成表的名称,而不是从该表中实际选择.
SELECT T.*
FROM (SELECT tablename
FROM ListOfTables
WHERE id = 0) AS T
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在ListOfTables包含的地方id=0, tablename='some_table',我想返回相同的结果集,就好像我直接写了一样:
SELECT * FROM some_table
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在MySQL 5中是否有以本机方式执行此操作,或者我是否必须在应用程序中执行此操作?
我有一个包含用户元数据的表.有4个领域......
`ID`,`meta_name`,`meta_value`,`user_id`
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我想在此表中存储电子邮件.当然,这些必须是独一无二的.但是我想在此表中存储其他数据,其中数据不需要是唯一的.有没有什么方法可以限制'meta_value'为独特,只有'meta_name'等于'电子邮件'?
嗨,我想知道哪种查询适用于多个表.
例如:
select table1.id, table1.name from table1,table2,table3
where table1.id=table2.id and table2.id=table3.id
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要么
select table1.id, table1.name
from table1
inner join table2 on table1.id=table2.id
inner join table3 on table2.id=table3.id
where 1
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要么
select table1.id, table1.name
from table1
join table2 on table1.id=table2.id
join table3 on table2.id=table3.id
where 1
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哪种查询最适合性能?
我有两张桌子如下.
user_id | username | first_name | role_type
-----------------------------------------------------------
1 | testuser1 | testu1 | student
2 | testuser2 | testu2 | student
3 | testuser3 | testu3 | student
4 | testuser4 | testu4 | student
5 | testuser5 | testu5 | student
6 | testuser6 | testu6 | admin
7 | testuser7 | testu7 | admin
-----------------------------------------------------------
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user_id | username | approved_id
----------------------------------------------------------------------
1 | testuser1 | 3B888F52-50BC-11E2-B08B-99E5B2CADDF7
2 | testuser2 | 3B888F52-50BC-11E2-B08B-99E5B2CADDF7
3 | testuser3 | 3B888F52-50BC-11E2-B08B-99E5B2CADDF7 …Run Code Online (Sandbox Code Playgroud) 嗨,我正在使用mysql5 innoDB数据库.我想强制删除父行及其相关子表数据的数据.我怎样才能做到这一点.任何人都可以帮助我.
我有这张桌子
CREATE TABLE IF NOT EXISTS `links` (
`link_id` int(20) NOT NULL AUTO_INCREMENT,
`item1_id` int(20) NOT NULL,
`item2_id` int(20) NOT NULL,
PRIMARY KEY (`link_id`),
UNIQUE KEY `item_id` (`item1_id`,`item2_id`)
) ENGINE=InnoDB;
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如何约束它以便the item_id只能在OR中出现一次?item1_iditem2_id
因为我想要一个项目只链接到另一个项目..
mysql ×11
mysql5 ×11
sql ×4
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dynamic-sql ×1
hibernate ×1
hibernate3 ×1
java ×1
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