我的MySQL查询有问题:
include '../inc/mysql_config.php';
$sql="INSERT INTO ordrar
(id, order, namn, adress, postnummer, postort, email, status)
VALUES
(NULL, '$order','$namn','$adress','$postnummer', '$postort', '$email', '$email', '$status')";
mysql_query($sql);
if (!mysql_query($sql)) { die('Error: ' . mysql_error()); }
这输出:
错误:SQL语法中有错误; 查看与您的MySQL服务器版本对应的手册,以便在第1行的'order,namn,adress,postnummer,postort,email,status"VALUES'附近使用正确的语法
谢谢.
解决了:
include '../inc/mysql_config.php';
$sql="INSERT INTO ordrar (id, substans, namn, adress, postnummer, postort, email, status)
VALUES
(NULL, '$substans','$namn','$adress','$postnummer', '$postort', '$email', '$status')";
mysql_query($sql);
if (!mysql_query($sql))
{
die('Error: ' . mysql_error());
}
感谢大家!
大家好,我正在尝试对我的数据库执行以下插入操作,但是每次尝试它都会失败,并且出现错误1064.我有两个双字段用于lat和long,以及一个整数id.有人能告诉我这里发生了什么吗？
INSERT INTO LatLong (lat, long) VALUES (51.53087375, -0.26259048);
我想用他们的全名"blo"来记录所有用户,例如:"Pablo"
我用userPHP参数传递"blo" 参数:
$q=mysql_query("select * From user Where fullName Like '%'".$_REQUEST['user']."'%'",$link );
在php SQL语句中有些错误,因为当我在我的SQL数据库上尝试带有参数"blo"的句子时,我看到SQL语句是正确的,因为它返回了正确的结果,这是带有参数的句子"在它上面: select * From user Where fullName Like "%blo%"
我确定PHP正确接收"blo"参数,然后,它必须是PHP上SQL语句的sintax错误....但我找不到它
编辑:好的!! 最后一句话已经解决,但现在我有这个新句子有同样的问题,它有一个错误,但我不知道在哪里
$query = sprintf("SELECT u.*
FROM USER u
WHERE u.fullName LIKE '%%%s%%' AND email NOT IN (select pp.fk_email2 from permission pp where pp.fk_email1='".mysql_escape($_REQUEST['mymail'])."') AND email NOT LIKE '".mysql_escape($_REQUEST['mymail'])."' ",
mysql_real_escape_string($_REQUEST['user']));
您的SQL语法有错误; 检查与您的MySQL服务器版本对应的手册,以便在第1行的')'附近使用正确的语法
似乎无法解决此错误:
protected void Page_Load(object sender, EventArgs e)
{
if (Page.IsPostBack)
{
//It is a postback so check if it was by div click (NOT WORKING because the javascript isnt posting back)
string target = Request["__EVENTTARGET"];
if (target == "DivClicked")
{
string id = Request["__EVENTARGUMENT"];
//Call my delete function passing record id
using (OdbcConnection cn = new OdbcConnection("Driver={MySQL ODBC 3.51 Driver}; Server=localhost; Database=gymwebsite2; User=root; Password=commando;"))
{
cn.Open();
using (OdbcCommand cmd = new OdbcCommand("DELETE FROM WallPosting WHERE idWallPosting="+id+")", cn))
{ …我正在使用Python并使用MySQLdb模块.我有一个工作连接(我可以成功运行其他查询)
c.execute("ALTER TABLE results ADD COLUMN desc TEXT")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/pymodules/python2.7/MySQLdb/cursors.py", line 166, in execute
self.errorhandler(self, exc, value)
File "/usr/lib/pymodules/python2.7/MySQLdb/connections.py", line 35,
in defaulterrorhandler
raise errorclass, errorvalue
我收到以下错误:
_mysql_exceptions.ProgrammingError: (1064, "You have an error in your SQL
syntax; check the manual that corresponds to your MySQL server version for the
right syntax to use near 'desc TEXT' at line 1")
我之前遇到过类似的麻烦; MySQLdb的语法错误消息非常不具描述性.
怎么解决这个问题？
CREATE TABLE IF NOT EXISTS message(
id INT NOT NULL auto_increment,
userid INT NOT NULL,
date Date NOT NULL,
text varchar(255) NOT NULL,
PRIMARY KEY ('id')
FOREIGN KEY ('userid') REFERENCES users('id'));
我只是想知道是否有人可以帮助我识别语法错误,因为我无法创建表.
所以我正在尝试这样的基本查询:
SELECT `City`.* FROM `city` WHERE (City 'LIKE %a%')
但是我得到了这个错误:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your
MySQL server version for the right syntax to use near ''LIKE %a%') LIMIT 0, 30' at line 1
我想我错过了什么!
connection.php:
$con = mysql_connect("localhost","networka_root","secret");
if (!$con) die('Could not connect: ' . mysql_error());
mysql_select_db("networka_simple_login", $con);
$sql="INSERT INTO `networka` (`username`, `password`,)
VALUES ('$_POST[username]','$_POST[password]')";
if (!mysql_query($sql, $con)) die('Error: ' . mysql_error());
echo "1 record added";
mysql_close($con)
当我把我的我的错误username和password:
您的SQL语法有错误; 检查与MySQL服务器版本对应的手册,以便
) VALUES ('username','password')在第1行附近使用正确的语法