标签: mongodb-aggregation

当我这样做时$lookup,在我的情况下foreignField:"_id",我在数组中得到找到的元素.下面是从后输出一个文档$lookup已经做了检索fromUser,并toUser从users集合:

{ 
    _id : { from : 57b8da368e4a6e1f0043cb3d, to : 57c381af7008e51f009d92df }, 
    fromUser : [
        {
            _id : 57b8da368e4a6e1f0043cb3d, 
            userName: "A"
        }
    ], 
    toUser : [
        {
            _id : 57c381af7008e51f009d92df, 
            userName: "B"
        }
    ]
}

你可以注意到fromUser并且toUser是数组.如何投射fromUser,toUser而不是数组,他们只包含用户的userName,如下所示:

{
    _id : { from : 57b8da368e4a6e1f0043cb3d, to : 57c381af7008e51f009d92df },
    fromUser: "A",
    toUser: "B"
}

我有一个包含如下文档的集合：

{
        "_id" : ObjectId("55b377cb66b393427367c3e2"),
        "comment" : "This is a comment",
        "url_key" : "55b377cb66b393427367c3df", //This is an ObjectId from another record in a different collection
}

我需要在此集合中找到包含注释和url_key重复值的记录。

我可以轻松地生成（使用汇总）相同，单个键（例如：注释）的重复记录，但是我不知道如何对多个关键字进行分组/汇总。

这是我当前的聚合管道：

db.comments.aggregate([ { $group: { _id: { comment: "$comment" }, uniqueIds: { $addToSet: "$_id" }, count: { $sum: 1 } } }, { $match: { count: { $gte: 2 } } }, { $sort: { count : -1} }, {$limit 10 } ]);

有聚合管道:

db.getCollection('yourCollection').aggregate(
    {
        $unwind: {
            path: "$dates",
            includeArrayIndex: "idx"
        }
    },
    {
        $project: {
            _id: 0,
            dates: 1,
            numbers: { $arrayElemAt: ["$numbers", "$idx"] },
            goals: { $arrayElemAt: ["$goals", "$idx"] },
            durations: { $arrayElemAt: ["$durations", "$idx"] }
        }
    }
)

执行以下数据(示例文档):

{
    "_id" : ObjectId("52d017d4b60fb046cdaf4851"),
    "dates" : [
        1399518702000,
        1399126333000,
        1399209192000,
        1399027545000
    ],
    "dress_number" : "4",
    "name" : "J. Evans",
    "numbers" : [
        "5982",
        "5983",
        "5984",
        "5985"
    ],
    "goals": [
        "1",
        "0",
        "4",
        "2"
    ],
   "durations": [
       "78",
       "45",
       "90",
       "90" …

当我对我的收藏进行此查询时...

models.Project.find(function(err, result) {
    //result = doc below
}).populate('media')

...我得到这个结果：

{ 
  _id: 57f36baa6cf34d079c8474a0,
  code: 'ZMIA',
  __v: 0,
  media:[
    { 
      _id: 57f36bb26cf34d079c847766,
      project_code: 'ZMIA',
      amount: 228,
      __v: 0 
    },
    { 
      _id: 57f36bb26cf34d079c84775c,
      project_code: 'ZMIA',
      amount: 250,
      __v: 0 
    } 
  ]
},
{ 
  _id: 57f36baa6cf34d079c8474a1,
  code: 'ZMJU',
  __v: 0,
  media: [] 
}

media是一个引用字段。如何将嵌套的媒体对象（如果存在）聚合到$sum该amount字段并将结果分组project_code？

我想对此架构执行查询:

{ 
   "name" : "xxx",
   "guests" : [ 
       {
            "category" : "category 1",
            "arrived" : false
       },
       {
            "category" : "category 2",
            "arrived" : false
       },
       {
            "category" : "category 1",
            "arrived" : true
       },
       {
            "category" : "category 2",
            "arrived" : true
       }
   ]
}

我想得到一个特定的名字,一个列表,列出每个类别的客人百分比.

对于上面的文档作为示例,我想收到:

{
    name : "xxx",
    results : [
         {
              category : "category 1",
              arrived : 50 (percent)
         },
         {
              category : "category 2",
              arrived : 50 (percent)
         },
    ]

有没有办法用一个MongoDB查询来做到这一点？另外,我应该在客户端还是服务器端进行此计算？

在我的查询中，concat关键字不起作用，它返回null。

这是查询：-

db.leads.aggregate([
{$project:{
    _id:0,
    status:1,
    stage:1,
    "todo.title":1,
    created:{
        day:{$substr:["$createdOn",8,2]},
        month:{$substr:["$createdOn",5,2]},
        year:{$substr:["$createdOn",0,4]}
        },
     myDate:{$concat:["$created.day","-","$created.month","-","$created.day"]}
         //----above $concat is not working-----//
         //--i want that `myDate` should be "12-09-2016"----//
    }
  }

])

这是查询输出：

{
    "stage" : "Prospect",
    "todo" : [],
    "status" : "OPEN",
    "created" : {
        "day" : "12",
        "month" : "09",
        "year" : "2016"
    },
    "myDate" : null

   //--here i want that `myDate` should be "12-09-2016"----//
}

在mongodb 中将createdOn字段数据存储为Date类型，即