标签: mod-wsgi

在第一次 HTTP GET 期间（在重新加载守护进程模式下的 WSGI 之后），admin.site.unregister 抛出一个 NotRegistered 异常，但 admin.site.register 抛出一个 AlreadyRegistered 异常（catch-22？）但是，在随后的 HTTP GET 中，一切都加载得很好，没有错误。

设置：

• 姜戈 1.3
• 阿帕奇 2.2
• CentOS

设置.py：

INSTALLED_APPS = (
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    #'django.contrib.sites', #(this didn't seem to make a difference)
    'django.contrib.messages',
    'django.contrib.staticfiles',
    # Uncomment the next line to enable the admin:
    'django.contrib.admin',
    # Uncomment the next line to enable admin documentation:
    'django.contrib.admindocs',
    'base',
    'sample',
    'reports',
    'south',
)

模型.py：

from django.db import models
from django.contrib import admin
from django.contrib.auth.models import User
from django.contrib.auth.admin import …

我正在尝试运行在同一VirtualHost. 其中一个应用程序是此处myapp指定的标准 hello-world 代码。它加载得非常好。另一个应用程序是 Django 网站。它失败并显示.uiappImportError

我在wsgi 文档中读到， 的值python-path附加到sys.path，所以这就是我在WSGIDaemonProcessfor中指定的值uiapp。

我无法确定问题是出在 Python 代码上还是 Apache 配置上。

这是我的虚拟主机配置：

    [ . . . ]

    # processGroups
    WSGIProcessGroup uiapp
    WSGIProcessGroup myapp

    # configurations for django sites
    WSGIScriptAlias /uiapp "/some/path/ui_dir/site_prod/wsgi.py"
    WSGIScriptAlias /myapp "/some/other/path/myapp.wsgi"

    # daemons
    WSGIDaemonProcess uiapp processes=2 threads=25 display-name=site_prod_wsgi python-path=/some/path/ui_dir
    WSGIDaemonProcess myapp processes=2 threads=25 display-name=helloworld_wsgi

    # doc root for /uiapp
    <Directory "/some/path/ui_dir/site_prod">
        Order allow,deny
        Allow from all
    </Directory>

    # …

我需要开发一个python(v2.7)wsgi应用程序来接收和解析从另一个Web发布的json对象中的数据.

示例JSON对象的格式如下所示.

{
  "BuildId":"4c53575f-36f48a7f1f37",
  "EventId":1,
  "EventName":"Archiving Complete",
  "EventDescription":"Fired each time the build products finish unzipping on an archive server after a successful build.",
  "ConfigurationId":2021,

  [
     {
        "archive_server":"CA",
        "ftp":"ftp://ABC.com/2011_V2/ccoderre_build_dev_build/2011.4.103.002",
        "dfs":"\\\\ABD.com\\ccoderre_build_dev_build\\2011.4.103.002"
     }
  ],
  "Changelists":
  [
     {
        "author":"mike",
        "description":"integrating from mainline\n",
        "number":1233242,
        "status":"OK",
        "submit_time":"\/Date(1305844615000)\/"
     }
  ],
  "InheritedChangelists":[],
  "CustomEventInfo":
  [
     {
        "Key":"ArchiveServer",
        "Value":"buildfsct"
     },
     {
        "Key":"HasSymbols",
        "Value":0
     }
  ]
}

如何使用wsgi来获取(读取)"BuildId","ConfigurationId","ftp"等？谁能帮我？提前致谢!

所以我犯了运行Ubuntu Server(12.04)的错误.我安装了Python3和mod_wsgi的python3版本.

Apache2启动 - 但保留以下错误日志:

[Mon May 05 11:00:24 2014] [error] python_init: Python version mismatch, expected '2.7.2+', found '2.7.3'.
[Mon May 05 11:00:24 2014] [error] python_init: Python executable found '/usr/bin/python'.
[Mon May 05 11:00:24 2014] [error] python_init: Python path being used '/usr/lib/python2.7/:/usr/lib/python2.7/plat-linux2:/usr/lib/python2.7/lib-tk:/usr/$
[Mon May 05 11:00:24 2014] [notice] mod_python: Creating 8 session mutexes based on 80 max processes and 0 max threads.
[Mon May 05 11:00:24 2014] [notice] mod_python: using mutex_directory /tmp
[Mon May 05 11:00:24 2014] [warn] mod_wsgi: Compiled …

我试图返回到客户端 mysql 数据，我得到 mod_wsgi (pid=2304): 异常发生处理 WSGI 脚本 TypeError: 期望的字节字符串值序列，找到类型列表的值\r

    def application(environ, start_response):

    result = ChildClass().getValue()
    status = '200 OK'
    output =  result

    response_headers = [('Content-type', 'text/plain'),
                        ('Content-Length', str(len(output)))]
    start_response(status, response_headers)

    print(output)
    return [output]

class ChildClass(): # define child class
   print('ppp')
   def __init__(self):
      print("Calling child constructor")

   def childMethod(self):
      print('Calling child method')
      #Parentclass().parentMethod()

   def getValue(self):
    # Open database connection
    db = mysql.connector.connect(user='root', password='55118',host='127.0.0.1',database='test')
    cursor = db.cursor()
    query = ("SELECT * from employees2")
    cursor.execute(query)
    #for (first_name) in cursor:
    return  cursor.fetchall()

如何将 cursor.fetchall …

我正在为 Centos 7 寻找 mod_wsgi 的 python3 版本。我知道对于 Fedora，它是 python3-mod_wsgi，而 ubuntu 是 libapache2-mod-wsgi-py3。但是，我找不到 Centos 7 的等效项。我需要这个包才能运行我的 django 网站。

正如之前在多个问题/答案中强调的那样，即这个和这个我已经将我的配置WSGISocketPrefix为/etc/httpd/run/wsgi

/etc/httpd/run 目录具有 root:apache 权限，创建的 sock 文件具有 apache:root 权限。

我面临的问题是 apache总是试图连接到比它应该寻找的少一个的袜子。示例袜子是/var/run/httpd/wsgi.1769.1.1.sock但 apache 寻找/var/run/httpd/wsgi.1769.0.1.sock

AFAIK 没有权限问题，问题在于 apache 正在查找的 WSGI 袜子号。我怎样才能克服这个问题？为什么sock-versionwsgi 和 apache 之间存在不匹配？

确切的日志行： (2)No such file or directory: [client A.B.C.D:57798] mod_wsgi (pid=1549): Unable to conn ect to WSGI daemon process 'wsgi' on '/etc/httpd/run/wsgi.1144.0.1.sock' after multiple attempts.

我已经在带有 Apache2.4.7 的 Ubuntu 服务器上安装了我的 Django 应用程序，并将其配置为在虚拟环境中使用 py3.5.2。

但是，从我在错误中看到的，它从 3.5 开始，默认为 3.4。

请解释为什么会发生这种情况：

/var/www/venv/lib/python3.5/site-packages
/usr/lib/python3.4

请参阅下面的完整错误：

SyntaxError at /

invalid syntax (forms.py, line 2)

Request Method:     GET
Request URL:    http://intranet.example.com/
Django Version:     1.10.1
Exception Type:     SyntaxError
Exception Value:    

invalid syntax (forms.py, line 2)

Exception Location:     /var/www/intranet/formater/views.py in <module>, line 7
Python Executable:  /usr/bin/python3
Python Version:     3.4.3
Python Path:    

['/var/www/intranet',
 '/var/www/venv/lib/python3.5/site-packages',
 '/usr/lib/python3.4',
 '/usr/lib/python3.4/plat-x86_64-linux-gnu',
 '/usr/lib/python3.4/lib-dynload',
 '/usr/local/lib/python3.4/dist-packages',
 '/usr/lib/python3/dist-packages',
 '/var/www/intranet',
 '/var/www/intranet/venv/lib/python3.5/site-packages']

这是我的 apache2.conf 文件：

WSGIScriptAlias / /var/www/intranet/intranet/wsgi.py
#WSGIPythonPath /var/www/intranet/:/var/www/intranet/venv/lib/python3.5/site-packages

WSGIDaemonProcess intranet.example.com python-path=/var/www/intranet:/var/www/venv/lib/python3.5/site-packages
WSGIProcessGroup intranet.example.com …

我正在运行带有 Ubuntu 和 Apache 的服务器。现在我试图让 Anaconda 与 mod_wsgi 一起工作，但无法让它工作。

首先。如果我使用 mod_wsgi-express，它就可以工作。按照https://anaconda.org/pypi/mod_wsgi安装到 Python 部分中的说明，我可以通过首先设置PYTHONHOME=/opt/anaconda然后/opt/anaconda3/bin/mod_wsgi-express start-server.

我想使用 Apache，所以我将 mod_wsgi 模块从 anaconda 加载到 apache 中。然后我有一个看起来像这样的 VirtualHost：

WSGIPythonHome /opt/anaconda3
WSGIPythonPath /opt/anaconda3/lib/python3.6/site-packages:/path/to/application
<VirtualHost *:8080>
ServerName example.com
WSGIDaemonProcess example python-home=/opt/anaconda3 python-path=path/to/application:/opt/anaconda3/lib/python3.6/site-packages
WSGIProcessGroup example

WSGIScriptAlias / /path/to/application/wsgi.py

<Directory /path/to/application/static>
    Require all granted
</Directory>

<Directory /path/to/application>
<Files wsgi.py>
    Require all granted
</Files>
</Directory>

</VirtualHost>

现在到了问题。我在我的 apache 错误日志中收到此错误。如果我不PYTHONHOME=/opt/anaconda使用 mod_wsgi_express指定，我会得到同样的错误。

[Wed Mar 01 09:31:17.159233 2017] [core:trace4] [pid 16941] mpm_common.c(530): mpm child 19356 …

我正在使用Django 1.11,Apache 2.2和mod_wsgi制作一个使用Python 2.7的Web应用程序.我在渲染页面时遇到问题.完整的追溯是,

Environment:


Request Method: GET
Request URL: http://website.com/~user/irtf/

Django Version: 1.11.1
Python Version: 2.7.13
Installed Applications:
['irtf.apps.IrtfConfig',
 'django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'mod_wsgi.server']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware']



Traceback:

File "/home/path/irtf_website/mysiteenv/lib/python2.7/site-packages/django/core/handlers/exception.py" in inner
  41.             response = get_response(request)

File "/home/path/irtf_website/mysiteenv/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
  187.                 response = self.process_exception_by_middleware(e, request)

File "/home/path/irtf_website/mysiteenv/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
  185.                 response = wrapped_callback(request, *callback_args, **callback_kwargs)

File "/home/path/irtf_website/mysite/irtf/views.py" in index
  18.         return HttpResponse(template.render(request))

File "/home/path/irtf_website/mysiteenv/lib/python2.7/site-packages/django/template/backends/django.py" in render
  64.         context = …