我一直在使用以下代码,几乎没有任何问题,但今天Xcode开始抱怨它BIGTIME.在我发现错误/内存泄漏之前,我几乎疯了.Xcode表示"消息已发送到解除分配的实例".我评论了几行(发行版),它停止了崩溃.
问题是,我完全迷失在这里......我不应该释放那些以避免内存泄漏吗?我的目标是针对这个项目的iOS 4.0,所以手动内存管理是必须的.
+ (NSString*)reformatRule:(NSString*) ruleStr {
NSString *bufRule = [[[NSString alloc] init] autorelease];
NSString *buf = [[NSString alloc] init];
char c = 0;
NSString *value = [[NSString alloc] init];
for(int i=0;i<[ruleStr length];i++){
c = [ruleStr characterAtIndex:i];
if([self isCharacterOrDigit:[NSString stringWithFormat:@"%c",c]]){
buf = [buf stringByAppendingString:[NSString stringWithFormat:@"%c",c]];
}else{
DLog(@"says:%@",buf);
value = [buf stringByReplacingOccurrencesOfString:@" " withString:@""];
//[buf release];
//buf = [[NSString alloc] init];
buf = @"";
if (![value isEqualToString:@""]) {
if ([value isEqualToString:CONDITION_AND] || [value isEqualToString:CONDITION_OR]) {
bufRule = [bufRule stringByAppendingString:[NSString stringWithFormat:@"%@",value]];
}else{ …Run Code Online (Sandbox Code Playgroud) 如果a vector包含一堆使用new然后解除引用而分配的元素,那么在vector删除这些元素时会释放这些元素的内存吗?例如:
vector<Obj> a = *(new vector<Obj>());
a.push_back(*(new Obj()));
delete &a;
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Obj创建的新内容是否已取消分配?
美好的一天!我在获取java线程的内存使用方面遇到了麻烦.我的研究把我带到了ThreadMxBean库.根据javadocThreadMXBean#setThreadAllocatedMemoryEnabled,应该有一个getThreadAllocatedBytes允许获取线程内存的方法.但是,我找不到这种类的方法,而存在上述文档中描述的其他方法.
示例getCurrentThreadCpuTime()并isThreadCpuTimeEnabled()显示在我的代码中.
import java.lang.management.ManagementFactory;
import java.lang.management.ThreadMXBean;
import javax.management.AttributeNotFoundException;
import javax.management.InstanceNotFoundException;
import javax.management.MBeanException;
import javax.management.MalformedObjectNameException;
import javax.management.ReflectionException;
class TwoThreadsTest {
public static void main (String[] args) throws Exception {
new Coding("Jamaica").start();
ThreadMXBean threadBean = ManagementFactory.getThreadMXBean();
long b = threadBean.getCurrentThreadCpuTime();
boolean bool= threadBean.isThreadCpuTimeEnabled();
System.out.println(bool);
}
}
Run Code Online (Sandbox Code Playgroud) 通过简单的保留/释放方案查看此代码片段:
#import <Foundation/Foundation.h>
@interface SomeClass : NSObject
@end
@implementation SomeClass
@end
int main(int argc, const char * argv[])
{
SomeClass *aClass = [[SomeClass alloc] init];
NSLog(@"retainCount: %lu", [aClass retainCount]);
[aClass retain];
NSLog(@"retainCount: %lu", [aClass retainCount]);
[aClass release];
NSLog(@"retainCount: %lu", [aClass retainCount]);
[aClass release];
NSLog(@"retainCount: %lu", [aClass retainCount]);
return 0;
}
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这是结果输出:
2013-04-29 17:33:50.695 retainCount: 1
2013-04-29 17:33:50.697 retainCount: 2
2013-04-29 17:33:50.697 retainCount: 1
2013-04-29 17:33:50.698 retainCount: 1
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最后一个retainCount应为"0"或应用程序崩溃.为什么结果为"1"?!
我正在编写一个包含"info"类型信息的简单数据库的代码.
这是我的代码:
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
#define NAME_LENGTH 20
#define EMAIL_LENGTH 15
struct info {
char name[NAME_LENGTH];
char email[EMAIL_LENGTH];
int flag;
};
int createDB(char *name) {
FILE * file = fopen(name, "w+b");
return fclose(file);
}
FILE *openDB(char *name) {
FILE* file = fopen(name, "r+b");
if(file != NULL) return file;
return NULL;
}
int closeDB(FILE *f) {
return fclose(f);
}
struct info *get(FILE *file, int index) {
struct info* temp;
fseek(file, index*sizeof(struct info), SEEK_SET);
fread(temp, 1, sizeof(struct info), file); …Run Code Online (Sandbox Code Playgroud) 假设我们想在C++中声明一个函数,我在其中声明一个局部变量,int p=new int [10];然后我做了一些操作,最后我做了一些操作return p;.
正如人们常说的那样,如果我们使用new,我们必须delete.但我想在这种情况下,我们不应该删除,对吧?否则,它根本不能返回p,对吧?但是,我也在考虑是否应该删除函数在测试时返回的项目int main().
我的程序在尝试为我的阵列分配新内存时保持染色.通过调用添加单词功能.任何帮助都会很棒!
完整代码下载@ http://www.johnsoncomputertechnologies.org/pgm2demo.zip
#include <iomanip> //Standard IO Manipulators Library
#include <algorithm>
#include <iostream> //Standard input/output library
#include <string> //Standard string Library
#include <cassert> //Error handeling Library
#include "pgm2.h"
using namespace std;
dictionary::dictionary()
{
wordptr = new value_type[DICTONARY_CAPACITY];
deffptr = new value_type[DICTONARY_CAPACITY];
used = 0;
}
dictionary::dictionary(const dictionary& other)
{
value_type *wordptr;
value_type *deffptr;
wordptr = new value_type[other.capacity];
deffptr = new value_type[other.capacity];
used = other.used;
capacity = other.capacity + 1;
copy(wordptr, other.wordptr + used, other.wordptr);
copy(deffptr, other.deffptr + used, other.deffptr);
} …Run Code Online (Sandbox Code Playgroud) 我是编程的新手,我正在努力理解它们之间的区别
A = (char * ) malloc(sizeof(char)*n);
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和
A = (char * ) malloc(sizeof(char));
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要么
A = new char [n];
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和
A = new char;
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当我没有指定特定数据类型的对象数时,编译器分配给此指针的默认内存是多少.
当我宣布时
A = new char [n];
cout << A[n+1];
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它没有给我一个分段错误.
它应该不会给出分段错误,因为我试图访问超出为阵列分配的内存.
我正在开发一个简单的车辆路径问题算法,我对内存管理有一点问题.所以我有以下课程
在这一个我存储订单的数据
Order::Order(int id, int idLoc, double xCoord, double yCoord, double demand, int startTime, int endTime, int serviceTime) {
this->id = id;
this->idLoc = idLoc;
this->xCoord = xCoord;
this->yCoord = yCoord;
this->demand = demand;
this->startTime = startTime;
this->endTime = endTime;
this->serviceTime = serviceTime;
}
Order::~Order() {
// TODO Auto-generated destructor stub
}
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在这一个中,我存储了一个订单列表,这些订单代表了在分发期间服务的一系列客户.
Route::Route(int idRoute,Vehicle *vehicleRoute) {
id = idRoute;
vehicle = vehicleRoute;
demandRoute = -1;
serviceTimeRoute =-1;
earliestTimeRoute =-1;
latestTimeRoute = -1;
serviceDistanceRoute = -1;
orders = new std::deque<Order>; …Run Code Online (Sandbox Code Playgroud) c++ ×5
c ×2
java ×2
memory-leaks ×2
objective-c ×2
ios ×1
jvm ×1
malloc ×1
memory ×1
new-operator ×1
retaincount ×1
vector ×1