在TileMill/CartoCSS中有一个选项可以有一个布尔"OR"吗?我确实尝试过正则表达式,但没有成功.我想简化这个CSS:
@ciPolyBackground: #F79320;
@ciPolyOpacity: 0.5;
#countries {
[ne_10m_adm = "BOL"] { polygon-fill: @ciPolyBackground; polygon-opacity: @ciPolyOpacity; }
[ne_10m_adm = "BRA"] { polygon-fill: @ciPolyBackground; polygon-opacity: @ciPolyOpacity; }
[ne_10m_adm = "BWA"] { polygon-fill: @ciPolyBackground; polygon-opacity: @ciPolyOpacity; }
[ne_10m_adm = "CHN"] { polygon-fill: @ciPolyBackground; polygon-opacity: @ciPolyOpacity; }
[ne_10m_adm = "COD"] { polygon-fill: @ciPolyBackground; polygon-opacity: @ciPolyOpacity; }
[ne_10m_adm = "COL"] { polygon-fill: @ciPolyBackground; polygon-opacity: @ciPolyOpacity; }
[ne_10m_adm = "ECU"] { polygon-fill: @ciPolyBackground; polygon-opacity: @ciPolyOpacity; }
[ne_10m_adm = "FJI"] { polygon-fill: @ciPolyBackground; polygon-opacity: @ciPolyOpacity; }
[ne_10m_adm …Run Code Online (Sandbox Code Playgroud) 以下javascript代码将允许在地图上的地图上创建标记,使用node.js/socket.io实时单击本地和全局.这很好,但每个添加的标记都可见.
像这个例子:http://jsfiddle.net/brettdewoody/LK35U/
现在,当第二标记已被添加到地图,我需要删除以前的标记(第一个)自动,再加入第三标记- >删除第二标记等.任何人都可以帮我理解如何做到这一点?也许和grouplayer一起?它是如何工作的?
// generate unique user id
var userId = Math.random().toString(16).substring(2,15);
var socket = io.connect('http://localhost:4000');
var doc = $(document);
// custom marker's icon styles
var tinyIcon = L.Icon.extend({
options: {
iconSize: [25, 39],
iconAnchor: [12, 36],
shadowSize: [41, 41],
shadowAnchor: [12, 38],
popupAnchor: [0, -30]
}
});
var anyIcon = new tinyIcon({ iconUrl: "assets/img/icon.png" });
var sentData = {}
var connects = {};
var markers = {};
var active = false;
// for …Run Code Online (Sandbox Code Playgroud) 有人知道mapbox或leaflet是否可以检测一个点是否位于L.Circle内?谢谢。
刚开始使用 Mapbox,通过在 locationManaged didUpdateLocations 中添加它来设法绘制一条 MGLPolyline
var shape = MGLPolyline(coordinates: &a, count: UInt(a.count))
mapView.addAnnotation(shape)
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func mapView(mapView: MGLMapView, lineWidthForPolylineAnnotation annotation: MGLPolyline) -> CGFloat { return 20.0 }
我有一个国家/地区列表,我正在尝试将地图居中并调整缩放级别以在地图中显示整个国家/地区。
使用 geocoding APIs https://api.mapbox.com/geocoding/v5/{dataset}/{query}.json?country={cc}&access_token=<your access token>,我能够得到一些不在国家中心的坐标,但至少我得到了相关的坐标,但是,返回的对象不包含任何关于缩放级别的信息。
<select id="country" name="country">
<option value="at">Austria</option>
<option value="cy">Cyprus</option>
<option value="de">Germany</option>
<option value="pt">Portugal</option>
<option value="es">Spain</option>
</select>
<div class="map" id="map"></div>
<script>
mapboxgl.accessToken = 'the_access_token';
var map = new mapboxgl.Map({
container: 'map', // container id
style: 'mapbox://styles/mapbox/streets-v8', //stylesheet location
center: [-74.50, 40], // random starting position
zoom: 9 // starting zoom level
});
// Find country
$('#country').on('change', function (e) {
countrycode = $(this).val();
country = $(this).find('option:selected').text();
console.log(countrycode, country);
$.ajax({
url: "https://api.mapbox.com/geocoding/v5/mapbox.places/"+country+".json?country="+countrycode+"&access_token="+mapboxgl.accessToken,
success: function(res) {
console.log(res);
map.easeTo({ …Run Code Online (Sandbox Code Playgroud) 我正在使用以下JavaScript代码在地图上绘制多边形:
var map = L.map('map').setView([], 10);
L.tileLayer('https://api.tiles.mapbox.com/v4/{id}/{z}/{x}/{y}.png?access_token=QA7i5Mpkd_m30IGElHziw', {
maxZoom: 18,
attribution: 'Map data © <a href="http://openstreetmap.org">OpenStreetMap</a> contributors, ' +
'<a href="http://creativecommons.org/licenses/by-sa/2.0/">CC-BY-SA</a>, ' +
'Imagery © <a href="http://mapbox.com">Mapbox</a>',
id: 'mapbox.light'
}).addTo(map);
map.doubleClickZoom.disable();
// get color depending on population density value
function getColor(d) {
return d > 3000 ? '#006400' :
d > 2500 ? '#FFEDA0' :
d > 2000 ? '#FFEDA0' :
d > 1500 ? '#c8ff58' :
d > 50 ? '#FFEDA0' :
d > 20 ? '#6fdc6f' :
d …Run Code Online (Sandbox Code Playgroud) 我有一张地图,其中起始缩放级别为 5。当用户单击一个点时,我希望地图转到该点并将缩放级别更改为 10。我正在使用 flyTo() 方法来居中点上的地图。如何更改缩放级别?
我试图从概念上理解 Deck.GL 如何渲染事物,所以我正在研究从 Lines 到 Polygons 到 GeoJson 的示例层。线条工作正常,但有些东西阻止我渲染即使是 DeckGL 在他们的例子中最简单的多边形。
这是一些有效的示例行代码
import React from "react";
import DeckGL, { LineLayer } from "deck.gl";
import { StaticMap } from "react-map-gl";
const MAPBOX_ACCESS_TOKEN = process.env.REACT_APP_MAPBOX_KEY;
// Viewport settings
const viewState = {
longitude: -122.41669,
latitude: 37.7853,
zoom: 13,
pitch: 0,
bearing: 0
};
// Data to be used by the LineLayer
const data = [
{
sourcePosition: [-91.72307036099997, 31.814196736000035],
targetPosition: [-122.41669, 37.781]
},
{
sourcePosition: [-122.41669, 37.781],
targetPosition: [-95.52274057225983, 30.131426214982195]
}
]; …Run Code Online (Sandbox Code Playgroud) 目前我正在尝试在 mapbox 提供的 android 导航 SDK 中创建导航路线。当向查询添加多个航点时,问题就开始了。(下面的查询返回响应并在地图上绘制路线)
NavigationRoute.builder()
.accessToken(Mapbox.getAccessToken())
.origin(start)
.destination(end)
.alternatives(false)
.build()
.getRoute(new Callback<DirectionsResponse>() {
@Override
public void onResponse(@NonNull Call<DirectionsResponse> call, @NonNull Response<DirectionsResponse> response) {
if (response.isSuccessful()) {
try {
assert response.body() != null;
routeodfgoh = response.body().routes().get(0);
if (navigationMapRoute != null) {
navigationMapRoute.removeRoute();
} else {
navigationMapRoute = new NavigationMapRoute(null, mapView, map);
}
//how to draw the map think map matching is work
navigationMapRoute.addRoute(routeodfgoh);
} catch (Exception ex) {
Toast.makeText(MainActivity.this, ex.toString(), Toast.LENGTH_LONG);
}
}
}
@Override
public void onFailure(Call<DirectionsResponse> …Run Code Online (Sandbox Code Playgroud) 我正在创建一个 Pop up
this.popUp = new mapboxgl.Popup({
closeButton: true,
closeOnClick: true,
anchor: 'bottom-left',
})
.setLngLat(coordinates)
.setHTML(
'<span><p>Foo: Bar
+ <img class="pop-up-image" src=.../></span>'
)
.addTo(this.map);
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的内容Pop up我定义以下
.setHTML(
'<span><p>Foo: Bar
+ <img class="pop-up-image" src=.../></span>'
)
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有没有办法将 aReact.Component或 afunctional Component作为内容传递给弹出窗口?