HI!如何检查用户是否尝试上传超过2mb的文件?我想否认这一点,并向试图这样做的用户发出错误消息.
我知道它是这样的,但是我应该将50000改为2mb?
if ($_FILES['imagefile']['size'] > 50000 )
{
die ("ERROR: Large File Size");
}
Run Code Online (Sandbox Code Playgroud) 如何在linq查询中限制扩展方法的结果数量?
var results = db.table.where(a=>a.Id > 500).Limit(10)???
Run Code Online (Sandbox Code Playgroud) 我怎么能这样的mysql查询:
SELECT id,title,timestamp,upvotes,downvotes,views FROM {$table} ORDER BY count DESC LIMIT $start_from, 20
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并基于timestamp(这是一个标准的mysql时间戳)
不仅让我的mysql,LIMIT $start_from, 20而且...
限制:
如果是在今天和一个星期之前制作的,如果是在今天和一个月之前制作的话
有任何想法吗?
在我的新网站上,我希望通过限制用户每小时最多2个帖子来减少垃圾邮件(这可能会改为允许更多,但现在只有2个)我设计了一种使用cookie的方法,但是,由于某种原因,该网站不是设置cookie,这是我的cookie代码:
$sql = "INSERT INTO mysql_table (timestamp,entry,uid,allowcomments) VALUES ('$timestamp','$entry','".rndTxt(16)."','$allowcommenting')";
$result = mysql_query($sql) or print ("Can't insert into table.<br />" . $sql . "<br />" . mysql_error());
if ($result != false) {
if(isset($_COOKIE['AnonPost']))
{
$hour = time() + 3600;
setcookie("AnonPost", "2", $hour);
}
else {
$hour = time() + 3600;
setcookie("AnonPost", "1", $hour);
}
print "<meta HTTP-EQUIV='REFRESH' content='0; url=index.php'>";
}
mysql_close();
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然后一个后来的if/else语句检查它是否存在,以及该值是什么(如果它不存在则会看到该网站正常,如果它存在,并且val = 1则它会显示一条消息,说明只有一个发布左侧,如果val = 2,他们会收到一条消息,说他们这小时已经没用了帖子.)
这适用于我的本地主机,但不在网站本身(http://aviatex14.co.uk/anonpost/)任何想法为什么?
除此之外,我知道这不是限制帖子的最佳方式,因此,任何人都可以帮我限制表单提交,或者告诉我我的cookie问题吗?
我如何解决Visual Studio Visual C#C2148错误?以下是产生错误的代码:
#define ACOUNT 2000
#define BCOUNT 9000
#define CCOUNT 195
struct s_ptx {
int pvCount[ACOUNT][BCOUNT][CCOUNT];
} ;
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这将生成VStudio 2010 Visual C(在64位以下编译)错误#C2148:错误C2148:数组的总大小不得超过0x7fffffff字节
我知道我可以动态分配pvCount 3d数组,但后来我必须做一个zillion alloc和free.我有192 gig的内存,所以我试图找到一个允许这种大小的编译器开关或选项.
编辑:我在试图简化事情时遗漏的复杂问题是ptx是一个指针,在运行时用作结构数组:
ptx *Ptx = (ptx *) calloc(10, sizeof(ptx));
for (int i = 0; i < 10; ++i)
{
Ptx->pv = (int (*)[BCOUNT][CCOUNT] ) malloc( (unsigned long) ACOUNT * BCOUNT *CCOUNT * sizeof(int));
}
for (int jav = 0; jav < 10; ++jav)
for (int j = 0; j < ACOUNT; ++j)
for …Run Code Online (Sandbox Code Playgroud) 我看了一遍,找不到这个答案.
MySQL有多少实际数字FLOAT?
我知道(想想?)它会截断超出FLOAT4字节限制的内容,但究竟是什么呢?
我必须限制要在django ORM模型对象中更新的记录数。
我试过了
CustomObject.objects.filter(column_x='XXX').update(column_y='YYY')[:10]
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但更新时不允许切片。
并且不想单独获取id并使用这些id进行更新,因为记录数非常大(100万到8000万),因此有兴趣查找数据库记录。
I know that I can set the maximum length of an input text within an EditText by using
android:maxLength="10".
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But can I also set the maximum length so that once the entire EditText is filled with text, the user can't type in anything anymore?
Something like this:
|_________________________| <-- empty EditText
|texttexttexttext_________| <-- user can still type in text
|texttexttexttexttexttextt| <-- that's it, user can't type in stuff anymore
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How could I accomplish that?
EDIT: In other words: I don't …
设置$i=0并++$i在增加时执行.我们会达到哪个号码?
请注意,它可能与Perl中的最大整数(在标题中提到的)不同,因为相邻整数之间可能存在大于的整数1.
我正在使用PostgreSQL 9.6.我有一个查询像这样:
SELECT anon_1.id AS anon_1_id, anon_1.is_valid AS anon_1_is_valid, anon_1.first_name AS anon_1_first_name, anon_1.last_name AS anon_1_last_name,
anon_1.patronymic_name AS anon_1_patronymic_name,
anon_1.experience AS anon_1_experience, anon_1.user_id AS anon_1_user_id, anon_1.rating_points as rating_points
FROM (SELECT DISTINCT ON (doctors.id) doctors.id AS id, doctors.created_at AS created_at, doctors.updated_at AS updated_at, doctors.is_valid AS is_valid, doctors.pretty_url AS pretty_url, doctors.first_name AS first_name, doctors.last_name AS last_name, doctors.patronymic_name AS patronymic_name, doctors.phone AS phone, doctors.birthday AS birthday, doctors.avatar AS avatar, doctors.experience AS experience, doctors.science_degree AS science_degree, doctors.sex_id AS sex_id, doctors.yclients_staff_id AS yclients_staff_id, doctors.user_id AS user_id, …Run Code Online (Sandbox Code Playgroud)