我试图通过检查两列"share_holder"和"distributor"的值来限制字段的选择.如果它们中的任何一个是真的,那么我想要那个选择.
在下面的版本中,我只有满足两个条件的选择('share_holder':True AND'distributor':True).
limit_choices_to={'share_holder': True, 'distributor': True}
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但是,我需要选择('share_holder':True OR''distributor':True).
我在限制formset中的可选选项时遇到了问题.我有以下模型:员工,部门,项目,项目类型,成员资格和角色.员工可以在表单集中添加/删除他们为给定部门项目播放的角色,表单应该将可选项目限制为仅属于员工所属部门的项目.
楷模:
class Department(models.Model):
name = models.CharField(max_length=20)
def __unicode__(self):
return self.name
class Employee(models.Model):
fname = models.CharField(max_length=15)
department = models.ForeignKey(Department)
def __unicode__(self):
return self.fname
class Projecttype(models.Model):
name = models.CharField(max_length=20)
def __unicode__(self):
return self.name
class Project(models.Model):
projecttype = models.ForeignKey(Projecttype)
department = models.ForeignKey(Department)
members = models.ManyToManyField(Employee, through='Membership')
def __unicode__(self):
return "%s > %s" % (self.department, self.projecttype)
class Role(models.Model):
name = models.CharField(max_length=20)
def __unicode__(self):
return self.name
class Membership(models.Model):
project = models.ForeignKey(Project, null=True)
department = models.ForeignKey(Department)
employee = models.ForeignKey(Employee)
role = models.ManyToManyField(Role, blank=True, null=True)
class …Run Code Online (Sandbox Code Playgroud) 我有几个django模型看起来像这样:
from django.contrib.sites.models import Site
class Photo(models.Model):
title = models.CharField(max_length=100)
site = models.ForeignKey(Site)
file = models.ImageField(upload_to=get_site_profile_path)
def __unicode__(self):
return self.title
class Gallery(models.Model):
name = models.CharField(max_length=40)
site = models.ForeignKey(Site)
photos = models.ManyToManyField(Photo, limit_choices_to = {'site':name} )
def __unicode__(self):
return self.name
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我正在尝试使用Gallery模型的各种乐趣limit_choices_to.我只希望管理员显示与此图库属于同一网站的照片的选项.这可能吗?
我正在运行Django 1.1并且无法获取我的ManytoManyField的"limit_choices_to"选项.
我有两个型号:
class MemberPhoto(ImageModel):
title = models.CharField(_('title'), max_length=255, blank=True, null=True)
caption = models.CharField(_('caption'), max_length=255, blank=True, null=True)
date_added = models.DateTimeField(_('date added'), default=datetime.now, editable=False)
member = models.ForeignKey(User)
def __unicode__(self):
return u'%s (%s)' % (self.member.username, self.id)
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和
class lock(models.Model):
user = models.ForeignKey(User, related_name="owner")
to_user = models.ForeignKey(User, related_name="to_user")
unlocked_photos = models.ManyToManyField(MemberPhoto, blank=True, null=True, limit_choices_to = {'member':'user'})
objects = locking_manager()
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在第二个模型中,我想确保在Django的管理员中,在多个选择字段中呈现的唯一"unlocked_photos"("MemberPhoto"对象)是具有"成员"值(用户对象)的那些与"锁定"对象的"用户"(也是一个用户对象).
我以为我已经遵循了Django文档,但它不起作用.我收到以下错误:
TemplateSyntaxError
Caught an exception while rendering: invalid input syntax for integer: "user"
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我已经尝试将"limit_choices_to"改为:
limit_choices_to = {'member':user} ---不起作用
limit_choices_to = {'member__username':'kyle'} ---这可行,但它没用,我只是手动指定用户名
我怎样才能从当前的"锁定"对象中获取用户并按此过滤MemberPhoto"member"属性? …