我正在使用 Ajax 请求来获取数据，它返回一个 Json 响应数据，该数据与我在创建 API 时将返回的数据相同。
问题是：我可以创建 Laravel 资源类并使用 (web), (API) Guards 返回该数据吗？
auth.php 文件
'guards' => [
'web' => [
'driver' => 'session',
'provider' => 'users',
],
'api' => [
'driver' => 'token',
'provider' => 'users',
'hash' => false,
],
],
我正在使用Laravel API资源，并希望将实例的所有部分都转换为数组。
在我的PreorderResource.php：
/**
* Transform the resource into an array.
*
* @param \Illuminate\Http\Request
* @return array
*/
public function toArray($request)
{
return [
'id' => $this->id,
'exception' => $this->exception,
'failed_at' => $this->failed_at,
'driver' => new DriverResource(
$this->whenLoaded('driver')
)
];
}
然后解决：
$resolved = (new PreorderResource(
$preorder->load('driver')
))->resolve();
乍一看，该方法可以解决问题，但问题是它无法递归工作。我的资源解析如下：
array:3 [
"id" => 8
"exception" => null
"failed_at" => null
"driver" => Modules\User\Transformers\DriverResource {#1359}
]
如何解析API资源以递归数组？
我正在使用 Laravel 的 API 资源将资源转换为 API 调用的数组，并且它工作正常，我是否可以在一次调用中检索多个模型的数据？至于获取用户的 JSON 数据和 Pages JSON ？或者我需要一个单独的电话。
这是我迄今为止尝试过的
//Controller
public function index(Request $request)
{
$users = User::all();
$pages = Page::all();
return new UserCollection($users);
}
//API Resource
public function toArray($request)
{
return [
'name' => $this->name,
'username' => $this->username,
'bitcoin' => $this->bitcoin,
];
}
任何帮助都将受到高度赞赏
我有简单的 Laravel 资源：
<?php
namespace App\Http\Resources;
use Illuminate\Http\Resources\Json\JsonResource;
class UserResource extends JsonResource
{
/**
* Transform the resource into an array.
*
* @param \Illuminate\Http\Request $request
* @return array
*/
public function toArray($request)
{
return [
'id' => $this->id,
'unread' => $this->unread,
'details' => new EmployeeAddressResource($this->employeeAddress),
];
}
}
这工作正常，现在我想让细节有条件：
'details' => $this
->when((auth()->user()->role == 'company'), function () {
return new EmployeeAddressResource($this->employeeAddress);
}),
它也可以正常工作，但是如何添加其他条件以返回其他资源？例如，如果角色是user我想获取资源：CompanyAddressResource
我试过这个：
'details' => $this
->when((auth()->user()->role == 'company'), function () {
return new EmployeeAddressResource($this->employeeAddress); …我正在测试一个带有分页的 API 端点返回的 Laravel 资源
public function test_showing_all_plans(): void
{
$plans = Plan::where('is_active', true)
->paginate(10);
$resource = PlansResource::collection($plans);
$this->withHeaders([
'Accept' => 'application/json',
'Content-Type' => 'application/json',
'AppKey' => 5,
])
->json('GET', '/api/customer/plans')
->assertStatus(200)
->assertExactJson([
$resource->response()->getData(true),
]);
}
所以我的问题是返回的结果不一样，因为端点的路径不等于资源的返回。
这是从端点返回的结果：
"links": {
"first": "http://www.site.local/api/customer/plans?page=1",
"last": "http://www.site.local/api/customer/plans?page=3",
"next": "http://www.site.local/api/customer/plans?page=2",
"prev": null
},
"meta": {
"current_page": 1,
"from": 1,
"last_page": 3,
"path": "http://www.site.local/api/customer/plans",
"per_page": 10,
"to": 10,
"total": 24
}
这是从资源“ $resource->response()->getData(true)”返回的代码
"links": {
"first": "http://www.site.local?page=1",
"last": "http://www.site.local?page=3",
"next": "http://www.site.local?page=2",
"prev": null
}, …How can I customize Laravel ResourceCollection meta and links information.
Links should include only prev,next and self instead of first,last,prev,next that is by default.
Meta should include pagination iformation like: current_page, total_items, items_per_page, total_pages instead of current_page, from, last_page, path, per_page, to, total.
This is how meta and links information looks now in JSON response:
"meta": {
"currentPage": 2,
"current_page": 1,
"from": 1,
"last_page": 3,
"path": "http://localhost:8000/api",
"per_page": 5,
"to": 5,
"total": 14
},
"links": {
"self": "http://localhost:8000/api",
"first": "http://localhost:8000/api?page=1", …