我有一个函数在a上执行一些流操作(特别是一个过滤器)List.
public List<String> getAndFilterNames(List<Person> people, Predicate<Person> nameFilter){
List<String> allNames = people.stream()
.map(person -> person.getName())
.filter(nameFilter)
.collect(Collectors.toList());
return allNames;
}
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我希望能够通过中间流操作(filter,distinct等),并有我的功能运行的终端操作之前执行该操作.就像是:
public List<String> getAndProcessNames(List<Person> people, <intermediate stream operation>){
List<String> allNames = people.stream()
.map(person -> person.getName())
// perform <intermediate stream operation> here
.collect(Collectors.toList());
return allNames;
}
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虽然,根据我目前的经验水平,似乎是不可能的.一些中间操作有一个参数(比如filter),有些没有(比如distinct),所以我不能设置一个能处理所有情况的参数类型...我想我可以创建一些签名,但是Function和Supplier.
即便如此,该功能界面与参数的功能需要变化...... filter需要Predicate,map需要Function,并从我的理解,是没有办法来表示一个通用的功能接口.那是对的吗?它们都没有真正的公共类或接口.
那么,到底,看来我最好的选择是公正map和collect,然后运行所需的我流操作的情况下,逐案的基础,如:
public List<String> getNames(List<Person> people){
List<String> allNames = …Run Code Online (Sandbox Code Playgroud) 我通过实现Collector接口并覆盖其方法来实现自定义收集器.Collector实现如下:
class MyCustomCollector implements Collector<Person, StringJoiner, String>{
@Override
public Supplier<StringJoiner> supplier() {
// TODO Auto-generated method stub
return () -> new StringJoiner("|");
}
@Override
public BiConsumer<StringJoiner, Person> accumulator() {
// TODO Auto-generated method stub
return (joiner,person) -> joiner.add(person.name.toUpperCase());
}
@Override
public BinaryOperator<StringJoiner> combiner() {
// TODO Auto-generated method stub
return (joiner1, joiner2) -> joiner1.merge(joiner2);
}
@Override
public Function<StringJoiner, String> finisher() {
// TODO Auto-generated method stub
return StringJoiner::toString;
}
@Override
public Set<java.util.stream.Collector.Characteristics> characteristics() {
// TODO Auto-generated method stub
return …Run Code Online (Sandbox Code Playgroud) 我有一个包含嵌套和内部类的类.在某些程序中,我使用遗留java方式中的相等运算符检查对象的空值.以下是我的代码片段:
class Outer {
Nested nested;
Nested getNested() {
return nested;
}
}
class Nested {
Inner inner;
Inner getInner() {
return inner;
}
}
class Inner {
String foo;
String getFoo() {
return foo;
}
}
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这是我如何对引用变量进行空检查:
Outer outer = new Outer();
if (outer != null && outer.nested != null && outer.nested.inner != null) {
System.out.println(outer.nested.inner.foo);
}
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我知道这也可以使用java 8的Optional类来完成,但是我没有办法在上面的特定场景中做同样的事情.有什么建议吗?
我有一个文件,其中包含JSON格式的数据.我正在逐行阅读它,每行都有1个JSON记录,所以格式确实不是问题.以下是一个示例行:
{"url": "http://ldrlongdistancerider.com/bikers_rights_motorcycle/rightsriders0163.php", "timestamp": 1257072412, "tags": ["nscensorship", "cloudmark", "network", "solutions", "content", "based", "spam", "signatures"]}
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我需要做的是计算所有重复的URL并将其打印为:
http://ldrlongdistancerider.com/bikers_rights_motorcycle/rightsriders0163.php" 1
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如何使用流来实现这一目标?顺便说一下,我需要根据时间戳过滤记录.因此,如果有人通过了一系列日期,我将不得不计算落在该范围内的网址.我已经完成了大部分工作,但这个计算部分对我来说很困惑.
这是我到目前为止所做的:
for (Path filePath : files) {
try {
Files.lines(Paths.get(filePath.toUri()))
.filter(s -> Link.parse(s).timestamp() > startSeconds)
.filter(s -> Link.parse(s).timestamp() < stopSeconds)
.forEach(s -> countMap.put(Link.parse(s).url(), 1));
} catch (IOException e) {
e.printStackTrace();
}
}
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countMap是String,Integer的HashMap
我使用Java 8实现了以下代码.
Map<String, String> coMap = getHashMap();
String newCoName = coMap.entrySet()
.stream()
.filter(coEntry -> coEntry.getValue().equals(newcoId))
.map(coEntry -> coEntry.getKey())
.collect(Collectors.joining());
String oldCoName = coMap.entrySet()
.stream()
.filter(coEntry -> coEntry.getValue().equals(oldcoId))
.map(coEntry -> coEntry.getKey())
.collect(Collectors.joining());
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现在.我想知道更好的方法,而不是重复相同的代码行两次.
在传统方式中,我已经编写了这个简单的java for循环
public String setString(String string) {
StringBuilder stringBuilder = new StringBuilder();
// This for loop I want to convert into stream.
for (char c : string.toCharArray()) {
if (Character.isSpaceChar(c))
stringBuilder.append(c);
else if (isBangla(c))
stringBuilder.append(get(c));
}
return stringBuilder.toString();
}
String get(int c) {
return keyMap.getMap((char) c); // Map<Character, String> keyMap
}
boolean isBangla(int codePoint) {
return ((codePoint >= BANGLA_CHAR_START && codePoint <= BANGLA_CHAR_END) &&
(codePoint <= BANGLA_NUMBER_START || codePoint >= BANGLA_NUMBER_END)));
}
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我试过这样的事情.
String str = string.chars()
.filter(i -> Character.isSpaceChar(i)) …Run Code Online (Sandbox Code Playgroud) 我有一段使用传统for循环编写的代码,如下所示.我想重构它以使用java 8流并删除for循环.以下代码的输出应为3,因为这是最长的连续数字列表(4,5和6)
List<Integer> weekDays = Lists.newArrayList(1, 2, 4, 5, 6);
List<Integer> consecutiveIntervals = Lists.newArrayList();
int maxConsecutiveTillNow = 1;
for (int i = 1; i < weekDays.size(); i++) {
if (weekDays.get(i) - weekDays.get(i - 1) == 1) {
maxConsecutiveTillNow++;
} else {
consecutiveIntervals.add(maxConsecutiveTillNow);
maxConsecutiveTillNow = 1;
}
}
consecutiveIntervals.add(maxConsecutiveTillNow);
System.out.println(consecutiveIntervals.stream()
.max(Integer::compareTo)
.get()
);
Run Code Online (Sandbox Code Playgroud) 我有一个对象列表,可以说形状。我想使用流来处理它们,并根据列表中的内容返回另一个对象-ShapeType。
通常,我只返回ShapeType.GENERIC,但是如果其中存在Rectangle,我想返回ShapeType.RECT。如果列表中有一个六角形,我想返回ShapeType.HEXA。当同时存在矩形和正方形时,我想返回ShapeType.HEXA。
现在,当涉及到代码时,我想要这样的东西:
public ShapeType resolveShapeType(final List<Shape> shapes) {
shapes.stream()
.filter(shape -> shape.getSideCount() == 6 || shape.getSideCount() == 4)
// I should have a stream with just rectangles and hexagons if present.
// what now?
}
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import java.time.LocalDateTime;
import java.time.ZoneId;
import java.time.ZoneOffset;
import java.time.ZonedDateTime;
import java.util.ArrayList;
import java.util.List;
import java.util.Set;
public class TimeZonesExample
{
public static void main(String[] args)
{
Set<String> allZones = ZoneId.getAvailableZoneIds();
LocalDateTime localDateTime = LocalDateTime.now();
List<String> zoneList = new ArrayList<>(allZones);
for (String s : zoneList)
{
ZoneId zoneId = ZoneId.of(s);
ZonedDateTime zoneDateTime = localDateTime.atZone(zoneId);
ZoneOffset zoneOffset = zoneDateTime.getOffset();
String out = String.format("%35s %10s%n", zoneId, zoneOffset);
System.out.printf(out);
}
}
}
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这产生了这样一个列表:
Asia/Aden +03:00
America/Cuiaba -03:00
Etc/GMT+9 -09:00
Etc/GMT+8 -08:00
Africa/Nairobi +03:00
America/Marigot -04:00 …Run Code Online (Sandbox Code Playgroud) 嗨,我在执行代码时遇到错误:
java.lang.IllegalStateException: Duplicate key ad.ecs.core.scriptengine.SiteIDAndNPI@3a75ce6f
at java.util.stream.Collectors.lambda$throwingMerger$0(Collectors.java:133)
at java.util.HashMap.merge(HashMap.java:1253)
at java.util.stream.Collectors.lambda$toMap$58(Collectors.java:1320)
at java.util.stream.ReduceOps$3ReducingSink.accept(ReduceOps.java:169)
at java.util.ArrayList$ArrayListSpliterator.forEachRemaining(ArrayList.java:1374)
at java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:481)
at java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:471)
at java.util.stream.ReduceOps$ReduceOp.evaluateSequential(ReduceOps.java:708)
at java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:234)
at java.util.stream.ReferencePipeline.collect(ReferencePipeline.java:499)
at ad.ecs.core.scriptengine.Utils.getInterfaceIDsWithSiteIDAndNPI(Utils.java:689)
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我正在尝试将我的列表分组到地图中:
public static Map<Integer, SiteIDAndNPI> getInterfaceIDsWithSiteIDAndNPI(Session session) {
@SuppressWarnings("unchecked")
List<Srvsetup> srvsetups = session.createCriteria(Srvsetup.class)
.add(Restrictions.gt("scriptinterfaceid", 0))
.list();
Map<Integer, SiteIDAndNPI> interfaceIDs = srvsetups.stream()
.collect(Collectors.toMap(srv -> srv.getScriptinterfaceid(),
srv -> getSiteIDAndNPI(srv.getId().getSiteid(), session)));
@SuppressWarnings("unchecked")
List<Facsetup> facsetups = session.createCriteria(Facsetup.class)
.add(Restrictions.gt("scriptinterfaceid", 0))
.list();
interfaceIDs.putAll(facsetups.stream()
.collect(Collectors.toMap(fac -> fac.getScriptinterfaceid(),
fac -> getSiteIDAndNPI(fac.getPlid(), session))));
return interfaceIDs;
}
public static SiteIDAndNPI getSiteIDAndNPI(int siteID, Session …Run Code Online (Sandbox Code Playgroud) java-8 ×10
java-stream ×10
java ×8
lambda ×3
collectors ×1
dictionary ×1
methods ×1
optional ×1