标签: jakarta-mail

我已经多次看到使用Android Intent Action.SEND在前台发送电子邮件的难易程度.

但是,我需要实施一个反馈表,通过电子邮件向我们发送完成后的详细信息.这并不适合Android Intent,因为用户不希望在发送之前看到生成的电子邮件.

如果我们假设smtp服务器是lol.does.thiswork并且用户名= lala,密码= po,那么是否有任何人可以使用后台发送电子邮件的示例代码.

干杯

我是Java Mail的新手.我首先想要执行程序(我通过我的老年人),看看是否一切正常.因此,当我编译该代码时,我发现错误,找不到所有Java邮件的类和包.
任何人都可以列出我的程序编译和执行所需的东西没有任何问题.我下载了"JAva Mail 1.4.5",但是没有安装文件？
我有JAva 1.6和Windows XP
请帮助........
错误:
C:>javac SMTPClient.java SMTPClient.java:2: package javax.mail does not exist import javax.mail.; ^ SMTPClient.java:3: package javax.mail.internet does not exist import javax.mail.internet.; ^ SMTPClient.java:18: cannot find symbol symbol : class Session location: class SMTPClient Session session = Session.getDefaultInstance(properties); ^ SMTPClient.java:18: cannot find symbol symbol : variable Session location: class SMTPClient Session session = Session.getDefaultInstance(properties); ^ SMTPClient.java:21: cannot find symbol symbol : class MimeMessage location: class SMTPClient MimeMessage message = new …

使用以下代码从Zimbra邮件服务器读取邮件.

String SSL_FACTORY = "javax.net.ssl.SSLSocketFactory";

Properties pop3Props = new Properties();

pop3Props.setProperty("mail.pop3.socketFactory.class", SSL_FACTORY);
pop3Props.setProperty("mail.pop3.socketFactory.fallback", "false");
pop3Props.setProperty("mail.pop3.auth", "true");
pop3Props.setProperty("mail.pop3.port",  "110");
pop3Props.setProperty("mail.pop3.socketFactory.port", "110");

URLName url = new URLName("pop3", host, 110, "",username, password);

Session session = Session.getInstance(pop3Props, null);
Store store = new POP3SSLStore(session, url);
store.connect();

但不断收到此错误

javax.mail.MessagingException: Connect failed;
  nested exception is:
    javax.net.ssl.SSLException: Unrecognized SSL message, plaintext connection?
    at com.sun.mail.pop3.POP3Store.protocolConnect(POP3Store.java:148)
    at javax.mail.Service.connect(Service.java:275)
    at javax.mail.Service.connect(Service.java:156)
    at javax.mail.Service.connect(Service.java:105)
    at VerifyMail.readPOP3(VerifyMail.java:177)
    at VerifyMail.main(VerifyMail.java:20)
Caused by: javax.net.ssl.SSLException: Unrecognized SSL message, plaintext connection?
    at com.sun.net.ssl.internal.ssl.InputRecord.handleUnknownRecord(Unknown Source)
    at com.sun.net.ssl.internal.ssl.InputRecord.read(Unknown Source) …

我正在处理与外部IMAP服务器的错误连接.我需要我的应用程序定期从此邮件服务器下载邮件.在很多情况下,我的代码已经使用javamail下载了消息并执行了message.getContent,然后处理各个正文部分(附件).在执行此操作的过程中,连接可能会丢失.

因此,我需要确保消息在执行message.getContent时没有自动标记为SEEN,这就是Javamail的行为方式,如本回复中所述:https://stackoverflow.com/a/7679091/303106

有没有办法确保未下载的邮件未标记为SEEN？

错误:

com.sun.mail.smtp.SMTPSendFailedException: 530 5.7.0 Must issue a STARTTLS command first. a5sm29349940pbw.4 - gsmtp

at com.sun.mail.smtp.SMTPTransport.issueSendCommand(SMTPTransport.java:1829)
at com.sun.mail.smtp.SMTPTransport.mailFrom(SMTPTransport.java:1368)
at com.sun.mail.smtp.SMTPTransport.sendMessage(SMTPTransport.java:886)
at javax.mail.Transport.send0(Transport.java:191)
at javax.mail.Transport.send(Transport.java:120)
at com.conceptbuild.EmailGenerator.main(EmailGenerator.java:120)

码:

package com.conceptbuild;

import java.io.UnsupportedEncodingException;
import java.util.Date;
import java.util.Properties;
import javax.mail.Address;
import javax.mail.Authenticator;
import javax.mail.Message;
import javax.mail.MessagingException;
import javax.mail.PasswordAuthentication;
import javax.mail.Session;
import javax.mail.Transport;
import javax.mail.internet.AddressException;
import javax.mail.internet.InternetAddress;
import javax.mail.internet.MimeMessage;
import javax.mail.internet.MimeMessage.RecipientType;

public class EmailGenerator {

    public EmailGenerator() {
        // TODO Auto-generated constructor stub
    }

    private class MailAuthenticator extends Authenticator {

        String username = "username";

        String …

我能够正确地从字段和主题字段获取,但即使我使用toString()方法,我仍然以对象格式获取邮件内容.

请查看以下源代码

    try {
        Session session = Session.getInstance(props, null);
        Store store = session.getStore();
        store.connect("imap.gmail.com", "mymail@gmail.com", "****");
        Folder inbox = store.getFolder("INBOX");
        inbox.open(Folder.READ_ONLY);
        Message msg = inbox.getMessage(inbox.getMessageCount());
        Address[] in = msg.getFrom();
        for (Address address : in) {
            System.out.println("FROM:" + address.toString());
        }

        Object obj = msg.getContent();
        //Multipart mp = (Multipart)obj;

        Multipart mp = (Multipart) msg.getContent();
       // MimeBodyPart part = (MimeBodyPart)mp.getBodyPart(0);
        BodyPart bp = ((Multipart) msg.getContent()).getBodyPart(0);

        // Object body = msg.getContent();

        //String value = String.valueOf(body);

        System.out.println("SENT DATE:" + msg.getSentDate());
        System.out.println("SUBJECT:" + msg.getSubject());
        System.out.println("CONTENT:" + …

我正在尝试使用JavaMail发送邮件,但获得IO异常,说访问被拒绝 请让我知道我在哪里犯了错误.我使用了java邮件和Internet API以及数据源,datahandler API.我试图作为附件发送的html文件也在适当的路径中,我拥有该文件的访问权限.以下是我的代码

import javax.activation.DataHandler;
import javax.activation.DataSource;
import javax.activation.FileDataSource;
import javax.mail.*;
import javax.mail.internet.*;
import java.util.*;

public class SendMail

{

public static void execute(String reportFileName) throws Exception

{
    String path="C:/reports";

    String[] to={"xyz@gmail.com"};
    String[] cc={"xyz@gmail.com"};
    String[] bcc={"abc@gmail.com"};

    SendMail.sendMail("xyz@gmail.com",
                        "******",
                        "smtp.gmail.com",
                        "465",
                        "true",
                        "true",
                         true,
                        "javax.net.ssl.SSLSocketFactory",
                        "false",
                         to,
                         cc,
                         bcc,
                        "Test Mail",
                        "Test Message",
                        path,
                        reportFileName);
  }

  public  static boolean sendMail(String userName,
            String passWord,
            String host,
            String port,
            String starttls,
            String auth,
            boolean debug,
            String socketFactoryClass,
            String fallback,
            String[] …

我正在尝试使用基于imap协议的java mail api连接到我的邮箱.我检查并确定我插入了正确的参数.这是我得到的以下异常:

[警告]请通过您的网络浏览器登录:https://support.google.com/mail/accounts/answer/78754(失败)

我不知道为什么会发生这种情况我在我的Gmail帐户设置中启用了imap选项.

我是我的代码:

 Properties protocol = new Properties();
 protocol.setProperty("mail.store.protocol", "imaps");

 try{
      Session session = Session.getInstance(protocol, null);
      Store store = session.getStore();
      String host = prop.getProperty("host");
      String email = prop.getProperty("username");
      String password = prop.getProperty("password");
      store.connect(host, email, password);
      Folder inbox = store.getFolder("INBOX");
      inbox.open(Folder.READ_ONLY);
      int messageCount = inbox.getMessageCount();
      model.addAttribute("msg","number of mails"+" "+messageCount);
      Message[] messages = inbox.getMessages();
      PrintWriter writer = new PrintWriter(username+".txt", "UTF-8");

      for(int i=0;i<messageCount || prop.getProperty("status").equals(status.RUNNING.toString()) ;i++ ){
          model.addAttribute("msg","Reading Mails");
          Multipart mp = (Multipart) messages[i].getContent();
          BodyPart bp …

我将Message msg分成Multipart multi1 =（Multipart）msg.getContent（）。邮件附件位于一个BodyPart中，Part part = multi1.getBodyPart（i）; 然后我要保存附件。

private void saveFile(String fileName, InputStream in) throws IOException {
File file = new File(fileName);
if (!file.exists()) {
  OutputStream out = null;
  try {
    out = new BufferedOutputStream(new FileOutputStream(file));
    in = new BufferedInputStream(in);
    byte[] buf = new byte[BUFFSIZE];
    int len;
    while ((len = in.read(buf)) > 0) {
      out.write(buf, 0, len);
    }
  } catch (FileNotFoundException e) {
    LOG.error(e.toString());
  } finally {
    // close streams
    if (in != null) { …

由于包含了以下测试,因此执行大约需要5秒钟m.saveChanges().

import org.junit.Before;
import org.junit.Test;    
import javax.mail.MessagingException;
import javax.mail.Session;
import javax.mail.internet.MimeMessage;
import java.io.IOException;
import java.util.Properties;
import static org.junit.Assert.assertEquals;   
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.when;

@Test
public void test1() throws MessagingException, IOException {
    Session s = Session.getDefaultInstance(new Properties());
    MimeMessage m = new MimeMessage(s);
    m.setContent("<b>Hello</b>", "text/html; charset=utf-8");
    m.saveChanges();
    assertEquals(m.getContent(), "<b>Hello</b>");
    assertEquals(m.getContentType(), "text/html; charset=utf-8");
}

我也用mockito嘲笑了Session,但它没有帮助:

Session s = mock(Session.class);
when(s.getProperties()).thenReturn(new Properties());

这里有什么问题？我可以嘲笑什么来加快速度？