标签: firebase-authentication

使用Firebase,我可以使用电子邮件地址注册和登录用户.但是,如果我希望该应用程序是基于用户名的.例如,您将使用"Bobzilla"而不是"Bob@mail.com"登录？

Firebase可以实现吗？

我尝试在Firebase连接的Android应用中实施Google登录.当我运行应用程序并按Google登录按钮时 - 没有任何反应.我在onActivityResult中收到此错误: Status {statusCode = DEVELOPER_ERROR,resolution = null}.

我的代码看起来像这样:

     protected void onActivityResult(int requestCode, int resultCode, Intent data) {

    if (requestCode == REQUEST_CODE_GOOGLE_LOGIN) {
        GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);

        if (result.isSuccess()){
            GoogleSignInAccount account = result.getSignInAccount();
            String emailAddres = account.getEmail();
            getGoogleQAuthToken(emailAddres);
        }
    }
}

         private void getGoogleQAuthToken(final String emailAddres){
             AsyncTask<Void,Void,String> task = new AsyncTask<Void, Void, String>() {
                 String errorMessage = null;

                 @Override
                 protected String doInBackground(Void... params) {
                     String token = null;
                     try {
                         String scope = "oauth2:profile email";
                         token = GoogleAuthUtil.getToken(MainActivity.this, …

我正在使用FirebaseAuth通过FB登录用户.这是代码:

private FirebaseAuth mAuth;
private FirebaseAuth.AuthStateListener mAuthListener;
private CallbackManager mCallbackManager;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    FacebookSdk.sdkInitialize(getApplicationContext());

    // Initialize Firebase Auth
    mAuth = FirebaseAuth.getInstance();

    mAuthListener = firebaseAuth -> {
        FirebaseUser user = firebaseAuth.getCurrentUser();
        if (user != null) {
            // User is signed in
            Log.d(TAG, "onAuthStateChanged:signed_in:" + user.getUid());
        } else {
            // User is signed out
            Log.d(TAG, "onAuthStateChanged:signed_out");
        }

        if (user != null) {
            Log.d(TAG, "User details : " + user.getDisplayName() + user.getEmail() + "\n" + user.getPhotoUrl() + …

我正在尝试使用以下方法更改/更新用户的电子邮件地址:

firebase.auth().changeEmail({oldEmail, newEmail, password}, cb)

但是我得到了...... changeEmail不是函数错误.我从旧的firebase文档中找到了这里的引用.

那么如何在3.x版本中实现呢？因为我无法在新文档中找到参考.

这里说的是我需要在java上设置Firebase:

FirebaseOptions options = new FirebaseOptions.Builder()
    .setDatabaseUrl("https://databaseName.firebaseio.com")
    .setServiceAccount(new FileInputStream("path/to/serviceAccountCredentials.json"))
    .build();
FirebaseApp.initializeApp(options);

但是我在哪里可以获得serviceAccountCredentials.json？

更新: 我发现这个文件似乎应该有这个字段,但是哪里得到这个值？

{
  "type": "",
  "project_id": "",
  "private_key_id": "",
  "private_key": "",
  "client_email": "",
  "client_id": "",
  "auth_uri": "",
  "token_uri": "",
  "auth_provider_x509_cert_url": "",
  "client_x509_cert_url": ""
}

我有一个只有PHP(没有Java,没有node.js)的共享主机方案.我需要从我的Android应用程序发送firebase ID令牌并通过PHP-JWT验证它.

我正在按照教程:验证Firebase ID令牌

它说:

"如果您的后端使用的语言没有官方的Firebase Admin SDK,您仍然可以验证ID令牌.首先,找到适合您语言的第三方JWT库.然后,验证标题,有效负载和签名ID令牌."

我找到了这个库:Firebase-PHP-JWT.在gitHub示例中; 我无法理解

$关键部分:

`$key = "example_key";` 

和

$ token部分:

`$token = array(
    "iss" => "http://example.org",
    "aud" => "http://example.com",
    "iat" => 1356999524,
    "nbf" => 1357000000
);`

我的问题:

1. 什么应该是$ key变量？
2. 为什么&token变量是一个数组？将从移动应用程序发送的令牌是一个字符串.
3. 如果有人可以发布一个用PHP-JWT验证firebase ID的完整示例,我将不胜感激.

编辑:

哦,我明白了.GitHub示例演示了如何生成JWT代码(编码)以及如何解码它.在我的情况下,我只需要解码由firebase编码的jwt.所以,我只需要使用这个代码:

$decoded = JWT::decode($jwt, $key, array('HS256'));

在此代码部分中,$ jwt是firebase ID令牌.对于$ key变量文档说:

最后,确保ID令牌由与令牌的孩子声明相对应的私钥签名.从https://www.googleapis.com/robot/v1/metadata/x509/securetoken@system.gserviceaccount.com获取公钥,并使用JWT库验证签名.使用来自该端点的响应的Cache-Control标头中的max-age值来了解何时刷新公钥.

我不明白如何将这个公钥传递给解码功能.键是这样的:

"----- BEGIN CERTIFICATE ----- \nMIIDHDCCAgSgAwIBAgIIZ36AHgMyvnQwDQYJKoZIhvcNAQEFBQAwMTEvMC0GA1UE \nAxMmc2VjdXJldG9rZW4uc3lzdGVtLmdzZXJ2aWNlYWNjb3VudC5jb20wHhcNMTcw \nMjA4MDA0NTI2WhcNMTcwMjExMDExNTI2WjAxMS8wLQYDVQQDEyZzZWN1cmV0b2tl \nbi5zeXN0ZW0uZ3NlcnZpY2VhY2NvdW50LmNvbTCCASIwDQYJKoZIhvcNAQEBBQAD \nggEPADCCAQoCggEBANBNTpiQplOYizNeLbs + r941T392wiuMWr1gSJEVykFyj7fe \nCCIhS/zrmG9jxVMK905KwceO/FNB4SK + l8GYLb559xZeJ6MFJ7QmRfL7Fjkq7GHS\N0/sOFpjX7vfKjxH5oT65Fb1 + …

我的 Flutter 应用程序使用 Firebase Auth（电话）。我一直看到错误：'Please register custom URL scheme 'com.googleusercontent.apps.602546125958-5lk04ghhdfj5xxxxxxxx'。

我已将 URL 架构添加到 info.plist 中，如下所示，但我遇到了同样的错误。

2020-04-29 20:40:05.173962-0400 Runner[395:20944] *** Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: 'Please register custom URL scheme 'com.googleusercontent.apps.602546125958-5lk04ghhdfj5xxxxxxxx' in the app's Info.plist file.'
*** First throw call stack:
(0x1889035f0 0x188625bcc 0x1887f9b28 0x10086cfa8 0x100f056a0 0x102efb3b0 0x102e921bc 0x102eeb9cc 0x102ea2a68 0x102ea4dcc 0x1888821c0 0x188881edc 0x1888815b8 0x18887c5c8 0x18887bc34 0x1929c538c 0x18c9ae22c 0x10082addc 0x188703800)
libc++abi.dylib: terminating with uncaught exception of type NSException

我是 Flutter 的新手。我有Firebase Auth/Google Auth 的问题FirebaseUser未定义代码：

FirebaseAuth _auth = FirebaseAuth.instance;
GoogleSignIn googleSignIn = GoogleSignIn();

Future<FirebaseUser> currentUser() async { // The Issue is here in the Future<>
  final GoogleSignInAccount account = await googleSignIn.signIn();
  final GoogleSignInAuthentication authentication =
      await account.authentication;

  final GoogleAuthCredential credential = GoogleAuthProvider.getCredential(
      idToken: authentication.idToken, accessToken: authentication.accessToken);

  final AuthResult authResult = await _auth.signInWithCredential(credential);
  final FirebaseUser user = authResult.user; // and here as I can't define this FirebaseUser object to return

  return user;
}

pubspec.yml

dependencies:
  flutter:
    sdk: …

升级Firebase Auth (20.0.0)电话身份验证依赖项后出错，PhoneAuthProvider.getInstance().verifyPhoneNumber()

依赖：

implementation 'com.google.firebase:firebase-auth:20.0.0'

错误：

java.lang.NoClassDefFoundError: Failed resolution of: Landroidx/browser/customtabs/CustomTabsIntent$Builder;
        at com.google.firebase.auth.internal.RecaptchaActivity.zza(com.google.firebase:firebase-auth@@20.0.0:92)
        at com.google.firebase.auth.api.internal.zzeq.zza(com.google.firebase:firebase-auth@@20.0.0:79)
        at com.google.firebase.auth.api.internal.zzeq.onPostExecute(com.google.firebase:firebase-auth@@20.0.0:88)
        at android.os.AsyncTask.finish(AsyncTask.java:755)
        at android.os.AsyncTask.access$900(AsyncTask.java:192)
        at android.os.AsyncTask$InternalHandler.handleMessage(AsyncTask.java:772)
        at android.os.Handler.dispatchMessage(Handler.java:107)
        at android.os.Looper.loop(Looper.java:237)
        at android.app.ActivityThread.main(ActivityThread.java:7948)
        at java.lang.reflect.Method.invoke(Native Method)
        at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:493)
        at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1075)
     Caused by: java.lang.ClassNotFoundException: Didn't find class "androidx.browser.customtabs.CustomTabsIntent$Builder"

谁能解释我应该为新的依赖项更改什么？有哪些新举措？

我一直在尝试使用 Firebase 身份验证来实现电话身份验证。它正在与 android 模拟器一起使用。我在模拟器中使用了一个测试号和一个实数。两者都有效。但只有测试号码在真实设备上工作，并为其他号码抛出此异常

Error is:[firebase_auth/missing-client-identifier] This request is missing a valid app identifier, 
 meaning that neither SafetyNet checks nor reCAPTCHA checks succeeded. 
 Please try again, or check the logcat for more details.

我也在 firebase 中设置了 SHA 密钥。