我在WinForms应用程序(VB.NET)上工作,它处理CRUD操作.当它加载数据时,似乎状态为"无响应",加载完成后,每件事都是正常的.
当表单从数据库中获取记录时,如何解决类似的问题?
非常感谢你.
我在下面的代码(在查询的末尾)收到以下错误消息:
警告:mysql_num_rows():提供的参数不是第28行的../view-ind-order.php中的有效MySQL结果资源
该脚本应该检索订单(从列出订单表中所有order_id行的页面),订单内容,订购用户和产品信息.我想我在哪里得到的错误是订单中有多个产品,但我不能确定我哪里出错了.(标题有会话启动命令)
<?php
$page_title = 'Order';
include ('./includes/header.html');
if ( (isset($_GET['id'])) && (is_numeric($_GET['id'])) )
{
$id = $_GET['id'];
} elseif ( (isset($_POST['id'])) && (is_numeric($_POST['id'])) )
{
$id = $_POST['id'];
} else {
echo 'This page has been accessed in error';
include ('./includes/header.html');
exit();
}
require_once ('mydatabase.php');
$query = "SELECT us.users_id, us.users_first_name, us.users_surname, us.users_business,
ord.order_id, ord.users_id, ord.total, ord.order_date,
oc.oc_id, oc.order_id, oc.products_id, oc.quantity, oc.price
prd.products_id, prd.products_name, prd.price
FROM users AS us, orders AS ord, order_contents AS oc, products AS …Run Code Online (Sandbox Code Playgroud) 好的,我有以下代码:
$array = mysql_query("SELECT artist FROM directory WHERE artist LIKE 'a%'
OR artist LIKE 'b%'
OR artist LIKE 'c%'");
$array_result= mysql_fetch_array($array);
Run Code Online (Sandbox Code Playgroud)
然后,当我尝试回显内容时,我只能回显$array_result[0];,它输出第一个项目,但如果我尝试回显,$array_result[1];我得到一个未定义的偏移量.
然而,如果我通过PHPMyAdmin运行上述查询,它将返回10个项目的列表.为什么这不被识别为10个项目的数组,允许我回显0-9?
谢谢您的帮助.
我有以下课程
#import <Foundation/Foundation.h>
#import <CoreData/CoreData.h>
@interface Bankdaten : NSManagedObject
@property (nonatomic, retain) NSString * blz;
@property (nonatomic, retain) NSString * name;
@property (nonatomic, retain) NSString * https;
@end
Run Code Online (Sandbox Code Playgroud)
和实施
#import "Bankdaten.h"
@implementation Bankdaten
@dynamic blz;
@dynamic name;
@dynamic https;
@end
Run Code Online (Sandbox Code Playgroud)
我检查了该对象的数据是否正确地由我的sqlite数据库中的相应表中的核心数据保存.
现在,我想通过执行此请求来获取特定对象:
-(Bankdaten*) ladeBankdaten:(NSString*) blz
{
NSEntityDescription *entityDescription = [NSEntityDescription entityForName:@"Bankdaten" inManagedObjectContext:moc];
NSFetchRequest *request = [[NSFetchRequest alloc] init];
[request setEntity:entityDescription];
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(blz == '%@')", blz];
[request setPredicate:predicate];
NSError *error = nil;
NSArray *array = [moc executeFetchRequest:request error:&error]; …Run Code Online (Sandbox Code Playgroud) 我获取了远程存储库,并将其存储在其中FETCH_HEAD,它有一些内容
cat .git/FETCH_HEAD
# => d11f8ef4a4735a4193633ed2fed90e441d9ce0f8 branch 'hotfix' of xxx
Run Code Online (Sandbox Code Playgroud)
但git-fetch没有显示
git show-ref FETCH_HEAD
# => nothing
Run Code Online (Sandbox Code Playgroud)
为什么?以及如何从FETCH_HEAD获取最后一次提交的SHA?
我使用FQL查询一次检索好友列表:
-(void)fetchSaveUserFriendDetails
{
NSString* query = [NSString stringWithFormat:@"SELECT uid,name,birthday_date FROM user WHERE uid IN (SELECT uid2 FROM friend WHERE uid1 = me())"];
// Set up the query parameter
NSDictionary *queryParam = [NSDictionary dictionaryWithObjectsAndKeys:
query, @"q", nil];
// Make the API request that uses FQL
[FBRequestConnection startWithGraphPath:@"/fql"
parameters:queryParam
HTTPMethod:@"GET"
completionHandler:^(FBRequestConnection *connection,
id result,
NSError *error) {
if (!error)
{
NSLog(@"result is %@",result);
NSArray *resultData = [result objectForKey:@"data"];
if ([resultData count] > 0) {
for (NSUInteger i=0; i<[resultData count] ; i++) { …Run Code Online (Sandbox Code Playgroud) 如何检查jsonResponce中从服务器发送的URL的FileExtension.
如果我的URL最后有".flv",我想传递一个方法.
例如
http://derana.lk/apps/apple/tvderana/iframe_video.php?file=SriGauthamaSambuddha_35_19673.flv
上面的链接最后有".flv".所以我知道这是一个flv视频.我想知道一种方法,以检查我的网址到底是否有.flv,以及是否已通过方法.
所以我的代码在这里返回一个Promise,因为我使用then语法,我不知道为什么会发生这种情况: - ??
fetch('someurltoAJsonFile.json')
.then(function(response) {
console.log(response.json());});
Run Code Online (Sandbox Code Playgroud) 我正在尝试执行服务器的后期请求,但使用axios不断获取CORS错误并在React中获取。
代码:
fetch('https://api/entries',
{ mode: 'no-cors',
method: 'post',
headers: {
"Content-Type":"application/octet-stream",
'Access-Control-Allow-Origin': true
},
body: JSON.stringify({
"KEY":"VALUE"
})
})
.then((response) => {
console.log(response)
})
.catch(err => console.log(err))
Run Code Online (Sandbox Code Playgroud)
要么
axios({
method: 'post',
url: 'https://api/entries',
headers: {
"Content-Type":"application/octet-stream",
'Access-Control-Allow-Origin': true
},
data: {
"KEY":"VALUE"
}
})
.then(response => {
console.log(response);
})
.catch(err => console.log(err));
Run Code Online (Sandbox Code Playgroud)
axios控制台响应
Access to XMLHttpRequest at 'https://api/entries' from origin 'http://localhost:3000' has been blocked by CORS policy: Response to preflight request doesn't pass access control check: It does not have …Run Code Online (Sandbox Code Playgroud) 我正在函数中进行API调用以获取一些数据。然后,我需要根据第一个调用中的特定值,对返回的每个数据项进行多个API调用。我在渲染状态时遇到问题,在渲染期间不存在从多个promise添加的值。
到目前为止,我有这样的事情:
fetch(url)
.then(resp => resp.json())
.then(data => {
//do some calculations and populate new array and return it
})
.then(data => {
const newData = [...data];
Promise.all(functionWhichReturnsArrayOfPromises).then(el => {
// more calculation
newData.push(el.someValue);
})
return newData;
})
.then(data => this.setState({data: data}))
Run Code Online (Sandbox Code Playgroud)
返回promise数组的函数如下所示:
fetchMoreData(arr) {
const promises = arr.map(el => {
return fetch(someUrl)
.then(data => data.json())
.then(data => data)
})
return promises;
}
Run Code Online (Sandbox Code Playgroud)
我认为将Promise.all链接到另一个Promise不好,是否有推荐且更优雅的方式来实现此目的?