标签: ebean

我想知道是否有可能使用@PrePersist,并@PreUpdate与Ebean玩吧!2.0.如果是这样,该功能如何激活.我已经看到一个月前有一个拉取请求添加此功能,但我无法在Play 2.0上进行此操作.

谢谢

我正在使用PlayFramework,我真的很喜欢它.当我想从表中获取数据时,例如我有一个user表,我使用以下语法:

List<User> users = User.find.where().eq("email", email).findList();

我的问题是,当我得到用户对象时,我有一个id列.使用该id值,我可以映射到其他表,并且id这些表的's'可以映射到更多的表,因此跨多个表连接的基本概念.是否有任何示例或地方我可以阅读它描述如何使用上述语法实现它？

我试图找到自己而不能,只有这样我才能想到它是使用直接sql与准备好的语句,我宁愿不做.

我有这个枚举:

public enum DocumentTypes {
    PDF("PDF Document"), JPG("Image files (JPG)"), DOC("Microsoft Word documents");

    private final String displayName;

    DocumentTypes(final String display) {
        this.displayName = display;
    }

    @Override
    public String toString() {
        return this.displayName;
    }
}

这样的模型:

@Entity
@Table(name = "documents")
public class Document extends Model {
    @Id
    public Long id;

    @Constraints.Required
    @Formats.NonEmpty
    @Enumerated(EnumType.STRING)
    @Column(length=20, nullable=false)
    public DocumentTypes type;

    @Constraints.Required
    @Formats.NonEmpty
    @Column(nullable=false)
    public String document;
}

我在我的控制器中使用它来匹配枚举:

DynamicForm form = form().bindFromRequest();
// ...
Document doc = new Document();
doc.type = DocumentTypes.valueOf(form.field("type").value());
doc.save(); …

我在Play Framework 2中使用Ebean,有时会出现类似的OptimisticLockException:

play.core.ActionInvoker$$anonfun$receive$1$$anon$1: Execution exception [[OptimisticLockException: Data has changed. updated [0] rows sql[update manager set modification_time=?, session_id=?, expiration_date=? where id=? and rating=? and creation_time=? and modification_time=? and name=? and surname=? and login=? and password_hash=? and email=? and session_id=? and expiration_date=?] bind[null]]]

当少数演员开始访问数据库时会发生这种情况

那么,Manager类是:

public class Manager extends Model {
@Getter @Setter
Long id;

@Getter @Setter
private String name;

@Getter @Setter
private String surname;

@Column(unique = true)
@Getter @Setter
private String login;

@Getter @Setter
private String passwordHash;

@Getter @Setter
private …

我有一个想要修改db中的行的play framework 2.0.4应用程序.

我需要将db中的'less'消息更新为"打开"状态(读取消息)我就像下面这样做了

    String sql = " UPDATE message  SET opened = true, opened_date = now() "
            +" WHERE id_profile_to = :id1 AND id_profile_from = :id2 AND opened IS NOT true";
    SqlUpdate update = Ebean.createSqlUpdate(sql);
    update.setParameter("id1", myProfileId);
    update.setParameter("id2", conversationProfileId);        
    int modifiedCount = update.execute();

我修改了postgresql来记录所有查询.

modifiedCount是修改行的实际数量 - 但查询是在事务中.在db中完成查询之后会有ROLLBACK - 因此不会进行UPDATE.我试图将db更改为H2 - 结果相同.

这是来自postgres审核日志的查询

2012-12-18 00:21:17 CET :  S_1: BEGIN
2012-12-18 00:21:17 CET :  <unnamed>:  UPDATE message  SET opened = true, opened_date = now()  WHERE id_profile_to = $1 AND id_profile_from = …

我正在尝试使用Ebean在Play中创建以下类:

public class BaseModel extends Model {

    @Column(name = "created_at")
    public Date createdAt;

    @Column(name = "updated_at")
    public Date updatedAt;

    @PrePersist
    public void createdAt() {
        this.createdAt = this.updatedAt = new Date();
    }

    @PreUpdate
    public void updatedAt() {
        this.updatedAt = new Date();
    }

}

它编译没问题,但是当我用我的实体bean子类化这个类时(所以每个都会插入时间戳进行创建和更新)我在尝试点击应用程序时遇到以下异常:

play.api.UnexpectedException: Unexpected exception[PersistenceException: Error with [models.InventoryItem] I believe it is not enhanced but it's superClass [class models.BaseModel] is? (You are not allowed to mix enhancement in a single inheritance hierarchy)]
        at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1$$anonfun$1.apply(ApplicationProvider.scala:150) ~[play_2.10.jar:2.1.4]
        at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1$$anonfun$1.apply(ApplicationProvider.scala:114) ~[play_2.10.jar:2.1.4]
        at …

运行Play Framework 2.2.x(Java)项目时出现以下错误:

Configuration error
Cannot register class [models.SomeClass] in Ebean server

浏览器中显示的错误消息将我指向我的行ebean.default="models.*",application.conf控制台告诉我我的java.lang.VerifyError: Bad type on operand stack一个方法.对于这种情况发生的方法没有什么特别之处,现在已经发生了一些方法.

我发现使用静态方法可以避免错误:即替换someObject.doJob()为SomeClass.doJob(someObject).我已经使用过这个hack,它可以工作,但是我不是很高兴我的所有方法都应该是静态的.

有没有人遇到同样的问题,并找到了解决方法(不使方法静态)？

最近升级到Play 2.4,我还在学习所有的小怪癖等等.我正试图让我的索引页面正常工作而且我很难接受它,而且我知道它很小,我很想念.这是错误

CreationException: Unable to create injector, see the following errors:

1) Error in custom provider, Configuration error: Configuration error[Cannot connect to database [default]]
  while locating play.api.db.DBApiProvider
  while locating play.api.db.DBApi
    for parameter 0 at play.db.DefaultDBApi.<init>(DefaultDBApi.java:28)
  at play.db.DefaultDBApi.class(DefaultDBApi.java:28)
  while locating play.db.DefaultDBApi
  while locating play.db.DBApi
    for field at play.db.DBModule$NamedDatabaseProvider.dbApi(DBModule.java:61)
  while locating play.db.DBModule$NamedDatabaseProvider
  at com.google.inject.util.Providers$GuicifiedProviderWithDependencies.initialize(Providers.java:149)
  at play.db.DBModule.bindings(DBModule.java:40):

和我的配置信息(是的,mysql的端口号是正确的)

application.conf

db.default.driver=com.mysql.jdbc.Driver
db.default.url="jdbc:mysql:localhost:33060/coffee_bean"
db.default.username=
db.default.password=""
ebean.default = ["models.*"]

主控制器

public Result index() {
        ObjectNode response = Json.newObject();
        Configuration config = Play.application().configuration();
        response.put(config.getString("coffee.bean.message.key"),config.getString("coffee.bean.success.message"));
        response.put(config.getString("version"), config.getString("coffee.bean.version"));

        return …

我不想在application.conf文件中定义默认数据库配置.相反,我想以编程方式构造默认的EbeanServer并将其自己注入DAO.

我遇到的问题是,如果我为EbeanServer提供程序创建一个guice绑定而没有在application.conf文件中定义任何配置,则播放错误,说它无法找到默认配置.

这是我的代码:

public class EbeanServerProvider implements Provider<EbeanServer> {

    final Logger.ALogger log = Logger.of(this.getClass());

    @Override
    public EbeanServer get() {

        ServerConfig serverConfig = new ServerConfig();
        DataSourceConfig dataSourceConfig = new DataSourceConfig();
        ClassLoader classLoader = Thread.currentThread().getContextClassLoader();

        Config dbConfig = ConfigFactory.load(classLoader,"env/default.conf");

        /* Read the config files */
        final String DB_DRIVER   = dbConfig.getString("db.default.driver");
        final String DB_URL      = dbConfig.getString("db.default.url");
        final String DB_USERNAME = dbConfig.getString("db.default.username");
        final String DB_PASSWORD = dbConfig.getString("db.default.password");

        log.debug("{}",DB_DRIVER);
        log.debug("{}",DB_URL);
        log.debug("{}",DB_USERNAME);
        log.debug("{}",DB_PASSWORD);
        /* Load the database driver */
        dataSourceConfig.setDriver(DB_DRIVER);
        try{
            Class.forName(DB_DRIVER).newInstance(); …

我在尝试搜索列表中的特定Java对象时遇到了问题.
实际上我得到了我想为另一个Java类工作的搜索功能.现在我尝试了另一个但不是返回结果列表我得到一个NullPointerException.

这就是我的功能:

 public static List<Customer> searchByEverything(String keyword){
    List<Customer> customerList = find.all(); //Using java Ebean

    System.out.println(keyword); //Check if keyword is not empty
    System.out.println(customerList); //Check if list is not empty

    Predicate<Customer> customerPredicate = u -> u.name.toLowerCase().contains(keyword.toLowerCase());

    try{
        return customerList.stream().filter(customerPredicate).collect(Collectors.toList());
    }catch (Exception e){
        e.printStackTrace();
    }

这是来自Exception e的strack trace:

java.lang.NullPointerException
at models.Customer.lambda$searchByEverything$2(Customer.java:174)
at java.util.stream.ReferencePipeline$2$1.accept(ReferencePipeline.java:174)
at java.util.ArrayList$Itr.forEachRemaining(ArrayList.java:891)
at java.util.Spliterators$IteratorSpliterator.forEachRemaining(Spliterators.java:1801)
at java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:481)
at java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:471)
at java.util.stream.ReduceOps$ReduceOp.evaluateSequential(ReduceOps.java:708)
at java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:234)
at java.util.stream.ReferencePipeline.collect(ReferencePipeline.java:499)
at models.Customer.searchByEverything(Customer.java:179)
at controllers.Application.searchCustomers(Application.java:262)
at router.Routes$$anonfun$routes$1$$anonfun$applyOrElse$17$$anonfun$apply$17.apply(Routes.scala:479)
at router.Routes$$anonfun$routes$1$$anonfun$applyOrElse$17$$anonfun$apply$17.apply(Routes.scala:479)
at play.core.routing.HandlerInvokerFactory$$anon$4.resultCall(HandlerInvoker.scala:157)
at play.core.routing.HandlerInvokerFactory$$anon$4.resultCall(HandlerInvoker.scala:156)
at play.core.routing.HandlerInvokerFactory$JavaActionInvokerFactory$$anon$14$$anon$3$$anon$1.invocation(HandlerInvoker.scala:136)
at …