我需要将Oauth设置为我将要开发的PHP项目的一部分.
为此,我跑了;
sudo pecl install oauth
这完成了OK,它指示我添加extension=oauth.so到我的php.ini文件中,我做了.
然后我重新启动Apache并运行
php -i | grep oauth
要查看它是否被PHP拾取,它似乎就像我得到的结果一样;
source version => $Id: oauth.c 325799 2012-05-24 21:07:51Z jawed $
但是当我运行(CodeIgniter)应用程序时,我得到错误;
Fatal error: Class 'Oauth' not found in...
我错过了一个至关重要的步骤吗？
好吧，我试图弄清楚如何使用insert_batch
我正在尝试这样的事情
function checkboxes($data,$category)
{
$insert=array(
'story'=>$data
'category'=>$category
);
$this->db->insert_batch('stories_to_categories',$insert);
}
对于$ data我有数组，可以有值和键的范围
(
[0] => 1
[1] => 6
[2] => 14
[3] => 15
[4] => 18
)
对于类别，我将只有一个值，例如2
我尝试达到我的习惯
story category
------------------------
1 2
6 2
14 2
15 2
18 2
有人可以帮助我，我很痛苦！
我正在尝试使用jQuery和ajax函数上传图像,如何获取图像文件的所有细节,就像我们使用的php一样 $_FILE()
这是我的代码
JS
$("#uploadimg" ).click(function() {
$( "#file" ).click();
});
$( "#file" ).change(function(e) {
var file=$('#file').val();
alert(file);
die();
e.preventDefault();
$.ajax({
url:'http://localhost/JSG/blog/uploadimg',
secureuri:false,
type: "POST",
fileElementId:'image',
dataType: 'text',
data:{ file: file },
cache: true,
success: function (data){
alert(data);
console.log(data);
},
});
});
调节器
public function uploadimg()
{
$var = $_POST['file'];
print_r($var);
if($this->input->post('file')) {
$config['upload_path'] = 'upload';
$config['file_name'] = $var;
$config['overwrite'] = 'TRUE';
$config["allowed_types"] = 'jpg|jpeg|png|gif';
$config["max_size"] = '1024';
$config["max_width"] = '400';
$config["max_height"] = '400';
$this->load->library('upload', $config);
if(!$this->upload->do_upload()) {
$this->data['error'] = …我有要求,我可以在新的添加功能中进行唯一值的验证
$this->form_validation->set_rules('email','Email','required|valid_email||is_unique[users.Email]');
它的工作,但在编辑功能,它不工作..我有写回调函数来检查唯一的电子邮件.这是我在编辑功能中编写的代码
$this->form_validation->set_rules('email','Email','required|valid_email|callback_check_email');
function check_username($email)
{
$return_value = $this->user_model->check_email($email);
if ($return_value)
{
$this->form_validation->set_message('email_check', 'Sorry, This username is already used by another user please select another one');
return FALSE;
}
else
{
return TRUE;
}
}
和user_model
function check_mail($email)
{
$sql = "SELECT users.Email
FROM users
WHERE
$email = users.Email
";
$result = $this->db->query($sql)->result_array();
return $result;
}
我无法验证唯一的电子邮件
我想使用codeigniter和mysql动态创建动态树菜单,我对css和jquery的树结构没有任何问题.
我有两个表,表组织和组织类:
(id, parent_org_id, org_class_id, title)
(1, 0, 1, Company Name)
(2, 0, 1, Company2 Name)
(3, 1, 2, Departement Name)
(4, 2, 2, Departement2 Name)
(5, 4, 3, Division2 Name)
(id, org_class_title, order_no)
(1, 0, 1)
(2, 0, 2)
(3, 1, 3)
这是我的功能:
$str ='';
$lastListLevel=0;
$firstRow=true;
foreach($organization->result() as $row){
$currentListLevel=$row->parent_organization_id -1 ; // minus one to correct level to Level 0
$differenceLevel=$currentListLevel-$lastListLevel;
$rootLevel=false;
if($differenceLevel==0){
if($firstRow){
$firstRow=false;
}else{
$str .='</li>';
}
$str .='<li>';
}elseif($differenceLevel>0){
for($j=0;$j<$differenceLevel;$j++){
$str .='<ul><li>';
}
}elseif($differenceLevel<0){ …在我的codeigniter视图中,我有一个包含选择框和文本框的div.还有一个"添加更多"按钮.我的任务是在单击添加更多按钮时复制整个div,当我提交表单时,我需要从原始div和重复div获取字段值.我怎么能做到这一点？我尝试使用jquery clone方法复制div .但找不到解决方案.
这是我到目前为止尝试的代码:
<?php echo form_open("vehicle/addparts");?>
<div class="row" id="addparts">
<div class="col-md-6">
<div class="form-group">
<select class="form-control input-medium" name="parts">
<option value="">select disabled>Select Parts</option>
<option value="a">A</option>
<option value="b">B</option>
<option value="c">C</option>
</select>
</div>
</div>
<div class="col-md-6">
<div class="form-group">
<label class="control-label">Quantity</label>
<input type="text" name="partsquantity" id="partsquantity">
</div>
</div>
</div>
<div class="row">
<input type="button" name="addmore" value="Add More" onClick="duplicate">
</div>
<?php echo form_close();?>
Javascript:
<script>
function duplicate() {
var original = document.getElementById('addparts');
var clone = original.cloneNode(true);
clone.id = "duplic";
document.bodey.append(clone);
}
</script>
我创建了一个登录系统，但是每次我设置一个if语句时，当我输入正确的密码时，它都会循环回到登录页面。我需要控制器中的index函数，list_employee函数和View_employee函数，以在用户直接访问登录页面时将其重定向到登录页面，但如果他们输入正确的密码，则可以转到该页面。
user_authentication控制器
<?php
session_start(); //we need to start session in order to access it through CI
Class User_Authentication extends CI_Controller {
public function __construct() {
parent::__construct();
// Load form helper library
$this->load->helper('form');
// Load form validation library
$this->load->library('form_validation');
// Load session library
$this->load->library('session');
// Load database
$this->load->model('login_database');
}
// Show login page
public function user_login_show() {
$this->load->view('login_form');
}
// Show registration page
public function user_registration_show() {
$this->load->view('registration_form');
}
// Validate and store registration data in database
public function new_user_registration() { …Your view folder path does not appear to be set correctly. Please open the following file and correct this: index.php我收到这个错误,我不知道有什么问题,我从官方网站下载了rc3(发布候选人3),解压缩它,添加了资产文件夹和帮助,当我运行应用程序时,我收到了错误Your view folder path does not appear to be set correctly. Please open the following file and correct this: index.php,这是我的index.php文件代码,图像显示了文件夹结构
// index.php code
<?php
/**
* CodeIgniter
*
* An open source application development framework for PHP
*
* This content is released under the MIT License (MIT)
*
* Copyright (c) 2014 - 2015, British …我正在为我的项目使用HMVC Codeigniter模式.在我的项目中,我需要在表单上设置值,其中输入类型的字段是file.So,我觉得很有帮助我解决这个问题的人.
我的控制器是test.php
<?php
class Test extends Controller{
function __construct(){
parent::__construct();
}
function index(){
redirect('test/form');
}
function form(){
$this->load->library('form_validation');
$this->load->helper('url');
$this->form_validation->set_rules('fname','First Name','required|trim');
$this->form_validation->set_rules('mname','Middle Name','required|trim');
$this->form_validation->set_rules('lname','Last Name','required|trim');
if (empty($_FILES['userfile']['name']))
{
$this->form_validation->set_rules('userfile', 'Attach Your File', 'required');
}
if($this->form_validation->run($this)){
$_SESSION['msg']="Your form has been submitted succesfully!!";
redirect('test/form');
}
else
{
$_SESSION['err']="Opp! There was some wrong to fill up a form so try again!!!";
redirect('test/form');
}
}
$data['pgtitle']='Test';
$this->load->view('test',$data);
}
}
我的视图文件是test.php
<form action="<?php echo site_url()?>test/form" method="post" enctype="multipart/form-data" onsubmit="return confirm('Do you really want to submit …我正在使用codeigniter而我正在尝试将以下查询转换为dbforge样式查询,我该怎么办？
create table filter (
filterid int primary key auto_increment,
filtername varchar(50) not null,
categoryid int not null,
isactive tinyint not null,
sequence int not null,
foreign key(categoryid) references category(id));
codeigniter ×10
php ×9
jquery ×2
mysql ×2
ajax ×1
javascript ×1
oauth ×1
pecl ×1
sql ×1
sql-server ×1