标签: codeigniter

codeigniter中$ _SERVER的等价是什么？

我有一个数组有多个对象(比如3个对象),每个对象有3个"键 - 值"对.

$PredefinedResult 是这样的:

[
    {
        "EffectiveStatusId":0,
        "EffectiveStatus":"abc",
        "RecordCount":0
    },
    {
        "EffectiveStatusId":0,
        "EffectiveStatus":"def",
        "RecordCount":0
    },
    {
        "EffectiveStatusId":0,
        "EffectiveStatus":"ghi",
        "RecordCount":0
    }
]

我有另一个对象数组,其名称为$MainResult:

[
    {
        "EffectiveStatusId":1,
        "EffectiveStatus":"abc",
        "RecordCount":7
    },
    {
        "EffectiveStatusId":6,
        "EffectiveStatus":"def",
        "RecordCount":91
    }
]

预期结果 :

我想用对象替换里面的类似$PredefinedResult对象,$MainResult并希望得到如下结果:

[
    {
        "EffectiveStatusId":1,
        "EffectiveStatus":"abc",
        "RecordCount":7
    },
    {
        "EffectiveStatusId":6,
        "EffectiveStatus":"def",
        "RecordCount":91
    },
    {
         "EffectiveStatusId":0,
         "EffectiveStatus":"ghi",
         "RecordCount":0
    }
]

我尝试了什么:

我试过这个代码,但它没有给我想要的结果.

$FinalResult = array_replace($PredefineResult,$MainResult);

任何人都可以帮助我如何获得上面提到的预期结果？

$q = $this->db->select('
             books.title,
             reserved_books.id,
             reserved_books.isbn, 
             reserved_books.price,
             reserved_books.item_sold,
             reserved_books.date_sold,
             reserved_books.total_amount
            ')
        ->from('reserved_books')
        ->join('books','reserved_books.isbn= books.isbn')
        ->limit($limit,$offset);

我怎么能在我的查询中使用distinct？reserved_books.isbn是唯一的.

我正在尝试学习Codeigniter并了解到目前为止的基础知识,但是当我尝试测试时,似乎缓存正在阻碍.通常,当我在localhost上测试时,我做了一个更改并立即在浏览器中看到它,但是使用Codeigniter,似乎我需要等待~1分钟才能在浏览器中看到更改.有没有办法普遍禁用Codeigniter缓存,以便在发生变化时立即发生？

伙计们.我正在使用codeigniter.我使用.htaccess从我的url中删除'index.php',并将"Allow from all"添加到我的default.conf中.'index.php'已成功删除,网站正在运行.但是自上次更新apache以来,.htacess停止了工作,并且在URL中需要'index.php'.这是我新更新的000-default.conf.

<VirtualHost *:80>
    # The ServerName directive sets the request scheme, hostname and port that
    # the server uses to identify itself. This is used when creating
    # redirection URLs. In the context of virtual hosts, the ServerName
    # specifies what hostname must appear in the request's Host: header to
    # match this virtual host. For the default virtual host (this file) this
    # value is not decisive as it is used as a last resort host regardless. …

我在这篇文章中尝试使用动态基本URL:

在CodeIgniter中设置动态基本URL

但我曾经使用http,但现在,我想改为https,我怎么能这样做？谢谢.

我遵循数据库架构 -

现在部门,年份和部门表已经填满了信息.

我现在需要插入学生数据.学生数据将从xls文件导入(导入和解析部分已完成).正如您在架构中看到的那样,表中的列student_data引用year_id,department_di和division_id.因此,在插入时我需要他们的ID字段,因为xls具有各自的名称值.

所以我要根据每个学生的列值来获取相应的ID.因此,这引入了3个查询,用于在学生表中插入一条记录.像这样 -

forloop(...):
     $studentData = new Entities\StudentData();

    $year =  $this->em->getRepository("Entities\Year")->findBy(array('year_name' => $this->year[$i]));
    $department =  $this->em->getRepository("Entities\Department")->findBy(array('department_name' => $this->branch[$i]));
    $division =  $this->em->getRepository("Entities\Division")->findBy(array('division_name'=>$this->division[$i]));

    $studentData->setYear($year[0]);
    $studentData->setDepartment($department[0]);
    $studentData->setDivision($division[0]);

    //other data
    .
    .
    .
    .
    .
    $this->em->persist($studentData);

endforloop();   

$this->em->flush();
$this->em->clear();

正如你所看到的,我将为每个部门,年份和部门获得ID循环.假设我正在导入100个学生列表,因此它最终会运行300个查询来获取这3个ID字段.

我可以在插入数据时直接从他们的名字中获取年份,部门和部门的ID吗？我是学说的新手,我不知道如何去做.

更新 如果问题不清楚,请告诉我.我可以用更多细节更新它或重组它.

我正在制作一个网页,这是一个单页网站,通过CodeIgniter中的Ajax与服务器进行交互.一般编码具有以下类型:

controller (user.php):

public function get_user_content() {
    $id = $this->input->post('id');
    $hits = $this->user_model->user_data($id);
    $s = '';    
    foreach ($hits as $hit) {
       $s .= $hit->name;
       $s .= $hit->age;
    }
    echo $s;
}

model(user_model.php):

function user_data($id) {
   //do sql operation
   return $query->result();
}

视图:

...
...
<a href="#" id="23" class="user-data">Click here for user details</a>
...
...

JavaScript的:

('.user-data').click(get_user_data);
....
....
function get_user_data(response) {
    return $.ajax({
        type: "POST",
        url:  "<?php echo base_url();?>index.php/user/get_user_content",
        data: { id: this.id },
        success: function(response) {
            $("#somediv").append(response); …

我正在使用codeigniter会话来存储用户登录.当用户在多个选项卡中打开时,在一个选项卡中注销时,我希望在用户访问其他选项卡时自动刷新页面.这可能吗？

使用带有我的codeigniter应用程序的SMTP时,我无法收到要发送的电子邮件.

在SO上有很多类似的问题,但没有一个可以解决我的问题,所以这就是为什么我要再问一次.

这是我得到的错误:

hello: 

The following SMTP error was encountered:
Failed to send AUTH LOGIN command. Error:

from: 

The following SMTP error was encountered:

to: 

The following SMTP error was encountered:

data: 

The following SMTP error was encountered:

The following SMTP error was encountered:
Unable to send email using PHP SMTP. Your server might not be configured to send mail using this method.

User-Agent: CodeIgniter
Date: Tue, 22 Apr 2014 22:54:12 -0400
From: 
Return-Path: 
To: myemail@gmail.com
Subject: =?utf-8?Q?Request_from_C&J_Builders_Contact_form?=
Reply-To: "donotreply@C&JBuilders.us" …