标签: case

我的MySQL查询有问题,我正在使用这个案例给它一个排序顺序.订单取决于序列号.

我的查询是:

    SELECT DISTINCT id, price, itemnr, itemnr_ori, link, name, setinfo 
CASE WHEN itemnr_ori LIKE '%-%-s%' THEN 0 WHEN itemnr_ori LIKE 'z-%-%' THEN 1
 WHEN itemnr_ori LIKE 'ak-%' THEN 2
 WHEN itemnr_ori LIKE 'fdc-%' THEN 3
 WHEN itemnr_ori LIKE 'max-%' THEN 4
 ELSE 5 END
 AS sort_order FROM items2 WHERE category1 = 'Overige' AND category2 = 'Afrikaanse Overige' ORDER BY sort_order ASC, price ASC, itemnr_ori ASC

我收到这个错误:

#1064 - You have an error in your SQL syntax; check the manual …

我试图编写一个程序来帮助我找到给定角度的三角函数值。下面是程序，

    #include<iostream>
#include<cmath>
using namespace std;

void convert(char type);

int main()
{
    char ch;


    cout<<"Enter what angle value u want to calculate: 'c' for cos, 's' for sine and 't' for tan: ",cin>>ch;

    convert(ch);

    return 0;
}

void convert(char type)
{
    float angle;
    double num;
    switch (type)
    {
        case 'C' || 'c':
            cout<<"Enter angle value to calculate cos equivalent: ",cin>>angle;
            num = cos(angle);
            break;
        case 's' || 'S':
            cout<<"Enter angle value to calculate sin equivalent: ",cin>>angle;
            num = sin(angle);
            break; …

我想在我的代码中创建一个switch语句,其代码遍及大范围的整数(1-15000),分为3个部分:1-5000,5001-10000,10001-15000.

我试过这样一次:

switch(number) {
    case 1 ... 1000: (statement here); 

这给了我一个关于"......"的语法错误 - "预期的a:".

然后我尝试了:

switch (number) {
case 1:
case 5000:
    (statement);
    break;

这个方法确实编译但是没有按预期工作,对于没有明确列出的案例的错误答案.

在网上找不到任何其他建议.有人可以帮忙吗？

我有一个查询，它返回按时间分组的数据，如下所示：

我需要从 13 点开始重新排序，并在 12:30 结束，如下所示：

有任何想法吗？非常感谢！

我的表有以下列:

|blo|NotionalCurrency|Notional|Premiumcurrency|Basecurrency|Termcurrency|StructureName|Basemarketprice|Termmarketpriceprecent |Termmarketprice|

我想从这些获得blo,货币和价格.下面是我的SQL:

   select blo.opt,
  case
  when opt.premiumcurrency is not null and opt.structurename is not null  then currency = opt.premiumcurrency
      case
      when opt.notionalcurrency = opt.basecurrency and opt.premiumcurrency = opt.termcurrency then price = opt.termmarketpricepercent / opt.notional
      else
          case
             when opt.premiumcurrency = opt.basecurrency then price = opt.basemarketprice /100
             else
             price = opt.termmarketpriceprecent /100
             end
       end
   when price = 0 then price = 0.000001
   end
FROM interface opt
WHERE opt.notionalcurrency = opt.basecurrency and opt.premiumcurrency = opt.termcurrency;

但我得到错误: ORA-00905: missing keyword

基本上,下面的逻辑应该用于获取/派生SQL以获得三列:Blo,货币和价格:

If …

我们有4个地区: a b c d

我们想把数字放在这些地区.

如何仅使用switch语句执行此操作:

 the number divisible by 10 and divisible by 7 ?n region a
 the number divisible by 10 but not divisible by 7 ?n region b
 the number not divisible by 10 but divisible by 7 ?n region c
 the number not divisible by 10 and divisible by 7 ?n region d

例如,如果:

input 770 out put is a

input 200 output b

input 154 output c

是否可以在开关盒环路中放置一个功能？因为我试过这个只是为了探索更多这个循环.虽然我尝试了其他方法,但我仍然存在问题.谁能帮我？

#include <stdio.h>
int main(void)

{

    int choice;

    switch(choice);
    {
    case 1:
    {
           int GetData()
           {
           int num;
           printf("Enter the amount of change: ");
           scanf("%d%*c", &num);

           return (num);

           }
           int getChange (int change,int fifty,int twenty,int ten,int five)
           {
                 int num = change;

                 fifty = num/50;
                 num %= 50;
                 twenty = num/20;
                 num %= 20;
                 ten = num/10;
                 num %= 10;
                 five = num/5;
                 num %= 5;

                 return (fifty, twenty, ten, five);
           }
           int main()
           {
                 int change, fifty, twenty, ten, …