我想要来自networkimageview的Bitmap.这是我的代码和
String url="https://graph.facebook.com/"+u_id+"/picture";
mNetworkImageView = (NetworkImageView) findViewById(R.id.networkImageView);
mImageLoader = MySingletonClass.getInstance(this).getImageLoader();
mNetworkImageView.setImageUrl(url, mImageLoader);
在此之后,我想要来自networkimageview的位图.怎么弄明白？
我正在尝试使用 volley 将 Json 发布到我的宁静 API，但它不起作用。到目前为止，我已经通过 Chrome 上的 Advance rest 客户端应用程序发送一个 json 有效负载来测试我的 Web 服务，它返回一个 json 响应......但是当我用 Volley 尝试它时，它返回 onErrorResponse。请有人告诉我如何解决这个问题，在此先感谢。
JSON 有效载荷：
{"country":"isreal","mobile":"009988778"}
代码
private void processLogin() {
showProgressDialog();
JsonObjectRequest jsonObjReq = new JsonObjectRequest(Method.POST,
Const.LOGIN_URL, null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
Log.i("JSON response", "JSON Posting" + response.toString());
hideProgessDialog();
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError volleyError) {
VolleyLog.d(ERROR_TAG, "Error: " + volleyError.getMessage());
hideProgessDialog();
}
}){
@Override
public Map<String, String> getHeaders() throws AuthFailureError {
HashMap<String, …尝试解析listview中的JSON数据时,我的凌空抛出错误响应.是因为我的JSON数据在对象节点中,而不是数组节点.
JSON数据
{
"users": [{
"userId": 1,
"name": "Dya Vega",
"profilePhoto": "https://graph.facebook.com/1301454197/picture?type=large",
"dateMatched": "1/1/2015",
"distance": "1 miles away",
"status": "Online",
"requestMessage": "Hi, can I know you?",
"like": 234,
"lastActive": "Active 1 hour ago"
}, {
"userId": 2,
"name": "Esa Ezzatinor",
"profilePhoto": "https://graph.facebook.com/1269334432/picture?type=large",
"dateMatched": "1/1/2015",
"distance": "2 miles away",
"status": "Online",
"requestMessage": "Hi, can I know you?",
"like": 234,
"lastActive": "Active 2 hour ago"
}]
}
码
// Creating volley request obj
JsonArrayRequest userReq = new JsonArrayRequest(url,
new Response.Listener<JSONArray>() {
@Override …是否有可能事先检查json的类型？我是somteimes得到一个数组,有时一个对象,我不知道如何处理这2个案例,而不做2个不同的功能...
public void RequestApi( String url, final ApiResponse<ApiResult> completion )
{
Log.v("Performing request: ", url);
JsonObjectRequest jsonRequest = new JsonObjectRequest(Request.Method.GET, hostname+url, (JSONObject) null,
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response)
{
Log.v("RequestApi Response", response.toString());
//Log.v("Data: ", response.toString());
try {
ApiResult res = new ApiResult();
Boolean success = response.getBoolean("success");
//here need to check type, sometimes array, sometimes object
JSONArray data = response.getJSONArray("data");
res.success = success;
res.data = data;
completion.onCompletion(res);
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() …我的Android应用程序通过REST API与后端服务进行通信.我想嘲笑这个API来快速开发前端.我使用android volley作为客户端网络库.
这是我想要使用的json数据:
{
"name" : "Ravi Tamada",
"email" : "ravi8x@gmail.com",
"phone" :
{
"home" : "08947 000000",
"mobile" : "9999999999"
}
}
这是我的JsonObjectRequest:
JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, APITEST,null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject jsonObject) {
Gson gson = new Gson();
People people;
people = gson.fromJson(jsonObject.toString(),People.class);
tv_city.setText(""+people.email);
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError volleyError) {
}
});
没关系tv_city.setText(""+ people.email())...
这是我的javabean类:
public class People {
public String name ;
public String email;
public class Phone{
public String …我使用Volley库创建了网络应用程序
当我从实时服务器加载JSON URL时,它正常工作
但是当我将这个PHP项目从实时服务器复制到本地服务器(如Xampp)并更改URL参数时
Response.ErrorListener() 方法将被调用,并且没有加载.
在我的应用程序中，根据客户要求，我必须发送一个字符串参数作为字符串响应，而作为响应，我将从服务器获取另一个字符串。我正在对字符串发布请求使用volley库。但是在我的onResponse（String response）方法中，打印响应仅给出200。我检查了POSTMAN上的Post请求，从服务器端可以看到String响应。我将在下面发布我的代码。我哪里出问题了？需要你的帮助。
try {
RequestQueue requestQueue = Volley.newRequestQueue(myContext);
JSONObject jsonBody = new JSONObject();
jsonBody.put("EmailID", "acacva@gmail.com");
jsonBody.put("PassWord", "agaha");
jsonBody.put("IsMobile", "true");
final String requestBody = jsonBody.toString();
StringRequest stringRequest = new StringRequest(Request.Method.POST, apiClass.API_LOGIN, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d("afaga", response);
Toast.makeText(myContext,response,Toast.LENGTH_SHORT).show();
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e("VOLLEY", error.toString());
}
}) {
@Override
public String getBodyContentType() {
return "text/plain; charset=utf-8";
}
@Override
public byte[] getBody() throws AuthFailureError {
try {
return requestBody == null …我的代码-
val accessTokenRequest: JsonObjectRequest = JsonObjectRequest(Request.Method.GET, url,
Response.Listener { response ->
},
Response.ErrorListener { error ->
Toast.makeText(activity,error.toString(), Toast.LENGTH_LONG).show()
}
)
AppController.instance!!.addToRequestQueue(accessTokenRequest)
我要放置的标题 - “搜索”和“授权”
kotlin android-volley rx-kotlin kotlin-extension kotlin-android-extensions
我正在使用Volley Library进行JSON解析,而解析响应如下:
JSON响应:
{"category":{"420":{"key":420,"label":{"420":"Acacia"},"count":"1"},"421":{"key":421,"label":.....
我们可以看到,在一个符号来的响应开始 .如何在不将其转换为字符串的情况下从Android端删除此符号？由于这个符号,我无法获得JSON对象.
代码:
private void jsonRequestGetFilterData() {
utils.showDialog();
String url = Constants.FILTER_URL;
Log.e("URL", "" + url);
StringRequest eventoReq = new StringRequest(Request.Method.POST, url,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.e("RESPONSE", response);
utils.hideDialog();
try {
JSONObject jsonObject = new JSONObject(response);
Log.e("jsonObject",""+jsonObject);
JSONObject jsonObjectCategory = jsonObject.getJSONObject("category");
Log.e("jsonObjectCategory",""+jsonObjectCategory);
} catch (JSONException e) {
e.printStackTrace();
utils.hideDialog();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e("Error: ", "" + error.getMessage());
utils.hideDialog();
}
}) { …