我从我的应用程序中得到了错误报告,所有这些都是一样的.这真的很烦人,因为在我的测试设备(HTC Wildfire,Galaxy S I-II-III,Galaxy Mini,Galaxy Tab 10)中,这个错误从未发生过,对我或我的测试伙伴来说,看起来像用户做了一些与我们不同的事情.
因为这个我不能给你太多有关情况的信息,有一件事我看到,它是一个对话框的解雇,我实际上从来没有通过代码调用.
这是错误:
java.lang.IllegalArgumentException: View not attached to window manager
at android.view.WindowManagerImpl.findViewLocked(WindowManagerImpl.java:587)
at android.view.WindowManagerImpl.removeView(WindowManagerImpl.java:324)
at android.view.WindowManagerImpl$CompatModeWrapper.removeView(WindowManagerImpl.java:151)
at android.app.Dialog.dismissDialog(Dialog.java:328)
at android.app.Dialog$1.run(Dialog.java:119)
at android.app.Dialog.dismiss(Dialog.java:313)
at android.app.Dialog.cancel(Dialog.java:1113)
at hu.kulcssoft.ingyenkonyv.reader.Reader$JavaScriptInterface$1.run(Reader.java:199)
at android.os.Handler.handleCallback(Handler.java:605)
at android.os.Handler.dispatchMessage(Handler.java:92)
at android.os.Looper.loop(Looper.java:137)
at android.app.ActivityThread.main(ActivityThread.java:4424)
at java.lang.reflect.Method.invokeNative(Native Method)
at java.lang.reflect.Method.invoke(Method.java:511)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551)
at dalvik.system.NativeStart.main(Native Method)
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有人能帮助我吗?由于这个问题我每周得到30-40个错误报告,我真的无法弄清楚为什么会这样.
所有建议将不胜感激.谢谢,
android illegalargumentexception android-view android-dialog
我有一个Activity,需要在其中显示Dialog.这里一切都很好.我在Activity中覆盖了onCreateDialog方法,这里是代码:
@Override
protected Dialog onCreateDialog(int dialog)
{
if(dialog == 10)
{
if(waitDialog != null)
waitDialog.dismiss();
dialogCreated = true;
waitDialog = CreateWaitDialog(this);
return waitDialog;
}
else
return new Dialog(this);
}
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其中CreateWaitDialog是创建对话框的自定义方法,而waitDialog是静态变量.
我通过调用showDialog(10)来显示对话框
所有代码都正常运行.
显示对话框后,我正在通过调用关闭它.
if(waitDialog != null)
waitDialog.hide();
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当Activity被销毁时我就会解雇它.
if(dialogCreated)
dismissDialog(10);
super.onDestroy();
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它正在关闭,一切都很棒.但是,当我更改设备的方向并重新创建活动时,它会自动弹出!我没有打电话给任何showDialog或类似的东西它只是弹出!
我需要在Android应用程序中显示自定义对话框.标准AlertDialog设计是不可接受的.Android文档说:
提示:如果需要自定义对话框,则可以将"活动"显示为对话框,而不是使用"对话框API".只需创建一个活动并将其主题设置为清单元素中的Theme.Holo.Dialog:
而已.活动现在显示在对话窗口而不是全屏.
听起来很有希望.我做到了,但透明度不起作用!背景总是灰色的:

这是清单中的一个desc:
<activity
android:name=".MyDialogActivity"
android:screenOrientation="portrait"
android:theme="@android:style/Theme.Holo.Dialog.NoActionBar" >
</activity>
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这是我活动的根源:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:background="#00000000"
android:layout_width="400dp"
android:layout_height="wrap_content" >
// Content ... //
</RelativeLayout>
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我也尝试过android:background="@null"- 效果是一样的.如果我使用android:background="#ff0000"那么它是红色的(应该是).但是我该如何让它变得透明?
更新
我结束了
<style name="MyThemeDialogCustom" parent="android:Theme.Holo.Dialog.NoActionBar" >
<item name="android:windowBackground">@color/transparent</item>
<item name="android:colorBackgroundCacheHint">@null</item>
</style>
Run Code Online (Sandbox Code Playgroud) 当我在Android 4.4及更高版本上运行时,我正在我的应用中使用沉浸式模式.(http://developer.android.com/training/system-ui/immersive.html)
我的活动确实以全屏显示,我通过使用按下音量键setOnSystemUiVisibilityChangeListener.我也有类似的代码将对话框放入沉浸式模式.
但是,当显示对话框时,导航.酒吧跳到屏幕上,然后立即撤退.当对话被解雇时,情况更糟 - 导航.酒吧跳跃并调整背后的活动.
以下是我的支持沉浸式模式的课程.它只是在每个Activity的onResume上调用,并且在构建每个对话框时也会调用一个单独的函数.
我错过了任何旗帜或回调,还是已知的Android问题?
public class ImmersiveModeHelper {
public ImmersiveModeHelper(Activity activity)
{
mActivity = activity;
}
@SuppressLint("NewApi")
public void supportFullScreenImmersiveMode()
{
MyLog.d("ImmersiveModeHelper: supportFullScreenImmersiveMode: ");
// Support full-screen immersive mode on Android 4.4 and up
if (Build.VERSION.SDK_INT >= 19)
{
// Get the needed flags by reflection and use them
try
{
final int immersiveFlag = View.class.getField("SYSTEM_UI_FLAG_IMMERSIVE_STICKY")
.getInt(null);
final int hideNavigationFlag = View.class
.getField("SYSTEM_UI_FLAG_HIDE_NAVIGATION").getInt(null);
final int fullScreenFlag = View.class.getField("SYSTEM_UI_FLAG_FULLSCREEN").getInt(
null);
// Set the …Run Code Online (Sandbox Code Playgroud) android android-ui android-dialog android-activity android-4.4-kitkat
I'm fairly new to Android development and I've created my first "real" application that does the following:
MainActivity processes Extra Data and then displays a ViewDialog that extends Dialog. ViewDialog has a showDialog() method that does the following to setup and display the Dialog:
protected void showDialog(final Activity activity)
{
dialog = new Dialog(activity);
dialog.requestWindowFeature(Window.FEATURE_NO_TITLE);
dialog.setCancelable(false);
dialog.setContentView(dialog_layout);
// Set background color of the dialog
ConstraintLayout currentLayout = (ConstraintLayout) dialog.findViewById(R.id.Dialog);
// setup of views etc ...
// …Run Code Online (Sandbox Code Playgroud)我的应用需要添加用户名才能正常运行.mainActivity在顶部显示它从数据库中检索的用户名.mainActivity还有一个按钮,通过startActivityForResult()方法导致'addusername'活动; 当用户实际输入用户名时,只有主活动上的用户名才会刷新并显示."addusername"活动上有一个提交按钮,用于添加用户名,setResult(RESULT_OK);
如果通过单击"addusername"按钮输入用户名,则Everything正常工作.
现在,我在mainActivity中添加了一个对话框,只有在数据库中没有用户名时才会启动应用程序.对话框提供了添加用户名的选项,如果单击该用户名,则会导致"addusername"活动.但按下"提交"按钮后,mainActivity会被调用,但用户名不会刷新(但数据库确实会更新)
以下是"addusername"活动的代码:
public void submitusername(View view) {
userdatabase name = new userdatabase(this);
name.open();
String user = name.getusername();
name.close();
EditText cinone = (EditText) findViewById(R.id.username);
username = cinone.getText().toString();
if(user.equals("")) {
userdatabase entry = new userdatabase(Editprofile.this);
entry.open();
entry.createEntry(username, null, null, null);
entry.close();
Context context = getApplicationContext();
CharSequence text = "Added new user!";
int duration = Toast.LENGTH_LONG;
Toast toast = Toast.makeText(context, text, duration);
toast.show();
}
else {
userdatabase update = new userdatabase(Editprofile.this);
update.open();
update.updateUsername(username);
update.close();
Context context = getApplicationContext();
CharSequence …Run Code Online (Sandbox Code Playgroud) 以下是我调用DialogFragment的方法:
DialogSelectAccount myDiag=new DialogSelectAccount();
myDiag.show(ft,"Diag" );
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这是(部分)我的DialogFragment的创建方式:
public class DialogSelectAccount extends DialogFragment {
public DialogSelectAccount() {
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setRetainInstance(true);
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.dialog_select_account, container, false);
tvMessage = (TextView) rootView.findViewById(R.id.tvMessage);
btnAccountPublic = (Button) rootView.findViewById(R.id.btnAccountPublic);
btnAccountEnterprise = (Button) rootView.findViewById(R.id.btnAccountEnterprise);
tvMessage.setText(message);
btnAccountPublic.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Login.setAccountType = 2;
dismiss();
}
});
btnAccountEnterprise.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Login.setAccountType …Run Code Online (Sandbox Code Playgroud) android android-layout android-fragments android-dialog android-dialogfragment
我无法让 AlertDialog 中的文本以粗体或斜体显示。
我尝试过直接格式化,也尝试过使用Android 字符串资源页面中的 CharSequence 实用程序,但我总是只得到纯文本。
我究竟做错了什么?
MyFragment.java
String idFormatted = String.format(resources.getString(R.string.id));
CharSequence idStyledText = Html.fromHtml(idFormatted);
CharSequence nameItalic = Utilities.italic(resources.getString(R.string.name));
String typeFormatted = String.format(resources.getString(R.string.type));
CharSequence typeStyledText = Html.fromHtml(idFormatted);
AlertDialog.Builder builder = new AlertDialog.Builder(mContext);
builder.setPositiveButton("Dismiss",
new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
}
}).setIcon(android.R.drawable.ic_dialog_info);
builder.setMessage( idFormatted + myData.getId() + "\t\t" + nameItalic + myData.getName() + "\t\t" + typeFormatted + myData.getType() );
Dialog dialog = builder.create();
dialog.setTitle("Details");
dialog.show();
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字符串.xml
<string name="id"><i>Id: </i></string>
<string name="name"><i>Name: </i></string> …Run Code Online (Sandbox Code Playgroud) 如何断言未显示对话框?
目前我有一个测试,检查文本是否不存在于不显示对话框的对话框中
onView(withText("Mobile connection")).inRoot(isDialog()).check(doesNotExist());
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但我得到一个 NoMatchingRootException
android.support.test.espresso.NoMatchingRootException: Matcher 'is dialog' did not match any of the following roots: [Root{application-window-token=android.view.ViewRootImpl$W@9acefba, window-token=android.view.ViewRootImpl$W@9acefba, has-window-focus=true, layout-params-type=1, layout-params-string=WM.LayoutParams{(0,0)(fillxfill) ty=1 fl=#81810100 wanim=0x1030465 needsMenuKey=2}, decor-view-string=DecorView{id=-1, visibility=VISIBLE, width=768, height=1280, has-focus=true, has-focusable=true, has-window-focus=true, is-clickable=false, is-enabled=true, is-focused=false, is-focusable=false, is-layout-requested=false, is-selected=false, root-is-layout-requested=false, has-input-connection=false, x=0.0, y=0.0, child-count=5}}]
at dalvik.system.VMStack.getThreadStackTrace(Native Method)
at java.lang.Thread.getStackTrace(Thread.java:1566)
at android.support.test.espresso.base.DefaultFailureHandler.getUserFriendlyError(DefaultFailureHandler.java:92)
at android.support.test.espresso.base.DefaultFailureHandler.handle(DefaultFailureHandler.java:56)
at android.support.test.espresso.ViewInteraction.runSynchronouslyOnUiThread(ViewInteraction.java:184)
at android.support.test.espresso.ViewInteraction.check(ViewInteraction.java:158)
at uk.co.imagitech.learn2.hp.MainActivityConnectedTest.doesntShowMeteredDialogAtStart(MainActivityConnectedTest.java:43)
at java.lang.reflect.Method.invoke(Native Method)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17)
at android.support.test.internal.statement.UiThreadStatement.evaluate(UiThreadStatement.java:55)
at android.support.test.rule.ActivityTestRule$ActivityStatement.evaluate(ActivityTestRule.java:270)
at org.junit.rules.RunRules.evaluate(RunRules.java:20)
at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:325)
at …Run Code Online (Sandbox Code Playgroud) 这是我的对话框的 xml 文件
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:id="@+id/main"
android:paddingTop="23dp"
android:background="@android:color/white">
<ImageView
android:id="@+id/officer"
android:layout_width="47dp"
android:layout_height="47dp"
android:layout_marginLeft="24dp"
android:background="@drawable/officerman"/>
<TextView
android:id="@+id/text"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Are you sure you want\nto sign out?"
android:textSize="15.5dp"
android:textColor="#1C86FF"
android:layout_marginTop="4dp"
android:lineSpacingExtra="2dp"
android:layout_marginLeft="84dp"/>
<LinearLayout
android:layout_marginTop="20dp"
android:layout_width="264dp"
android:layout_height="wrap_content"
android:orientation="horizontal"
android:weightSum="1"
android:layout_below="@id/officer">
<Button
android:id="@+id/yes"
android:layout_width="wrap_content"
android:layout_weight="0.5"
android:layout_height="42dp"
android:background="#1C86FF"
android:text="Yes"
android:textAllCaps="false"
android:textSize="15dp"
android:textColor="@android:color/white"/>
<Button
android:id="@+id/no"
android:layout_width="wrap_content"
android:layout_weight="0.5"
android:layout_height="42dp"
android:background="#0078FF"
android:textSize="15dp"
android:textColor="@android:color/white"
android:textAllCaps="false"
android:text="No"/>
</LinearLayout>
</RelativeLayout>
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这是我的java代码
AlertDialog.Builder build = new AlertDialog.Builder(Login.this);
View lview = getLayoutInflater().inflate(R.layout.dialog_leave,null);
build.setView(lview);
AlertDialog dialog = build.create();
dialog.show(); …Run Code Online (Sandbox Code Playgroud)