有没有之间的差异isset和!empty.如果我做这个双布尔检查,这种方式是正确的还是多余的?有没有更短的方法来做同样的事情?
isset($vars[1]) AND !empty($vars[1])
Run Code Online (Sandbox Code Playgroud) 我正在尝试进行SQL查询,但我需要以某种方式检查该值是否为电子邮件地址.我需要一种方法来检查是否$user是一个电子邮件地址,因为我在我的表中有这样的用户值.
test
test2
test@example.com
test2@example.com
test392
test@example.net
Run Code Online (Sandbox Code Playgroud)
等等...
我需要$useremail检查$user以确定它是否是电子邮件地址.所以我可以更新值WHERE user=test OR user=test@example.com,等等.
$user = strtolower($olduser);
$useremail = "";
mysql_query("UPDATE _$setprofile SET user=$sn, fc=$fc WHERE user='$user' OR user='$useremail");
Run Code Online (Sandbox Code Playgroud) 是否有一个更简单的功能:
if (isset($_POST['Submit'])) {
if ($_POST['login'] == "" || $_POST['password'] == "" || $_POST['confirm'] == "" || $_POST['name'] == "" || $_POST['phone'] == "" || $_POST['email'] == "") {
echo "error: all fields are required";
} else {
echo "proceed...";
}
}
Run Code Online (Sandbox Code Playgroud) 每当我在表单中提交某些内容时,我想检查是否有任何字段为空.到目前为止,我所拥有的不起作用
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$username = $_POST['username'];
$password = $_POST['password'];
$passwordconf = $_POST['passwordconf'];
$email = $_POST['email'];
$securityq = $_POST['securityq'];
$qanswer = $_POST['qanswer'];
if(empty($firstname) || empty($lastname) || empty($username) || empty($password) || empty($passwordconf) || empty($email) || empty($securityq) || empty($qanswer))
{
echo "You did not fill out the required fields.";
}
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和形式
<form name="registrationform" action="register.php">
First Name:<input type="text" name="firstname">
Last Name:<input type="text" name="lastname">
Email:<input type="text" name="email">
Username:<input type="text" name="username">
Password:<input type="password" name="password">
Confirm Password:<input type="password" name="passwordconf">
Security Question:<input type="text" name="securityq"> …Run Code Online (Sandbox Code Playgroud)