相关疑难解决方法(0)

在浏览了pyaudio的文档并阅读了网上的其他文章后,如果我的理解是正确的,我会感到困惑.

这是在pyaudio网站上找到的录音代码:

import pyaudio
import wave

CHUNK = 1024
FORMAT = pyaudio.paInt16
CHANNELS = 2
RATE = 44100
RECORD_SECONDS = 5
WAVE_OUTPUT_FILENAME = "output.wav"

p = pyaudio.PyAudio()

stream = p.open(format=FORMAT,
                channels=CHANNELS,
                rate=RATE,
                input=True,
                frames_per_buffer=CHUNK)

print("* recording")

frames = []

for i in range(0, int(RATE / CHUNK * RECORD_SECONDS)):
    data = stream.read(CHUNK)
    frames.append(data)

print("* done recording")

stream.stop_stream()
stream.close()
p.terminate()

如果我添加这些行,那么我可以播放我记录的任何内容:

play=pyaudio.PyAudio()
stream_play=play.open(format=FORMAT,
                      channels=CHANNELS,
                      rate=RATE,
                      output=True)
for data in frames: 
    stream_play.write(data)
stream_play.stop_stream()
stream_play.close()
play.terminate()

1. "RATE"是每秒收集的样本数.
2. "CHUNK"是缓冲区中的帧数.
3. 每帧将有2个样本作为"CHANNELS = 2".
4. 每个样本的大小为2个字节,使用函数计算:pyaudio.get_sample_size(pyaudio.paInt16). …

我已经让OpenCV和PyAudio都工作了但是我不确定如何将它们同步到一起.我无法从OpenCV获得帧速率,并且测量帧的调用时间会随时变化.然而,对于PyAudio,它的基础是获取某个采样率.我如何以相同的速率同步它们.我假设有一些标准或某种方式编解码器做它.(我已经尝试了谷歌,我得到的是唇同步的信息:/).

OpenCV帧率

from __future__ import division
import time
import math
import cv2, cv

vc = cv2.VideoCapture(0)
# get the frame
while True:

    before_read = time.time()
    rval, frame = vc.read()
    after_read  = time.time()
    if frame is not None:
        print len(frame)
        print math.ceil((1.0 / (after_read - before_read)))
        cv2.imshow("preview", frame)

        if cv2.waitKey(1) & 0xFF == ord('q'):
            break

    else:
        print "None..."
        cv2.waitKey(1)

# display the frame

while True:
    cv2.imshow("preview", frame)

    if cv2.waitKey(1) & 0xFF == ord('q'):
        break

抓取并保存音频

from sys import byteorder
from array …