相关疑难解决方法(0)

我在Java 6中使用SwingWorker来避免在事件派发线程上运行长时间运行的代码.

如果在我的done()方法中调用get()会返回异常,那么处理异常的适当方法是什么？

我特别关注可能的InterruptedExceptions.JavaDoc示例简单地忽略了异常,但多年来我已经了解到吞咽异常导致难以调试的代码.

示例用法如下:

new SwingWorker<String, Void>() {

    @Override
    protected String doInBackground() throws Exception {
        // do long-running calculation
        return result;
    }

    @Override
    protected void done() {
        try {
            setTextField(get());
        } catch (InterruptedException e) {
            e.printStackTrace();  
        } catch (ExecutionException e) {
            e.printStackTrace();  
        }
    }
}.execute();

我通过使用Executor玩SwingWorker的多线程,我在那里错误地从Vector中识别出错误的元素,看起来像这个代码相当忽略了Vector中的元素不存在

我的问题 - >如何/有可能以某种方式捕获此异常

简单的输出

run:
Thread Status with Name :StartShedule, SwingWorker Status is STARTED
Thread Status with Name :StartShedule, SwingWorker Status is DONE
Thread Status with Name :StartShedule, SwingWorker Status is STARTED
Thread Status with Name :StartShedule, SwingWorker Status is DONE
Thread Status with Name :StartShedule, SwingWorker Status is STARTED
Thread Status with Name :StartShedule, SwingWorker Status is DONE
BUILD SUCCESSFUL (total time: 11 seconds)

通过取消注释

//changeTableValues1(); // un-comment for get ArrayIndexOutOfBoundsException

一切都正确,我得到ArrayIndexOutOfBoundsException并输出

run:
Exception in thread "AWT-EventQueue-0" java.lang.ArrayIndexOutOfBoundsException: …