相关疑难解决方法(0)

以下代码在第2行接收seg错误:

char *str = "string";
str[0] = 'z';  // could be also written as *str = 'z'
printf("%s\n", str);

虽然这非常有效:

char str[] = "string";
str[0] = 'z';
printf("%s\n", str);

经过MSVC和GCC测试.