相关疑难解决方法(0)

我想通过codeigniter的db helper类编写以下查询,引导我plz

SELECT * FROM table where column like binary "abc";

我试过了

$this->db->select("*");
$this->db->from("table");
$this->db->like("column","binary abc");
$this->db->get();

但它产生了

SELECT * FROM table WHERE column like '%binary abc%'