相关疑难解决方法(0)

我想知道程序/功能/订单需要多长时间才能完成测试.

这是我做的,但我的方法是错误的'因为如果秒的差异为0则无法返回经过的毫秒:

请注意,睡眠值为500毫秒,因此经过的秒数为0,则无法返回毫秒数.

    Dim Execution_Start As System.DateTime = System.DateTime.Now
    Threading.Thread.Sleep(500)

    Dim Execution_End As System.DateTime = System.DateTime.Now
    MsgBox(String.Format("H:{0} M:{1} S:{2} MS:{3}", _
    DateDiff(DateInterval.Hour, Execution_Start, Execution_End), _
    DateDiff(DateInterval.Minute, Execution_Start, Execution_End), _
    DateDiff(DateInterval.Second, Execution_Start, Execution_End), _
    DateDiff(DateInterval.Second, Execution_Start, Execution_End) * 60))

有人能告诉我更好的方法吗？也许有一个TimeSpan？

解决方案:

Dim Execution_Start As New Stopwatch
Execution_Start.Start()

Threading.Thread.Sleep(500)

MessageBox.Show("H:" & Execution_Start.Elapsed.Hours & vbNewLine & _
       "M:" & Execution_Start.Elapsed.Minutes & vbNewLine & _
       "S:" & Execution_Start.Elapsed.Seconds & vbNewLine & _
       "MS:" & Execution_Start.Elapsed.Milliseconds & vbNewLine, _
       "Code execution time", MessageBoxButtons.OK, …

是否可以Environment.TickCount用来计算时间跨度？

int start = Environment.TickCount;
// Do stuff
int duration = Environment.TickCount - start;
Console.WriteLine("That took " + duration " ms");

因为TickCount已签名并将在25天后翻转(所有32位需要50天,但如果你想对数学有任何意义,你必须废弃已签名的位),看起来它太冒险了.

我正在使用DateTime.Now.这是最好的方法吗？

DateTime start = DateTime.Now;
// Do stuff
TimeSpan duration = DateTime.Now - start;
Console.WriteLine("That took " + duration.TotalMilliseconds + " ms");

我有两个蒙版的TextBox控件,并想知道如何在每个控件中获取时间然后将差异转换为毫秒.比如说,在tb1我写"12:01",在tb2我写"12:02",然后点击一个按钮.单击按钮后,它将启动一个计时器,并在12:02显示一个消息框.除了时间转换部分,我知道如何做所有这些.

如何实现？