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在C中将进程放在后台

我目前潜入创建一个backgrounding工作C&.我需要实现非阻塞waitpid才能使其正常工作.我知道.此外,如果&在命令行末尾输入,我已经抓住了这个条件.我只是不确定如何准确地将进程作为后台作业发送,并将其实现为执行,而另一个提示是提示下一个命令.
任何事情都会有所帮助,谢谢.

    struct bgprocess{
        int pid;
        struct bgprocess * next;
        struct bgprocess * prev;    
    };

    struct bgprocess * bgprocess1;
    bgprocess1 = malloc(sizeof(struct bgprocess));
    bgprocess1->prev = NULL;
    bgprocess1->next = NULL;
    bgprocess1->pid = NULL;

    struct bgprocess * current;
    current = bgprocess1;

    do{
        int bgreturn = 0;
        while (current != NULL){
            if (waitpid(current->pid, &bgreturn, WNOHANG)){
                printf("Child exited");
                current->prev->next = current->next;
                current->next->prev = current->prev;
                current->prev = NULL;
                current->next = NULL;
                free(current);                  
            }
        current = current->next;    
        } …
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c unix background-process

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