PHP代码:
echo hash('sha256', 'jake');
PHP输出:
cdf30c6b345276278bedc7bcedd9d5582f5b8e0c1dd858f46ef4ea231f92731d
Java代码:
String s = "jake";
MessageDigest md = MessageDigest.getInstance("SHA-256");
md.update(s.getBytes(Charset.forName("UTF-8")));
byte[] hashed = md.digest();
String s2 = "";
for (byte b : hashed) {
s2 += b;
}
System.out.println(s2);
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Java输出:
-51-1312107528211839-117-19-57-68-19-39-43884791-1141229-4088-12110-12-223531-11011529
我曾预料到两者会返回相同的结果.显然,事实并非如此.我怎样才能让两者相匹配或者不可能?
编辑:我犯了一个错误,认为我现在已经回答了这个问题.
我一直在尝试加密一个项目的一些用户密码,但我似乎无法让它正常工作.我决定使用SHA-256算法,当我使用Sha2向MySQL引入密码时(例如,256)它为加密密码添加了两个零.在Java中,我使用它来散列程序中的文本,但无法获得相同的结果.
try {
MessageDigest digest = MessageDigest.getInstance("SHA-256");
byte[] hash = digest.digest("ContrasenhaPassword".getBytes("UTF-8"));
StringBuilder hexString = new StringBuilder();
for (int i: hash) {
hexString.append(Integer.toHexString(0XFF & i));
}
String Hashed = new String(hexString);
System.out.println(hexString);
System.out.println(Hashed);
// Below, MySQL Output for SHA2('ContrasenhaPassword',256)
System.out.println("d17bf0da90f56b8fc627bac6523ffd284aa0d82c870e1a0428274de048f49d78");
System.out.println(Hashed.equals(hexString));
} catch (Exception e) {
e.printStackTrace();
}
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我得到的输出是:
d17bf0da90f56b8fc627bac6523ffd284aa0d82c87e1a428274de048f49d78
d17bf0da90f56b8fc627bac6523ffd284aa0d82c87e1a428274de048f49d78
d17bf0da90f56b8fc627bac6523ffd284aa0d82c870e1a0428274de048f49d78
false
BUILD SUCCESSFUL (total time: 0 seconds)
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有任何想法吗?