相关疑难解决方法(0)

您好我无法弄清楚为什么当直接传递给keyup事件时debounce函数按预期工作; 但如果我将它包装在匿名函数中,它就不起作用.

我有问题:http : //jsfiddle.net/6hg95/1/

编辑:添加了我尝试过的所有东西.

HTML

<input id='anonFunction'/>
<input id='noReturnAnonFunction'/>
<input id='exeDebouncedFunc'/>
<input id='function'/>
<div id='output'></div>

JAVASCRIPT

$(document).ready(function(){
    $('#anonFunction').on('keyup', function () {
        return _.debounce(debounceIt, 500, false); //Why does this differ from #function
    });
    $('#noReturnAnonFunction').on('keyup', function () {
        _.debounce(debounceIt, 500, false); //Not being executed
    });
    $('#exeDebouncedFunc').on('keyup', function () {
        _.debounce(debounceIt, 500, false)(); //Executing the debounced function results in wrong behaviour
    });
    $('#function').on('keyup', _.debounce(debounceIt, 500, false)); //This is working.
});

function debounceIt(){
    $('#output').append('debounced');
}

anonFunction并且noReturnAnonFunction不会启动去抖功能; 但是最后一次function …