相关疑难解决方法(0)

我有2个物体,当我移动一个物体时,我想从另一个物体获得角度.

例如:

Object1X = 211.000000, Object1Y = 429.000000
Object2X = 246.500000, Object2Y = 441.500000

我在阳光下尝试过以下各种变化:

double radians = ccpAngle(Object1,Object2);
double degrees = ((radians * 180) / Pi); 

但我只是得到2.949023返回我想要45度等的东西.

我实施了http://www.movable-type.co.uk/scripts/latlong.html中的"方位"公式.但它似乎非常不准确 - 我怀疑我的实施中有些错误.你能帮我找到它吗？我的代码如下:

protected static double bearing(double lat1, double lon1, double lat2, double lon2){

double longDiff= lon2-lon1;
double y = Math.sin(longDiff)*Math.cos(lat2);
double x = Math.cos(lat1)*Math.sin(lat2)-Math.sin(lat1)*Math.cos(lat2)*Math.cos(longDiff);

return Math.toDegrees((Math.atan2(y, x))+360)%360;
}

我试图使用css 3变换旋转功能将div旋转到一个点.

我达到了这一点:jsfiddle链接

$(document).ready(function(){
    var scw,sch,scx,scy;
    calcCenter();
    $(window).resize(function() {         
        calcCenter();
    });
    function calcCenter(){
      sch = $(window).height(); 
      scw = $(window).width(); 
      scx = scw/2;
      scy = sch/2;
        $(".circle").remove();
      var circle = $("<span></span>").addClass('circle').text('.');
      circle.css('top',scy-50+"px");
      circle.css('left',scx-50+"px");
    $(document.body).append(circle);
    }
    function calcAngle(p1,p2){

        var angle = Math.atan2(p2.y - p1.y, p2.x - p1.x) * 180 / Math.PI;
        return angle;
    }



    $(document).click(function(e){  
        var box = $("<span></span>").addClass('box');
        var x = e.pageX,y=e.pageY; 
        box.css('top',y+"px");
        box.css('left',x+"px"); 

        $(document.body).append(box);
        var angle = calcAngle({x:x,y:y},{x:scx,y:scy});

        box.css('-webkit-transform','rotate('+(90+angle)*-1+'deg)');        

        box.draggable({
                drag: function(e) {
                        var box = $(this);
                        var x …