相关疑难解决方法(0)

{u'Status': u'OK', u'City': u'Ciri\xe8', u'TimezoneName': '', u'ZipPostalCode': '', u'CountryCode': u'IT', u'Dstoffset': u'0', u'Ip': u'x.x.x.x', u'Longitude': u'7.6', u'CountryName': u'Italy', u'RegionCode': u'12', u'Latitude': u'45.2333', u'Isdst': '', u'Gmtoffset': u'0', u'RegionName': u'Piemonte'}

这是我的对象的输出.我想访问City,但它是编码的.如何读取所有参数并对其进行解码

>>> data['City']
u'Ciri\xe8'

>>>data['City'].decode('utf-8')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/encodings/utf_8.py", line 16, in decode
    return codecs.utf_8_decode(input, errors, True)
UnicodeEncodeError: 'ascii' codec can't encode character u'\xe8' in position 4: ordinal not in range(128)

我想明文不是unicode字符串.谢谢!

我的unicode奇怪的错误.我正在处理unicode很好,但是当我今天早上运行它时,一个项目你''u201d'给了我错误并给了我

UnicodeError: ASCII encoding error: ordinal not in range(128)

我查了代码,显然是它的utf-32但是当我尝试在解释器中解码时:

c = u'\u201d'
c.decode('utf-32', 'replace')

或者它的任何其他操作,它只是没有在任何编解码器中识别它但我发现它是"正确的双引号"

我明白了:

Traceback (most recent call last):
File "<pyshell#154>", line 1, in <module>
    c.decode('utf-32')
  File "C:\Python27\lib\encodings\utf_32.py", line 11, in decode
    return codecs.utf_32_decode(input, errors, True)
UnicodeEncodeError: 'ascii' codec can't encode character u'\u201d' in position 0: ordinal not in range(128)