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将curl示例转换为pycurl

有人可以将以下PostMark卷曲示例转换为pycurl吗?

curl -X POST "http://api.postmarkapp.com/email" \

-H "Accept: application/json" \

-H "Content-Type: application/json" \

-H "X-Postmark-Server-Token: ed742D75-5a45-49b6-a0a1-5b9ec3dc9e5d" \

-v \

-d "{From: 'sender@example.com', To: 'receiver@example.com', Subject: 'Postmark test', HtmlBody: '<html><body><strong>Hello</strong> dear Postmark user.</body></html>'}"
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curl pycurl python-2.7 postmark

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curl ×1

postmark ×1

pycurl ×1

python-2.7 ×1