相关疑难解决方法(0)

jpa中生成的表中的排序错误

这应该是一件相当简单的事情,但我正在努力.

我希望像这样生成一个表:

id 
organizationNumber 
name

但是,当我查看数据库时,我发现排序错误.有谁知道我如何强制hibernate/jpa生成正确排序的表?

desc Organization;
+--------------------+--------------+------+-----+---------+----------------+
| Field              | Type         | Null | Key | Default | Extra          |
+--------------------+--------------+------+-----+---------+----------------+
| id                 | bigint(20)   | NO   | PRI | NULL    | auto_increment | 
| name               | varchar(255) | NO   |     | NULL    |                | 
| organizationNumber | varchar(255) | NO   | UNI | NULL    |                | 
+--------------------+--------------+------+-----+---------+----------------+

这就是我的实体bean的样子:

@Entity
@NamedQuery(name = "allOrganizations", query = "SELECT org FROM Organization org order by name")
public class Organization {

    private …

java hibernate jpa

54
推荐指数
5
解决办法
2万
查看次数

Hibernate + MySQL:如何为数据库和表设置编码utf-8

我的系统运行在Linux Mandriva,RDBMS - MySQL 5上.我需要使用UTF-8创建数据库和表.

这是hibernate.cfg.xml的一个片段-

... 
 <property name="hibernate.hbm2ddl.auto">create-drop</property>   
 <property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
 <property name="hibernate.connection.characterEncoding">utf8</property> 
...
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my.cnf -

# The MySQL server
[mysqld]
...
default-character-set=cp1251
character-set-server=cp1251
collation-server=cp1251_general_ci
init-connect="SET NAMES cp1251"
skip-character-set-client-handshake
...
[mysqldump]
...    
default-character-set=cp1251
...
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有些课,例如 -

@Entity
@Table(name = "USER")
public class User {
    @Id 
    @Column(name = "USERID")
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id;

    @Column(name = "USERNAME")
    private String name;

    @Column(name = "USERPASSWORD")
    private String password;

    @Column(name = "USERIP")
    private String ip;
        // …
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mysql linux hibernate jpa character-encoding

25
推荐指数
5
解决办法
7万
查看次数

使用hibernate创建新表时如何维护列顺序?

这是我的pojo注释为实体

@Entity
@Table(name = "book", catalog = "book_db")
public class Book {
    private Integer bookId;
    private String bookName;
    private String bookShortDesc;
    private String bookDesc;
    private String bookAuthor;
}
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "book_id", unique = true, nullable = false)
public Integer getBookId() {
    return this.bookId;
}

@Column(name = "book_name", nullable = false, length = 256)
public String getBookName() {
    return this.bookName;
}
@Column(name = "book_short_desc", nullable = false, length = 1024)
public String getBookShortDesc() {
    return this.bookShortDesc;
} …
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java database hibernate

11
推荐指数
1
解决办法
6060
查看次数

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