相关疑难解决方法(0)

我想通过单击按钮将图像从Web显示到另一个Jframe中的面板,但每当我单击按钮时,图像就会加载,在此期间当前表单可能会冻结,一旦图像加载,表单就会显示与形象..我怎么能避免我的形式冻结的情况,因为它非常刺激

我的代码::

我现在的课

private void btn_TrackbusActionPerformed(java.awt.event.ActionEvent evt) {                                             
        try {
            sendMessage("Query,map,$,start,211,Arsenal,!");
            System.out.println(receiveMessage());
        } catch (UnknownHostException ex) {
            Logger.getLogger(client_Trackbus.class.getName()).log(Level.SEVERE, null, ex);
        } catch (IOException ex) {
            Logger.getLogger(client_Trackbus.class.getName()).log(Level.SEVERE, null, ex);
        }
        catch (Exception ex) {
            Logger.getLogger(client_Trackbus.class.getName()).log(Level.SEVERE, null, ex);
        }
        client_trackedbus nextform=new client_trackedbus(planform,connection,packet_receive,packet_send);
        this.setVisible(false);
        this.dispose();
        nextform.setVisible(true);
        // TODO add your handling code here:
    }                                            

我的下一个课程显示图像

public class client_trackedbus extends javax.swing.JFrame {
    client_planform planform=null;
    DatagramSocket connection=null;
    DatagramPacket packet_receive=null;
    DatagramPacket packet_send=null;
    JLabel label=null;
    /** Creates new form client_trackedbus */
    public client_trackedbus(client_planform planform,DatagramSocket connection,DatagramPacket packet_receive,DatagramPacket packet_send) …