相关疑难解决方法(0)

我收到警告:Call-time pass-by-reference has been deprecated对于以下代码行:

function XML() {
    $this->parser = &xml_parser_create();
    xml_parser_set_option(&$this->parser, XML_OPTION_CASE_FOLDING, false);
    xml_set_object(&$this->parser, &$this);
    xml_set_element_handler(&$this->parser, 'open','close');
    xml_set_character_data_handler(&$this->parser, 'data');
}
function destruct() {
    xml_parser_free(&$this->parser);
}
function & parse(&$data) {
    $this->document = array();
    $this->stack    = array();
    $this->parent   = &$this->document;
    return xml_parse(&$this->parser, &$data, true) ? $this->document : NULL;
}

它是什么原因以及如何解决它？

我有一个古老的脚本,最近我得到这个错误:

Fatal error: Call-time pass-by-reference has been removed in /****/******/public_html/****/cp-list-summary.php on line 100

它看起来像是在该文件的第100行:

if ($row[images])
{
    $image_set = array ();
    $result = mysql_query ('SELECT fname FROM ' . $dbimgs . ' WHERE listid=\'' . $_GET['id'] . '\' ORDER BY id ASC', $link);
    while ($images = mysql_fetch_array ($result))
    {
        array_push (&$image_set, $images[fname]);
    }
}

是什么导致错误以及如何解决？我不是开发人员,所以请慢慢来.

我有这个错误消息与Centos 5.9,PHP 5.4和较旧的PHP程序扩展(typo3 CMS).

PHP致命错误:已在第279行的class.tx_spscoutnetcalendar_pi1.php中删除了调用时传递引用

这是模拟php代码的功能:

    // ********* Start XML code *********
    // get XML data from an URL and return it
    function fetchCalendarData($xmlUrl,$timeout) {

            $xmlSource="";
            $url = parse_url($xmlUrl);

            $fp = fsockopen($url['host'], "80", &$errno, &$errstr, $timeout);
            if ($fp) {
                    fputs($fp, "GET ".$url['path']."?".$url['query']." HTTP/1.1\r\nHost: " . $url['host'] . "\r\n\r\n");
                    while(!feof($fp))
                    $xmlSource .= fgets($fp, 128);
            }
                    // strip HTTP header
        if ($pos = strpos($xmlSource,"<?xml")) { // this has to be the first line
            $xmlSource = substr($xmlSource, $pos);
        } else {
            $xmlSource="";
        } …