相关疑难解决方法(0)

我搜索了很多并找到了很多解决方案,但没有一个能给我2012-12-31的正确周数.甚至MSDN(链接)上的示例都失败了.

2012-12-31是星期一,因此它应该是第1周,但我尝试的每种方法都给了我53.以下是我尝试过的一些方法:

来自MDSN图书馆:

DateTimeFormatInfo dfi = DateTimeFormatInfo.CurrentInfo;
Calendar cal = dfi.Calendar;

return cal.GetWeekOfYear(date, dfi.CalendarWeekRule, dfi.FirstDayOfWeek);

解决方案2:

return new GregorianCalendar(GregorianCalendarTypes.Localized).GetWeekOfYear(date, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);

解决方案3:

CultureInfo ciCurr = CultureInfo.CurrentCulture;
int weekNum = ciCurr.Calendar.GetWeekOfYear(dtPassed, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
return weekNum;

更新

当日期为2012-12-31时,以下方法实际返回1.换句话说,我的问题是我的方法不符合ISO-8601标准.

// This presumes that weeks start with Monday.
// Week 1 is the 1st week of the year with a Thursday in it.
public static int GetIso8601WeekOfYear(DateTime time)
{
    // Seriously cheat.  If its Monday, Tuesday or Wednesday, then it'll 
    // be …

我正在计算日期的周数,但是在System.Globalization.Calendar2007年和2012年的12月31日(其他年份)中,它将返回奇数结果.

Calendar calendar = CultureInfo.InvariantCulture.Calendar;
var date = new DateTime(2007, 12, 29);
for (int i = 0; i < 5; i++)
{
    int w = calendar.GetWeekOfYear(date, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
    Console.WriteLine("{0}\t{1}", date.ToString("dd.MM.yyyy"), w);
    date = date.AddDays(1);
}

结果

29.12.2007      52
30.12.2007      52
31.12.2007      53 <--
01.01.2008       1
02.01.2008       1

29.12.2012      52
30.12.2012      52
31.12.2012      53 <--
01.01.2013       1
02.01.2013       1

据我了解,2007年和2012年不应该有53周,但是应该在第1周包括这些日子.有没有办法改变这种行为Calendar？