相关疑难解决方法(0)

假设我创建一个对象如下:

var myObject = {
    "ircEvent": "PRIVMSG",
    "method": "newURI",
    "regex": "^http://.*"
};

什么是去除财产的最好方式regex与新落得myObject如下？

var myObject = {
    "ircEvent": "PRIVMSG",
    "method": "newURI"
};

我想从JSON中删除JSON元素或一整行.

我有以下JSON字符串:

{
   "result":[
       {
           "FirstName": "Test1",
           "LastName":  "User",
       },
       {
           "FirstName": "user",
           "LastName":  "user",
       },
       {
           "FirstName": "Ropbert",
           "LastName":  "Jones",
       },
       {
           "FirstName": "hitesh",
           "LastName":  "prajapti",
       }
   ]
}

我有一个json对象,如下所示.我想删除"otherIndustry"条目及其值,使用下面的代码不起作用.

var updatedjsonobj = delete myjsonobj['otherIndustry'];

如何删除Json对象特定的键及其值.下面是我的示例json对象,我想删除"otherIndustry"键及其值.

var myjsonobj =  {
      "employeeid": "160915848",
      "firstName": "tet",
      "lastName": "test",
      "email": "test@email.com",
      "country": "Brasil",
      "currentIndustry": "aaaaaaaaaaaaa",
      "otherIndustry": "aaaaaaaaaaaaa",
      "currentOrganization": "test",
      "salary": "1234567"
    };
delete myjsonobj ['otherIndustry'];
console.log(myjsonobj);

日志仍然打印相同的对象而不从对象中删除"otherIndustry"条目.

我有这个 JSON 文件：http : //danish-regional-data.googlecode.com/svn/trunk/danish_regional_data.json

如何删除所有attribues within_5_km，within_10_km，within_25_km，within_50_km，within_100_km所有的邮政编码？

我已阅读此问题：删除 JSON 属性

$(document).ready(function() {

    $.getJSON("post.json", function(data) {

    var pc = data.postalcodes;
    for (var id in pc) {
       if(pc.hasOwnProperty(id)) {
          for(var attr in pc[id]) {
             if(pc[id].hasOwnProperty(attr) && attr.indexOf('within_') === 0) {
               delete pc[id][attr];
             }
          }
       }
    }

    $("#json").html(pc);

    });

});