我使用eclipselink了JPA.我有一个实体,它有一个由两个字段组成的复合键.以下是我的可嵌入主键类'字段(成员).
@Embeddable
public class LeavePK {
@ManyToOne(optional = false)
@JoinColumn(name = "staffId", nullable = false)
private Staff staff;
@Temporal(TemporalType.TIMESTAMP)
private Calendar date;
//setters and getters
}
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我的实体将保留与员工相关的休假数据,因此我尝试将员工对象和离开日期结合起来以生成组合键.除了我的逻辑,它不允许我在embeddable类中有一个外键映射.当我尝试使用JPA工具 - >从实体生成表时,它会给出如下错误,这解释了,但我没有得到它.
org.eclipse.persistence.exceptions.ValidationException
Exception Description: The mapping [staff] from the embedded ID class [class rs.stapp.entity.LeavePK] is an invalid mapping for this class. An embeddable class that is used with an embedded ID specification (attribute [leavePK] from the source [class rs.stapp.entity.Leave]) can only contain …Run Code Online (Sandbox Code Playgroud)