我正在尝试使用twitter4j库为我的java项目发送推文.在我第一次运行时,我收到了关于证书sun.security.validator.ValidatorException和错误的错误sun.security.provider.certpath.SunCertPathBuilderException.然后我添加了twitter证书:
C:\Program Files\Java\jdk1.7.0_45\jre\lib\security>keytool -importcert -trustcacerts -file PathToCert -alias ca_alias -keystore "C:\Program Files\Java\jdk1.7.0_45\jre\lib\security\cacerts"
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但没有成功.这是获得twitters的过程:
public static void main(String[] args) throws TwitterException {
ConfigurationBuilder cb = new ConfigurationBuilder();
cb.setDebugEnabled(true)
.setOAuthConsumerKey("myConsumerKey")
.setOAuthConsumerSecret("myConsumerSecret")
.setOAuthAccessToken("myAccessToken")
.setOAuthAccessTokenSecret("myAccessTokenSecret");
TwitterFactory tf = new TwitterFactory(cb.build());
Twitter twitter = tf.getInstance();
try {
Query query = new Query("iphone");
QueryResult result;
result = twitter.search(query);
System.out.println("Total amount of tweets: " + result.getTweets().size());
List<Status> tweets = result.getTweets();
for (Status tweet : tweets) {
System.out.println("@" + tweet.getUser().getScreenName() + " …Run Code Online (Sandbox Code Playgroud) 以下代码工作正常:
public static void main(String[] args) {
String userName = "admin";
String password = "s3cret";
Hashtable env = new Hashtable();
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.PROVIDER_URL, "ldap://192.168.10.45:389/dc=softwaredev,dc=local");
//env.put(Context.SECURITY_PROTOCOL, "ssl");
env.put(Context.SECURITY_AUTHENTICATION, "simple");
env.put(Context.SECURITY_PRINCIPAL, new String("softwaredev" + "\\" + userName));
env.put(Context.SECURITY_CREDENTIALS, password);
DirContext ctx = null;
NamingEnumeration results = null;
try {
ctx = new InitialDirContext(env);
SearchControls controls = new SearchControls();
controls.setSearchScope(SearchControls.SUBTREE_SCOPE);
results = ctx.search("", "(objectclass=person)", controls);
while (results.hasMore()) {
SearchResult searchResult = (SearchResult) results.next();
Attributes attributes = searchResult.getAttributes();
System.out.println(" Person Common Name = " …Run Code Online (Sandbox Code Playgroud)