相关疑难解决方法(0)

我正在更深入地学习哈希码,并认为:

1.如果重写equals(),则必须覆盖hashcode().

2.要查找2个对象是否是同一个对象,请使用==运算符

考虑到这两个因素,在Java中我假设当== operator用于比较2个实例是否相同时,

if(object1 == object2)

实际上是在做

if(object1.hashcode() == object2.hashcode())

但是通过下面的测试看起来我错了.

public class Main {

    public static void main(String[] args){
        Obj1 one = new Obj1();
        Obj1 two = new Obj1();
        //is this calling hashCode() in backend???
        if(one == two) {
            System.out.println("same");
        }
        else {
            System.out.println("nope");
        }
        //this is of course return true
        if(one == one) {
            System.out.println("one and one is same");
        }
    }
}

class Obj1 {
    @Override
    public int hashCode() {
        System.out.println("hashCode() is called"); …