相关疑难解决方法(0)

考虑一下代码:

#include <stdio.h>

class Base {
public: 
    virtual void gogo(int a){
        printf(" Base :: gogo (int) \n");
    };

    virtual void gogo(int* a){
        printf(" Base :: gogo (int*) \n");
    };
};

class Derived : public Base{
public:
    virtual void gogo(int* a){
        printf(" Derived :: gogo (int*) \n");
    };
};

int main(){
    Derived obj;
    obj.gogo(7);
}

得到此错误:

>g++ -pedantic -Os test.cpp -o test
test.cpp: In function `int main()':
test.cpp:31: error: no matching function for call to `Derived::gogo(int)'
test.cpp:21: note: candidates are: virtual …

为什么这不编译？
错误C2660:'Concrete :: WriteLine':函数不带1个参数
我知道如果我
使用AbstractBase :: WriteLine 添加Line://;
它有效,但我不明白为什么.

#include "iostream" 

class AbstractBase
{
public:
   virtual void WriteLine() = 0;
   virtual void WriteLine( int i )
   {
      std::cout<<"AbstractBase"<<std::endl;
   }
};

class Concrete : public AbstractBase
{
public:
   //using AbstractBase::WriteLine;
   virtual void WriteLine()
   {
      std::cout<<"Concrete Sub Class"<<std::endl;
   }
};

int main()
{
   Concrete ff;
   ff.WriteLine();
   ff.WriteLine(1);
   return 0;
}

有人可以解释一下这里发生了什么.感谢名单

有谁知道这种行为是否是来自C++标准的已定义行为.是否在C++标准中提到过？或者它只是一种编译器行为？