相关疑难解决方法(0)

String myString = "this";
//string is immutable

myString.concat(" that");
//a new object is created but not assigned to anything

System.out.println(myString); //prints out "this"

我更喜欢编译时错误 - 为什么不是这种情况？在没有提供返回类型的情况下调用它时,同样的问题可以应用于具有返回类型的任何方法.

public myObject doStuff(...whatever){
 //define my method
 return anObject;
}

可以调用而不提供引用/变量来保存返回类型:

MyObject newObject = doStuff(); //works
doStuff(); //works too without assigning return object