相关疑难解决方法(0)

我想从纬度和经度中找到当前位置名称,

这里是我的代码片段我试过,但我的日志显示,除了在所有的地方空值placemark,placemark.ISOcountryCode和placemark.country

我想要的价值placemark.locality,并placemark.subLocality却是露出空值.

- (void)viewWillAppear:(BOOL)animated
{
     [super viewWillAppear:animated];

    // this creates the CCLocationManager that will find your current location
    locationManager = [[CLLocationManager alloc] init];
    locationManager.delegate = self;
    locationManager.desiredAccuracy = kCLLocationAccuracyNearestTenMeters;
    [locationManager startUpdatingLocation];

}

// this delegate is called when the app successfully finds your current location
- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
    CLGeocoder *geocoder = [[CLGeocoder alloc] init];
    [geocoder reverseGeocodeLocation:locationManager.location
                   completionHandler:^(NSArray *placemarks, NSError *error) {
                       NSLog(@"reverseGeocodeLocation:completionHandler: Completion Handler called!"); …

我有一个简单的问题.

MKReverseCoder已弃用,自iOS 5起无效.我们必须使用CLGeocoder.但是,iOS4下有很多人.新应用如何与iOS4和iOS5配合使用进行地理编码？

谢谢!

我试图通过CLLocationManager使用纬度和经度获取地址,但它只返回州和国家名称,我也想要城市,我附加我的代码可以任何人告诉我,我怎么能改变我的代码以获得城市名称.Below是我的代码

- (void)locationManager:(CLLocationManager *)manager didUpdateLocations:(NSArray *)locations
{
    currentLocation = [locations objectAtIndex:0];
    CLGeocoder *geocoder1 = [[CLGeocoder alloc] init];

     NSLog(@"Detected Location : %f, %f", currentLocation.coordinate.latitude, currentLocation.coordinate.longitude);

    //CLLocation *newLocation = [[CLLocation alloc]initWithLatitude:26.9260 longitude:75.8235];

    CLLocation *newLocation = [[CLLocation alloc]initWithLatitude:currentLocation.coordinate.latitude longitude:currentLocation.coordinate.longitude];

    [geocoder1 reverseGeocodeLocation:newLocation
                   completionHandler:^(NSArray *placemarks, NSError *error) {

                       if (error) {
                           NSLog(@"Geocode failed with error: %@", error);
                           return;
                       }

                       if (placemarks && placemarks.count > 0)
                       {
                           CLPlacemark *placemark = placemarks[0];

                           NSDictionary *addressDictionary =
                           placemark.addressDictionary;

                           NSLog(@"%@ ", addressDictionary);
                           NSString *address = [addressDictionary
                                                objectForKey:(NSString *)kABPersonAddressStreetKey];
                           NSString *city …