我正在使用JAX WS来公开WebService.此服务的某些操作可能会生成异常.不是内部服务器异常,而是依赖于操作调用的输入参数的异常.
如果我指定我的操作抛出自定义异常,如下所示:
@WebService
@SOAPBinding(style = Style.RPC, use = Use.LITERAL)
public class MyServiceEndpointImpl implements MyServiceEndpoint {
@WebMethod
public void throwsException throws InvalidInputException;
}
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运行应用程序时,我最终得到以下堆栈跟踪:
com.sun.xml.ws.model.RuntimeModelerException: runtime modeler error: Wrapper class com.mypackage.ws.services.jaxws.InvalidInputExceptionBean is not found. Have you run APT to generate them?
at com.sun.xml.ws.model.RuntimeModeler.getClass(RuntimeModeler.java:285)
at com.sun.xml.ws.model.RuntimeModeler.processExceptions(RuntimeModeler.java:1006)
at com.sun.xml.ws.model.RuntimeModeler.processRpcMethod(RuntimeModeler.java:969)
at com.sun.xml.ws.model.RuntimeModeler.processMethod(RuntimeModeler.java:546)
at com.sun.xml.ws.model.RuntimeModeler.processClass(RuntimeModeler.java:370)
at com.sun.xml.ws.model.RuntimeModeler.buildRuntimeModel(RuntimeModeler.java:256)
at com.sun.xml.ws.server.EndpointFactory.createSEIModel(EndpointFactory.java:322)
at com.sun.xml.ws.server.EndpointFactory.createEndpoint(EndpointFactory.java:188)
at com.sun.xml.ws.api.server.WSEndpoint.create(WSEndpoint.java:467)
at org.jvnet.jax_ws_commons.spring.SpringService.getObject(SpringService.java:333)
at org.jvnet.jax_ws_commons.spring.SpringService.getObject(SpringService.java:45)
at org.springframework.beans.factory.support.FactoryBeanRegistrySupport$1.run(FactoryBeanRegistrySupport.java:121)
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添加@XmlRootEntity到InvalidInputException不解决问题.
如果这不是报告Web服务故障的推荐方法,那么有更好的方法吗?我的异常是应该继承RuntimeException并依赖于传输进行错误处理(即,所有内容最终都将包含在SOAPException中)?我希望有类似Spring-WS的东西SoapFaultAnnotationExceptionResolver.是否有类似的东西可用于JAX-WS?
我们需要在REST调用期间发生异常时返回自定义错误代码和错误消息.我们已经创建了一个异常映射器提供程序,它适用于应用程序代码中的异常.但是,当从CXF代码发生异常时(例如,形成我编写的CustomValidationInterceptor),它不起作用.
例如,如果我请求无效路径参数(例如无效的phoneNumber).在这种情况下,我们需要返回一个JSON格式的自定义错误代码和错误消息,但即使我们创建以处理WebApplicationException一个例外映射器提供商这是行不通的.
有没有办法处理来自cxf拦截器的异常并返回对用户的响应,如下所示?
{
"errorDetail": {
"errorCode": "404",
"errorMessage": "Bad Request"
}
}
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我的CustomValidationInterceptor的代码片段:
public class CustomValidationInterceptor extends AbstractPhaseInterceptor<Message>{
public CustomValidationInterceptor() {
super(Phase.PRE_INVOKE); // Put this interceptor in this phase
}
public void handleMessage(Message message) {
MetadataMap<String, String> metadataMap = (MetadataMap<String, String>) message.get("jaxrs.template.parameters");
if(null != metadataMap) {
List<String> list = metadataMap.get("phoneNumber");
if(null != list) {
String phoneNumber = list.get(0);
boolean result = validatePhoneNumber(phoneNumber);
if(!result){
throw new TelusServiceException(Response.status(Response.Status.BAD_REQUEST).build(), 400, "phone number not valid");
}
} else {
throw new TelusServiceException(Response.status(Response.Status.BAD_REQUEST).build(), 400, …Run Code Online (Sandbox Code Playgroud) 我有一个流程,在CXF客户端上我安装了拦截器,提供程序和异常映射器。就我而言,我正在通过拦截器捕获来自客户端的不良响应,然后我想中止cxf总线链并引发故障。不幸的是我做不到,因为在任何情况下都只记录从拦截器抛出的异常,但是主要错误(错误的json格式)会传播到异常映射器。我想避免使用异常映射器,但是我不知道怎么做。我正在使用WebClient来实现这样的拦截器:
@Component
public class MyInterceptor extends AbstractPhaseInterceptor<Message> {
public MyInterceptor() {
super(POST_STREAM);
}
@Override
public void handleMessage(Message message) throws Fault {
if (message != null) {
//message.getExchange().setOneWay(true);
//message.getExchange().put(Exception.class, new MyException());
//message.getInterceptorChain().abort();
//message.setContent(Exception.class, new MyException());
//Endpoint ep = message.getExchange().get(Endpoint.class);
//message.getInterceptorChain().abort();
//if (ep.getInFaultObserver() != null) {
// ep.getInFaultObserver().onMessage(message);
//}
//throw new WebApplicationException( new MyException());
//message.setContent(Response.class, response);
throw new Fault(new MyException());
}
}
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我读到我应该实现jaxrs-filter,因为拦截器抛出的异常不会传播到异常映射器。由于WebClient的实现,在Java中有什么方法可以做到吗?
S client = create(url, clazz, list(jsonProvider(), providers));
WebClient.getConfig(client).getInInterceptors().add(new MyInterceptor());
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我也尝试过在拦截器上使用不同的阶段,但是也没有用。